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      <title>Complex Numbers &amp; Operations - 1/4/22 - Per 3 by Kristine Greengrove</title>
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      <language>en-us</language>
      <pubDate>2022-01-03 00:24:12 UTC</pubDate>
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         <title>Application</title>
         <author>kgreengrove1</author>
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         <pubDate>2022-01-03 00:24:12 UTC</pubDate>
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         <title>Practice</title>
         <author>kgreengrove1</author>
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         <description><![CDATA[<div>Write each of the following in the form a + bi<br><br>1. (2 + 5i) - (-6 + i)<br>2. (2i)(6 + 3i) -- Hint: Use Distributive Property<br><br>Solve the equation.<br><br>3. x<sup>2 </sup>+ 16 = 0<br><br></div>]]></description>
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         <pubDate>2022-01-03 00:24:12 UTC</pubDate>
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         <title>Zain Ali</title>
         <author>zain692292</author>
         <link>https://padlet.com/kgreengrove1/h0mmxjd6hhjbpawj/wish/1974418644</link>
         <description><![CDATA[<div>1. (2+5i) - ( -6+i)<br>&nbsp; &nbsp; (2+5i) + (6 -i)<br>&nbsp; &nbsp; &nbsp;(2+6) + ( 5i-i)<br>&nbsp; &nbsp; &nbsp; &nbsp;8 + 4i</div>]]></description>
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         <pubDate>2022-01-04 15:15:40 UTC</pubDate>
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         <title>Zain Ali</title>
         <author>zain692292</author>
         <link>https://padlet.com/kgreengrove1/h0mmxjd6hhjbpawj/wish/1974429151</link>
         <description><![CDATA[<div>2. (2i) (6+3i)<br>&nbsp; &nbsp; &nbsp;12i + 6i<br>&nbsp; &nbsp; &nbsp; &nbsp;18i<br><br>When you multiply 2i and 6i you get 12i^2.   i^2 = -1.  12i + 6i^2 = 12i + 6(-1) = -6 + 12i</div>]]></description>
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         <pubDate>2022-01-04 15:20:01 UTC</pubDate>
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         <title>Zain Ali</title>
         <author>zain692292</author>
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         <description><![CDATA[<div>x^2 + 16 = 0<br>x^2&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 0-16<br>&nbsp;x^2&nbsp; &nbsp; &nbsp; &nbsp; = -16<br>&nbsp;square root on both sides<br>&nbsp; &nbsp; &nbsp; &nbsp;x&nbsp; &nbsp; &nbsp; = +-4&nbsp; &nbsp; &nbsp;-1&nbsp;<br>&nbsp; &nbsp; &nbsp; &nbsp;x&nbsp; &nbsp; &nbsp; &nbsp;= +4i<br>                    -4i</div>]]></description>
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         <pubDate>2022-01-04 15:24:21 UTC</pubDate>
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         <author>richard700669</author>
         <link>https://padlet.com/kgreengrove1/h0mmxjd6hhjbpawj/wish/1974442221</link>
         <description><![CDATA[<div>1. &nbsp; (2+5i)-(-6+i)            <br>&nbsp; &nbsp; &nbsp; ( 2-6)(i-5i)<br>      (4,-4i)</div>]]></description>
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         <pubDate>2022-01-04 15:25:11 UTC</pubDate>
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         <author>richard700669</author>
         <link>https://padlet.com/kgreengrove1/h0mmxjd6hhjbpawj/wish/1974453075</link>
         <description><![CDATA[<div>(2i)(6+3i)<br>(2i+x3i)(6)<br>(6i,6)<br><br>This is a multiplication problem.  Use distributive property to get 12i + 6i^2.   Then substitute -1 for i^2.  12i + 6(-1) = -6 + 12i</div>]]></description>
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         <pubDate>2022-01-04 15:29:25 UTC</pubDate>
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         <author>richard700669</author>
         <link>https://padlet.com/kgreengrove1/h0mmxjd6hhjbpawj/wish/1974474369</link>
         <description><![CDATA[<div>x^2 + 16 =0<br>x ^2 = 0-16<br>x^2=-16<br>x^2= -16<br>x^2 = +- 16 -1<br>x+ =+- 4 -i<br>(4i , -4i)</div>]]></description>
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         <pubDate>2022-01-04 15:37:38 UTC</pubDate>
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         <title>Micah</title>
         <author></author>
         <link>https://padlet.com/kgreengrove1/h0mmxjd6hhjbpawj/wish/1975185934</link>
         <description><![CDATA[<div>1. (2+5i)-(-6+i)<br>8+4i<br><br>2. 2i(-6+3i)=-12i+6i^2<br>-12i+6i^=-12i-6<br>-6-12i<br><br>3. x=4i, -4i<br><br></div>]]></description>
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         <pubDate>2022-01-04 21:42:02 UTC</pubDate>
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