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      <title>HÓA HỌC 8 _ĐỊNH LUẬT BẢO TOÀN KHỐI LƯỢNG by Mai Huong Nguyen</title>
      <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro</link>
      <description>THÍ NGHIỆM</description>
      <language>en-us</language>
      <pubDate>2021-10-29 08:58:53 UTC</pubDate>
      <lastBuildDate>2025-12-03 18:13:56 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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      <item>
         <title>Hà Minh Châu</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895506510</link>
         <description><![CDATA[<div>&nbsp;Theo định luật bảo toàn khối lượng ,ta có</div><div>mBaCl2 + mNa2SO4&nbsp; = mBaSO4<sub><br></sub>&nbsp; + mNaCl</div><div>=&gt;Khối lượng của bari clorua&nbsp; đã phản ứng:</div><div>mBaCl2 = mBaSO4 + mNaCl- mNa2SO4= 23,3 + 11,7 - 14,2 = 20,8 (g)</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 00:50:08 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895506510</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895506511</link>
         <description><![CDATA[<div>Phương trình chữ của phản ứng:</div><div>Natri sunfat + Bari clorua → Bari sunfat + Natri clorua</div><div>Theo định luật bảo toàn khối lượng</div><div>m<sub>BaCl2</sub> + m<sub>Na2SO4</sub> = m<sub>BaSO4</sub> + m<sub>NaCl</sub>&nbsp;</div><div>⇒ m<sub>BaCl2</sub> = m<sub>BaSO4</sub> + m<sub>NaCl</sub> - m<sub>Na2SO4</sub> = 23,3 + 11,7 - 14,2 = 20,8g.</div><div><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 00:50:08 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895506511</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895507476</link>
         <description><![CDATA[<div>Na2SO4 + BaCl2 ==&gt; BaSO4 + 2NaCl</div><div>Theo định luật bảo toàn khối lượng,ta có:</div><div>mNa2SO4 + mBaCl2= mBaSO4 + mNaCl</div><div>⇔ mBaCl2= (mBaSO4 + mNaCl) - mNa2SO4<br>= (23,3+11,7)-14,2<br>= 20,8 (g)<br>Đức</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 00:50:35 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895507476</guid>
      </item>
      <item>
         <title>Ngọc Linh </title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895507882</link>
         <description><![CDATA[<div>mBari clorua+mNatri sufat---&gt;mBari sunfat+mNatri clorua<br>=&gt; mBari clorua=(mBarisunfat+mNatri clorua)-mNatri sunfat<br>mBari clorua=(23,3+11,7)-14,2<br>mBari clorua=20,8(g)</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 00:50:46 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895507882</guid>
      </item>
      <item>
         <title>Thanh Sơn</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895508357</link>
         <description><![CDATA[<div>Phương trình chữ:<br>Natri sunfat + Bari clorua -&gt; Bari sunfat + Natri clorua<br>Định luật bảo toàn khối lượng:<br><br></div><div>m<sub>BaCl2</sub> + m<sub>Na2SO4</sub> = m<sub>BaSO4</sub> + m<sub>NaCl</sub>&nbsp;<br><br></div><div>-&gt; m<sub>BaCl2</sub> = m<sub>BaSO4</sub> + m<sub>NaCl</sub> - m<sub>Na2SO4</sub>&nbsp;<br>=23,3 + 11,7 - 14,2 = 20,8g.<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 00:51:00 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895508357</guid>
      </item>
      <item>
         <title>Quốc Khánh</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895508518</link>
         <description><![CDATA[<div>Phương trình chữ của phản ứng:<br>Natri sunfat + Bari clorua -&gt; Bari sunfat + Natri clorua<br>Theo định luật bảo toàn khối lượng<br>mBaCl2 + mNa2SO4 = mBaSO4 + mNaCl&nbsp;<br>--&gt; mBaCl2 = mBaSO4 + mNaCl - mNa2SO4 = 23,3 + 11,7 - 14,2 = 20,8g.<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 00:51:04 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895508518</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895508677</link>
         <description><![CDATA[<div>Ta có phản ứng hoá học:<br>Bari clorua + Natri sunfat —&gt; Bari sunfat + Natri clorua<br>Theo định luật bảo toàn khối lượng ta có<br>   &nbsp;mBari clorua +mNatri sunfat = mBari sunfat + mNatri clorua<br>&nbsp; &nbsp; mBari clorua + 14,2=23,3 + 11,7<br>&nbsp; &nbsp; &nbsp;mBari clorua = 23,3 + 11,7 -14,2<br>&nbsp; &nbsp; &nbsp;mBari clorua = 20,8g&nbsp;<br>Việt Anh</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 00:51:09 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895508677</guid>
      </item>
      <item>
         <title>tohathanh</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895531026</link>
         <description><![CDATA[<div><strong>a)</strong> mMg + mO2 = mMgo.<br><br></div><div><strong>b)</strong> mQ2= mMgO – mMg= 15 - 9 = 6(g).<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:00:58 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895531026</guid>
      </item>
      <item>
         <title>Kim Chi</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895532327</link>
         <description><![CDATA[<div>a) m Mg + m O2= m MgO<br>b)m Mg + m O2= m MgO<br>m O2=m MgO -m Mg<br>m O2= 15-9<br>m O2=6(g)</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:01:34 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895532327</guid>
      </item>
      <item>
         <title>Hà Minh Châu</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895533364</link>
         <description><![CDATA[<div>Magie cháy là xảy ra phản ứng với khí O2 trong không khí tạo ra magie oxit MgO</div><div>a) Công thức khối lượng của phản ứng:</div><div>Mg&nbsp; + O2 &nbsp; = MgO</div><div>b) Khối lượng của khí oxi đã phản ứng là:</div><div>O2 &nbsp; = Mgo– Mg =&nbsp; 15 – 9 = 6(g)</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:02:02 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895533364</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895537693</link>
         <description><![CDATA[<div>a)Công thức về khối lượng của phản ứng xảy ra :<br>&nbsp; &nbsp;mMg +mO2 =mMgO<br>b)Khối lượng của oxi :<br>&nbsp; &nbsp;mO2 = mMgO-mMg<br>&nbsp; &nbsp;mO2 = 15 - 9<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; =6g<br>Việt Anh</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:04:04 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895537693</guid>
      </item>
      <item>
         <title>Minh Anh</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895542913</link>
         <description><![CDATA[<div>3.D 16,5 </div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:24 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895542913</guid>
      </item>
      <item>
         <title>Quốc Khánh</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543220</link>
         <description><![CDATA[<div>Đáp án d<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:32 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543220</guid>
      </item>
      <item>
         <title>Kim Chi</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543264</link>
         <description><![CDATA[<div>D</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:34 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543264</guid>
      </item>
      <item>
         <title>Quang</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543474</link>
         <description><![CDATA[<div>D,16,5g</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:39 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543474</guid>
      </item>
      <item>
         <title>Huy</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543491</link>
         <description><![CDATA[<div>D</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:39 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543491</guid>
      </item>
      <item>
         <title>Vân Hà</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543541</link>
         <description><![CDATA[<div>3. D</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:41 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543541</guid>
      </item>
      <item>
         <title>tohathanh</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543566</link>
         <description><![CDATA[<div>câu 3<br>D 16,5kg<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:42 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543566</guid>
      </item>
      <item>
         <title>Tường Vy</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543995</link>
         <description><![CDATA[<div>D. 16,5g</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:48 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895543995</guid>
      </item>
      <item>
         <title>Ngọc Linh </title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895544197</link>
         <description><![CDATA[<div>D. 16,5g</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:54 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895544197</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895544340</link>
         <description><![CDATA[<div>D&nbsp;<br>Việt Anh</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:06:58 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895544340</guid>
      </item>
      <item>
         <title>Huyền Anh</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895544545</link>
         <description><![CDATA[D]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:07:04 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895544545</guid>
      </item>
      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895557917</link>
         <description><![CDATA[<div>a)Theo định luật bảo toàn khối lượng ta có:<br>&nbsp; &nbsp; mCaCO3=mCaO+mCacbonic<br>&nbsp; &nbsp; 5=2,8 + mCacbonic<br>&nbsp; &nbsp; mCacbonic=5 - 2,8<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;=2,2 tấn<br>b)gây ô nhiễm môi trường<br>Việt Anh</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:13:11 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895557917</guid>
      </item>
      <item>
         <title>Minh Anh</title>
         <author></author>
         <link>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895560252</link>
         <description><![CDATA[<div>a) Canxi cacbonat = canxi oxit + khí cacbonic<br>BTKL: mCanxi cacbonat = mCanxi oxit +m khí Cacbonic<br>thay số :5 = 2,8 + m khí cacbonic&nbsp;<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 5-2,8 = m khí cacbonic<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2,2 = m khí cacbonic<br>b)Lò nung vôi thủ công tạo ra nhiều khí CO2 gây ô nhiễm không khí<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-11-17 01:14:08 UTC</pubDate>
         <guid>https://padlet.com/maihuongsphoa/es68wyw7zai56oro/wish/1895560252</guid>
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