<?xml version="1.0"?>
<rss version="2.0">
   <channel>
      <title>Tutoring by Denbeigh Whitmarsh</title>
      <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow</link>
      <description></description>
      <language>en-us</language>
      <pubDate>2015-11-21 17:12:26 UTC</pubDate>
      <lastBuildDate>2023-03-17 04:05:55 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url></url>
      </image>
      <item>
         <title>Hello!</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82819269</link>
         <description><![CDATA[<p>people besides those i have spoken to personally, please don't alter this padlet! we need it just as it is! thanks!</p><p>denbeigh</p>]]></description>
         <enclosure url="" />
         <pubDate>2015-11-21 17:19:51 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82819269</guid>
      </item>
      <item>
         <title>Fraction to Decimal to Percent</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82819390</link>
         <description><![CDATA[<p>Fraction to Decimal: 1 ie <b>3/4</b></p><p>Decimal to Percent: 2 ie 0.75</p><p>Percent to Fraction: 3 ie 75% or 75,000% </p><p>Percent to decimal: 4 ie 75%=</p><p>Decimal to Fraction: 5 ie 0.7534= 7534/10000</p><p>Fraction to percent: 6 ie 3/4= 0.75</p>]]></description>
         <enclosure url="https://d20uo2axdbh83k.cloudfront.net/151121/84c90969538a4030f1f449e1b8d1970f.jpg" />
         <pubDate>2015-11-21 17:23:21 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82819390</guid>
      </item>
      <item>
         <title>fraction - decimal - percent</title>
         <author></author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82819476</link>
         <description><![CDATA[<br>1: <b>fraction to decimal: </b>divide numerator by denominator <br><br>2: <b>Decimal to percent: </b>multiply by 100<br><br>3:<b>Percent to decimal:</b>divide by 100 <br><div><p>4: <b>Decimal to fraction: </b>write decimal over top of 10^a, where a is the number of digits that follow the decimal point, then simplify</p><div>5:<b>Fraction to percent:</b> divide numerator by denominator, then multiply by 100</div></div><div>6: <b>Percent to fraction:</b> divide by 100, (answer will be a decimal), then write decimal over top of 10^a, where a is the number of digits that follow the decimal point, then simplify</div>]]></description>
         <enclosure url="" />
         <pubDate>2015-11-21 17:25:56 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82819476</guid>
      </item>
      <item>
         <title>Simplifying</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82819696</link>
         <description><![CDATA[<p>108/144</p><p>Look at the factors of each number: find greatest common factor of both numerator and denominator</p><p>(12 in this case)</p><p>divide both the numerator and the denominator by that GCF</p><p>=9/12</p>]]></description>
         <enclosure url="" />
         <pubDate>2015-11-21 17:31:54 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82819696</guid>
      </item>
      <item>
         <title>Adding and Subtracting Fractions</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82820594</link>
         <description><![CDATA[<p>3<b>&amp;</b>1/2 - 3/4</p><p>=7/2 -3/4</p><p>=7x2/2x2 -3/4</p><p>=14/4 - 3/4</p><p>=11/4</p><p><b>Method:</b></p><p>1- convert any mixed fractions to improper fractions (multiply the denominator by the whole number, add <b>product</b> onto numerator)</p><p>2-  convert fractions so that they are both over a common denominator. Remember: what you to the top of a fraction, you must also do to the bottom :)</p><p>3- add or subtract the numerators, write the <b>sum</b>/<b>difference</b> over the denominator </p><p>4- simplify, and/or turn back into mixed fraction if asked in the question </p>]]></description>
         <enclosure url="" />
         <pubDate>2015-11-21 17:52:12 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82820594</guid>
      </item>
      <item>
         <title>Math Terminology</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82820979</link>
         <description><![CDATA[<p><b>Sum</b>- the answer to an addition</p><p><b>Difference</b>- the answer to a subtraction</p><p><b>Product</b>- answer to a multiplication</p><p><b>Quotient</b>- answer to a division</p><p><b>Operation-</b> a multiplication, division, subtraction, addition, etc.</p>]]></description>
         <enclosure url="" />
         <pubDate>2015-11-21 18:02:32 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82820979</guid>
      </item>
      <item>
         <title>Multiplying Fractions</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82821067</link>
         <description><![CDATA[<p>   2/3 x 4&amp;7/18</p><p>=2/3 x 79/18</p><p>=(2)(79) x (3)(18) (cancel out)</p><p>=(1)(79) x (3)(9)</p><p>=79/27</p><p>1)<b> Method:</b></p><p>1-convert any mixed fractions to improper fractions (multiply the denominator by the whole number, add <b>product</b> onto numerator)</p><p>2- Simplify the multiplication by cancelling out terms (terms that have a common factor with another term on the opposite side of the fraction line)</p><p>3- multiply the numerators by each other, and the denominators by each other</p><p>4- simplify if possible </p>]]></description>
         <enclosure url="" />
         <pubDate>2015-11-21 18:04:54 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82821067</guid>
      </item>
      <item>
         <title>Dividing Fractions</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82821476</link>
         <description><![CDATA[<p>4/5 / 3&amp;12/20</p><p>=4/5 / 72/20</p><p>=4/5 x 20/72</p><p>=(4)(20) x (5)(72)</p><p>=(1)(4) x (1)(18)</p><p>=(2) x (9)</p><p>=18</p><p><b>Method:</b></p><p>1- convert any mixed fractions to improper fractions (multiply the denominator by the whole number, add <b>product</b> onto numerator)</p><p>2- flip the second fraction (so that denominator becomes the numerator and vice versa), and multiply<span style="font-size: 13px;"> (see other note)</span></p>]]></description>
         <enclosure url="" />
         <pubDate>2015-11-21 18:15:23 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/82821476</guid>
      </item>
      <item>
         <title>Adding and Subtracting Integers</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87181362</link>
         <description><![CDATA[<p>Remember:</p><p>-two of the same sign together means "add" i.e. (<b>-</b>3)(<b>-</b>5)=(+15)&nbsp;</p><p>or <span style="font-size: 13px; font-style: normal; color: rgb(102, 102, 102);">(-4)<b>-(-</b>3)= (-4)+3= (-1)</span></p><p>-two opposite signs together mean "subtract" i.e. (+5)<b>+(-</b>6)=(-1)</p><p>or (<b>-</b>6/<b>+</b>2)= (<b>-</b>3)</p>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-21 16:34:56 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87181362</guid>
      </item>
      <item>
         <title>Ratios</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87182306</link>
         <description><![CDATA[<p><b>Remember:</b></p><p>-similar to fractions, except to get the number of pieces in your "whole pie", you have to add all the numbers of pieces together i.e. 3:2:1, there are 3+2+1=6 pieces ("parts") total</p><p>-"parts" don't have to be the same, i.e. it could be 3 carrots: 2 radishes: 1 celery stick</p><p><b>Example Question: </b></p><p>The ratio of nitrogen to potassium to phosphorus in a bag of fertilizer is 4:5:2. If there are 33 kg of fertilizer, how much of that is phosphorus?</p><p>-&gt; here, our "whole pie" is the 33kg </p><p>-&gt; the number of "parts" in our pie is 4+5+2=11 parts</p><p>-&gt; we want to know what ONE part is worth, (so we can figure out how much the TWO parts of phosphorus are worth):</p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>33kg/11 parts = 3 kg per part </p></blockquote></blockquote><p>-&gt; now we know that one part is worth 3kg, so 2 parts is worth:</p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>(3kg)(2)=6kg</p></blockquote></blockquote><p>        Therefore, the amount of phosphorus in the bag is 6kg.</p>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-21 16:44:29 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87182306</guid>
      </item>
      <item>
         <title>Cross Multiplying Trick</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87184182</link>
         <description><![CDATA[<p>-&gt; use if you are asked to find the value of something, while maintaining a ratio</p><p>-&gt; note: 30/100 =30% (this is a ratio of 30 to 100)</p><p>-&gt;i.e. if you had 30% of an hour, how many minutes it that?</p><p>-&gt; to solve, let x represent what you're trying to find (here, the number of minutes)</p><p>-&gt; look at whatever number is across from "x" (here, the 100)</p><p>-&gt; take the other two number, and multiply them</p><p>-&gt; divide that answer by 100 (the last number)</p><p>-&gt; that will be the value of x</p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>x= (30)(60) / (100)</p><p>x= 18 </p><p>That means 30% of one hour is 18 min.</p></blockquote>]]></description>
         <enclosure url="https://d20uo2axdbh83k.cloudfront.net/151221/393162f5db7b5f9a4d6041bedc93188f.jpg" />
         <pubDate>2015-12-21 17:05:12 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87184182</guid>
      </item>
      <item>
         <title>Unit Price Questions</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87185264</link>
         <description><![CDATA[<p>-&gt; the unit price is the price of one unit of something</p><p>-&gt; if we had 2.5kg of cereal that is worth $6.30, what is the unit price?</p><p>-&gt;here, the "whole" is the 2.5 kg, and the "parts" is $6.30</p><p>-&gt; to find the price of ONE kg, we divide the 2.5kg by $6.30:</p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>2.5kg/$6.30 = $o.40/kg</p></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>   ^unit price</p><p>If you had $10, how many kg could you buy?</p><p>$10/$0.40 per kg = 25k</p></blockquote></blockquote></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"></blockquote>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-21 17:16:37 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87185264</guid>
      </item>
      <item>
         <title>Exponent Laws</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281325</link>
         <description><![CDATA[<p><b> X^n -&gt; n=exponent</b></p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p><b>X= Base</b></p><p><b>X^n = Power</b></p></blockquote><p><b><br></b></p><p><b>When Bases are the same:</b></p><p><b>Product Law:</b> (X^m)(X^n) = X^(n+m) -&gt; if you have two powers being multiplied, add the exponents</p><p><b>Quotient Law:</b> (X^m) / (X^n) = X^(m - n) -&gt; if you have two powers that are being divided, subtract the exponents</p><p><b>Zero Exponents:</b> X^0 = 1 <span><br></span>-&gt; Anything to an exponent of zero is equal to one (except if the base is zero) </p><p><b>Negative Exponents:</b> X^(-n) = 1/(X^n) -&gt; if you have a negative exponent, to make it positive, use the reciprocal (flip the fraction (if it's a whole number, remember it's an imaginary fraction over 1), and write the base and a positive version of the exponent on the bottom)</p>]]></description>
         <enclosure url="https://d20uo2axdbh83k.cloudfront.net/151223/87a12276738d4233ee8d3be6fa37325f.jpg" />
         <pubDate>2015-12-23 22:21:41 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281325</guid>
      </item>
      <item>
         <title>Reciprocal</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281537</link>
         <description><![CDATA[<p>-&gt; the "opposite" of a number:</p><p>Flip the number so that the numerator is on the bottom, and the denominator is on the top. Remember that if a number doesn't appear to have a denominator, it actually has an imaginary denominator of 1. </p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>ie 3 -&gt; 1/3</p><p>or 3/2 -&gt; 2/3</p></blockquote>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-23 22:39:02 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281537</guid>
      </item>
      <item>
         <title>Distributive Property</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281574</link>
         <description><![CDATA[<p>-&gt; multiply the number(s) outside of the brackets by each number/term inside the brackets </p><p>(3x+2)(3+x)= (3x)(3)+(2)(3)+(3x)(x)+(2)(x)</p><p>                   =9x + 6 +3x^2 + 2x</p><p>                   =3x^2 + 11x +6</p><p>or</p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>3(4x-5) = (3)(4x) + (3)(-5)</p></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>  = (12x) + (-15)</p><p>  = 12x - 15</p></blockquote></blockquote>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-23 22:42:30 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281574</guid>
      </item>
      <item>
         <title>Collecting Like Terms</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281615</link>
         <description><![CDATA[<p>-&gt; add together terms that have the same variable to the same exponent</p><blockquote><p><b>3x^2</b> + 4x^3 <b>+ 5x^2 </b>+7 -3x <b>-7x^2</b> + 4x^3</p><p>= 8x^3 +x^2 -3x +7 </p><p>-&gt; remember that most teachers want you to write the final answer in descending, alphabetical order (descending exponents, NOT coefficients)</p></blockquote>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-23 22:45:45 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281615</guid>
      </item>
      <item>
         <title>Polynomial Terms</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281727</link>
         <description><![CDATA[<p>3X^2</p><p>-&gt; 3 = Numerical Coefficient</p><p>-&gt; X = Variable/ Literal   &nbsp;<span><br></span><span style="font-size: 13px;">           Coefficient</span></p><p><span style="font-size: 13px;">Degree of the expression: 2nd</span><span style="color: rgb(102, 102, 102); font-size: 13px;"><span><br></span></span></p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p><span style="color: rgb(102, 102, 102); font-size: 13px;">(Degree is the number of the highest exponent in the expression)</span></p></blockquote></blockquote><p><span style="font-size: 13px;">-&gt; 3X = term</span></p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p><span style="font-size: 13px;">Remember: terms are </span>usually separated by addition/subtraction</p></blockquote>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-23 22:58:49 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281727</guid>
      </item>
      <item>
         <title>Evaluating</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281785</link>
         <description><![CDATA[<p>-&gt; means solve for an answer, which is (probably) just a number</p><p>-&gt; if there are variables in the expression, the question will probably give you the values of those variables.</p><p><b>Method:</b><span style="font-weight: bold;"><br></span>1) sub in the given number (replace the variable with its number)</p><p>2) solve (follow bedmas)</p><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><p>ie 3x + 2x^2 +1</p><p>Given: x= -3</p><p>Hint: put -3 in brackets when you sub it in!</p><p>= 3(-3) + 2(-3)^2 +1</p><p>= -9 + 2(9) +1</p><p>= -9 + 18 +1</p><p>= 10</p></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"></blockquote></blockquote><blockquote style="margin: 0 0 0 40px; border: none; padding: 0px;"></blockquote>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-23 23:05:57 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281785</guid>
      </item>
      <item>
         <title>Simplifying</title>
         <author>denbeighwhitmar</author>
         <link>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281868</link>
         <description><![CDATA[<p>1) Apply distributive property if necessary</p><p>2) collect like terms</p>]]></description>
         <enclosure url="" />
         <pubDate>2015-12-23 23:16:12 UTC</pubDate>
         <guid>https://padlet.com/denbeighwhitmar/gm7okslt67ow/wish/87281868</guid>
      </item>
   </channel>
</rss>
