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      <title>Surface area of a cylinder. by </title>
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      <language>en-us</language>
      <pubDate>2018-04-30 18:04:43 UTC</pubDate>
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         <title></title>
         <author>lathajoy68</author>
         <link>https://padlet.com/lathajoy68/fh5ayoyxb9y/wish/614667811</link>
         <description><![CDATA[]]></description>
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         <pubDate>2020-06-07 02:10:21 UTC</pubDate>
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         <title>group 2</title>
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         <description><![CDATA[<div>diameter=84cm<br>radius=84/2=42cm<br>length=120cm Csa of a cylinder=2 x 22/7 x 42 x 120=31680cm2<br>area of playground=500 x 31680=15840000cm2=15840000/10000=1584m2<br><br></div>]]></description>
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         <pubDate>2020-06-07 05:45:45 UTC</pubDate>
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         <title>Group 3 answer</title>
         <author>dalvint_oow</author>
         <link>https://padlet.com/lathajoy68/fh5ayoyxb9y/wish/614749317</link>
         <description><![CDATA[<div>H=10m, D=3.5m, R= 35/20<br><br>I) CSA= 2πrh<br>= 2 x 22/7 x 35/20 x 10<br>= 110m2<br><br>II) cost= 40/m2<br>= 40 x 110<br>= 4400 rupees</div>]]></description>
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         <pubDate>2020-06-07 05:46:21 UTC</pubDate>
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         <title>Group 1 (answer)</title>
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         <description><![CDATA[<div>height = 14 <br>csa = 88cm<br>Radius = 4<br>diameter = 2<br>therefore CSA of this cylinder =2πrh<br>which is 88cm</div><div><br></div><div><br><br></div><div> </div>]]></description>
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         <pubDate>2020-06-07 05:47:19 UTC</pubDate>
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         <title>GROUP 1 </title>
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         <link>https://padlet.com/lathajoy68/fh5ayoyxb9y/wish/614750017</link>
         <description><![CDATA[<div>2 x 22/7 x R x 14 : 88<br>44/7 x 14 : 44 x 2 : 88<br>88R : 88<br>R : 1 <br>D : 2 <br>Mohammed Owais Qadri .<br><br></div>]]></description>
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         <pubDate>2020-06-07 05:47:33 UTC</pubDate>
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         <title>group 2 </title>
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         <pubDate>2020-06-07 05:51:34 UTC</pubDate>
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