Class Project Math Mr. Rodinsky by Robert Rodinsky

https://docs.google.com/forms/d/1dsGbWemvYpWV1zQpWTMy6NkxXRiXt0Zijun8ywnsJxc/edit

2020-05-04 16:50:38 UTC

https://drive.google.com/open?id=1auclQFF-L0H5tTFh-qskqlysndMnnDXu

2020-05-04 16:55:37 UTC

Brandon Lum
2 Period Mr. Rodinsky
Marble-slide Challenge #5

I solved this equation by forming lines to influence the object's movements. Most of the lines traveled through the y-axis and had a positive slope.

https://drive.google.com/file/d/1rOhogeGHClPiwYOwVKCmb6IPkot-SCEm/view

909280 — 2020-05-04 17:33:30 UTC

Matthew Yu
1st Period
Challenge #8

To solve this equation, I first had to look at the y-intercept, I looked at where it starts and I determined that the y intercept would be 11. Then, I saw that the stars traveled through a downward slope.

https://drive.google.com/file/d/1s1ebMXBpf7DPWL8fmInQ8ikzRD1Fpahm/view

906829 — 2020-05-04 18:14:20 UTC

John Broussard
6th Period
Challenge #4

First, I did y=-0.5x, because I knew the first line had to have a negative and "slow" slope. Then, I made the y intercept 10, so that it would line up with the ball. Also, I made {x<10}, so that it would cut off and align with the second line. For the second line, I did y=0.5x, because i knew that it would be a positive line with a slope of 0.5. Then, I made the y intercept -2, so that it would align with the stars.

https://drive.google.com/file/d/1GhHmrpWYnaop0aaHHOeVK9U869FkNmTl/view

2020-05-04 18:33:14 UTC

Nestor Munoz
Period 5 Mr.rodinsky

https://drive.google.com/file/d/1a5NvTIKgcaRgrAedkT3YhvNrxUJ1dEf1/view

2020-05-04 18:55:55 UTC

Jacqueline Pan
6th period
Challenge #4

https://drive.google.com/file/d/1YzRx6GYNpNgu5DjiXnvdfg5Vpx3-McEm/view

2020-05-04 19:25:06 UTC

Alyssa Draheim
6th Period
Challenge 8

First I wrote y= 1/2 x because the slope of the line was very flat. When the line appeared, it was facing the wrong direction. To fix it I added a negative sign to the 1/2. This moved the line so it was parallel with the stars. I then moved the line up 10 and pressed launch. The dots hit the first star but did not touch the other ones. To fix it I moved the line up another .5. This time when I hit launch the dots hit all the stars.

https://drive.google.com/file/d/1O_X828HxhbNxrQHDbhND-yD9xU3hLQXw/view

2020-05-04 20:00:29 UTC

Evan Kim
6th period
Challenge 4

https://drive.google.com/file/d/1rmee_4v8vcxeT3Def0JAvNoWoP56usCM/view

2020-05-04 20:03:36 UTC

Leland Le
3rd period
challenge #4

The first thing that I wrote was y= -1 I knew the first line had to be a negative slope to reach the next slope which was a positive slope. I decided on doing -1/2 as the slope and cut the line off so the could land on the next line which does through all of the stars downward.

https://drive.google.com/file/d/1O3BaCO1Vos9KtMB3_o6RM5N1ld58kZ3Q/view

2020-05-04 20:15:44 UTC

Joshua Choe
6th Period
Challenge #4

A negative slope is needed, and thus one was implemented. I played around and found the right slope to bring the line to a rough drop point. I also tested a few y-intercepts to create the optimal slope to drop onto, which was then found to be 10. I then created a condition for the line to stop to thus create a drop point, and that condition was {x<10}. I created a second line as the point for the 🤬 to drop onto, then creating the line for the 🤬 to slide down to accumulate the stars.

https://drive.google.com/file/d/1K7bdg9GJPde_lWU9mMY7xXWB_gPTUAlg/view

2020-05-04 20:31:48 UTC

Sarah Lam
2nd Period
Challenge #2

I began by creating a line with a negative slope that had the y intercept of 15 since that was where the marbles started and adjusted the slope of the line so that the line would be able to reach the stars. I then cut the line short by so the line wouldn't block off the tunnels that led to the stars. Then, I made another line which would guide the marbles which had touched the first 2 stars to the other stars by making the slope negative. I changed the y intercept and cut the line short so the marbles could get the stars.

https://drive.google.com/file/d/1uC1VWS_ilBDMLJ6LU5T98AT1JeSYGKz-/view

906202 — 2020-05-04 20:45:20 UTC

Tyler Chan
5th Period
Challenge#7

https://drive.google.com/file/d/1QFuk9uP4PQpzw6SP9FV-ybfWWvfHswP6/view

2020-05-04 22:48:25 UTC

Cassandra Lee
Period 1
Challenge #6
First I created a line that had a negative slope near the ball, so that it can roll towards the stars. Then I made a line that is a "platform" for the ball to roll in the direction of the stars that are in the straight line. Also, the stars that are in the straight line are on the 6 y-intercept, so then I created a line that is on the 6 y intercept, that way after the ball rolls off the platform, it can hit the stars in one go. Secondly, I made the second red line to help the ball gain power to keep rolling down. Lastly, I made one more line that allowed the ball to get to the last star, which is on the (7,2) point.

https://drive.google.com/file/d/1dPbTQlRhIdliTaBFikGz2sUD7-3TCp10/view

2020-05-05 01:13:52 UTC

Ethan Chu
6th Period
Challenge #6
All lines are going directly through the ball. That way, the ball glitches on both sides of the line, enabling me to make straight paths to each star.

https://drive.google.com/file/d/1reFDwymISMdVrwIfm5fyxbu-t9V-NH6c/view

2020-05-05 17:03:00 UTC

Hannah Mckinnell
6th Period
Challenge #4
First I made the slope y= -1/2x because it had to be negative. Then I made the y-intercept 9 so the ball would be able to drop onto the line and roll down. For the second equation, I made the slope 1/2 so the ball would be able to get all the 🤬, and I made the y-intercept -2 so the ball could drop from the first line to the second.

https://drive.google.com/file/d/16TwQ0Lvpk7p-VcacmjwM-oZAE2IhVoEJ/view?usp=sharing

2020-05-05 23:12:02 UTC

David Huang
5th Period

First I needed a line that has a negative slope. I used y=3/4x+15{x<4} as it went through the ball and would stop at the first line. The second line, y=10/27x+11{x<11} as it would have the second line let it stop at the second box. The ball would roll off so I would use x=12.

https://drive.google.com/open?id=1Sv2aKdNK-QBdFhNZCLmXvaH5yfTBubJr

2020-05-08 23:27:18 UTC

Albert Chavez
5th Period
Challenge #2

https://drive.google.com/file/d/1b4z90BJgWaCf40Dw_dzRXE5CstRvI8G0/view?usp=sharing

2020-05-11 22:57:33 UTC

Amilia Wu
1st Period
Challenge #8

First, without any line, the marbles fall straight down. We need a line so the marbles can collect all the stars. We need just one line, y=-1/2x + 10.5. This makes a ramp with a slope of -1/2 and a y-intercept of 10.5. With this line, the marbles can roll down and collect all 4 stars.

https://drive.google.com/file/d/1LnH40J6y_DSkXulBqA97kepS9PCyR3_O/view

2020-05-12 18:57:02 UTC

Melanie 🤬>3rd Period
Challenge #8

First, I typed y=-1x because I knew the slope was negative because the stars were pointing downwards. The line was too low so I changed it to y=-1/2x. The line was still too low so I added 10. The dots only hit 1 star because the line was still too low. I changed the 10 to 11 making the y-intercept a bit higher. The equation in the end was y=-1/2x + 11.

https://drive.google.com/file/d/1nlPQniMFZb9X5CX9x9nydnCd3bz3bvyl/view

2020-05-13 02:47:17 UTC

Sabrina Guo
Rodinsky 6°
Challenge #5

I made a line , y=2/9x+7 with a domain of 2.5-20, and y=3/7x+2 with a domain of 9+, to guide the balls down. The first line would guide the balls and get the first star, before bouncing off the line x=1.3 to get the star below. The second line would guide the balls that fell from the first line downwards. They'll fall on the line y=-1/3x+8 with a domain of 2.5+ to collect the stars going the other way. Since the first and third lines have the same minimum x value, it leaves a small enough gap that prevents the balls on the second line from overshooting and pushes them in the right direction.

https://drive.google.com/file/d/1FUvSwQDX7bejcSaAES11Ow_mfpm0HRV9/view

2020-05-14 19:14:54 UTC

Manal Faisal
Period 3
Challenge #4

The first thing I did was that I made a line parallel to the stars and to do that I did y=½x because the fraction (which is the slope in the case) is the number that is multiplied on the x. After that the line was too high so I have to subtract 2 from ½x to make it lower. Then I made the line that made the balls fall in a diagonal line to fall onto the first line I made. Since it was going downward this time it was a negative slope and the slope of the line seemed flat like last time so I put -1/2x. After, I put in the y-intercept, which was 10. The two lines were touching so I had to add a delimiter to cut the top line off. So I put in x is less than 10 because when the line stopped at 10 there was enough space for all the balls to come down and then fall onto the bottom line and get all the stars.

https://drive.google.com/file/d/1FCAd3202pWLGqk7KbyRfVhZVExDmsHcP/view

907657 — 2020-05-20 14:06:57 UTC

Caleb Yeung
3rd Period
Challenge #8

We first look at the stars and their formation, a straight line diagonal to the right, meaning the slope would be negative. I first tried y=-1x, but it was too low, and y=-0.5x was perfect. I added 10 to see if it would work, but the y-intercept was too low, so I changed it to 11. The equation that I found to work in the end was y=-0.5x + 11. With a straight line through the stars, with the right slope, all the stars will be captured.

https://drive.google.com/file/d/159SXL1pbl91tzZM9bU9ErlpvQxXX1GtL/view

2020-05-20 20:19:07 UTC

Kaylen La
6th Period
Challenge #8

https://drive.google.com/file/d/1apcPbnndb5vDZz2v-MHUJ6Yop-p1a7SU/view

2020-05-22 00:36:11 UTC

Adrienne Lee
Period 6
Challenge #8

We see that the stars are in a straight line, so all we have to do is put a line directly under all the stars to the ball can collect them all. By looking at the stars, you can see that you need a negative line, so I started with y = -x. Then I saw that the line need to be higher, so tried setting the y intercept to 12, but that was too high, so I changed it to 11. Next, I needed to change the slope to fit under all the stars. I first tested out a slope of 0.5, but that wasn't right. 0.4 was way too flat, and 0.6 was way too steep. So I ended up putting in 0.53 as the slope, which was perfect. In the end, I used the equation y = -0.53x + 11

https://drive.google.com/file/d/1Ln_CajXdXYGkGY2IZ5JSW254bwpYNbl6/view

906409 — 2020-05-23 06:11:32 UTC

Megan Leung
Period 3
Challenge#1
Without any lines, the balls fall straight down, only knocking out two of the stars. We only need two lines. The first equation, y = 1x {x<10} + x, has a slope of 2. This accounts for the leftmost star. The second equation, x = -y { y < 13.0199999} + 23.488999, (Yes, I realize how ridiculous it looks to have this many decimal numbers, but they do serve a purpose.) has a slope of about negative 1. This line should allow some balls through to knock out the two middle stars and allow some through for the right star. The x-intercept for the second line had to be so exact because if the line began at 23.5, the line would interfere with the balls’ natural path down, making them curve around the bottom middle star. Similarly, the line had to end at 13.0199999 because any lower or higher, it also would have interfered with the balls’ natural path down to the stars.