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      <title>Exploration #2_Factorizing by jinseop lee</title>
      <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp</link>
      <description>G10 MYP5 Maths_Quadratics</description>
      <language>en-us</language>
      <pubDate>2017-09-03 09:13:24 UTC</pubDate>
      <lastBuildDate>2026-01-03 19:16:57 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title>Worksheet</title>
         <author>jinseopleekcis</author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184393848</link>
         <description><![CDATA[<div>Download the following Worksheet</div>]]></description>
         <enclosure url="https://padletuploads.blob.core.windows.net/prod/217904286/f42c0a7471888bc14f5134c10e4c5b82/Informal_Formative_Exploration_Task__1_Expanding_Binomial.pdf" />
         <pubDate>2017-09-03 09:15:17 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184393848</guid>
      </item>
      <item>
         <title>Questions to Answer</title>
         <author>jinseopleekcis</author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184394147</link>
         <description><![CDATA[<div>Please answer the question and share your answer for #4 and #5 here.</div>]]></description>
         <enclosure url="" />
         <pubDate>2017-09-03 09:24:13 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184394147</guid>
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      <item>
         <title>wxxxxx</title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184447759</link>
         <description><![CDATA[<div>4# （x+1)(x+7)=x^2+8x+7<br>(x-3)(x+8)=x^+5x-24<br>(x-1)(x-2)=x^2-3x+2<br>(x+5)(x-5)=x^-25<br>5#(x+p)(x+q)=x^2+(p+q)x+p*q</div>]]></description>
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         <pubDate>2017-09-04 00:39:14 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184447759</guid>
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         <title></title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184447798</link>
         <description><![CDATA[<div>#4&nbsp;<br>(x+1)(x+7) =x^2+8x+7<br>(x-3)(x+8) =x^2+5x<br>(x-1)(x-2) =x^2-3x+2<br>(x-5)+(x+5)=x^2-25<br>#5<br>(x+p)(x+q) = x^2 +(p+q)x+pq</div>]]></description>
         <enclosure url="" />
         <pubDate>2017-09-04 00:39:52 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184447798</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184447825</link>
         <description><![CDATA[<div>4. predictions: p+q=b, pq=c, a=1.<br>(x+1)(x+7)=x<sup>2</sup>+8x+7<br>(x-3)(x+8)=x<sup>2</sup>+5x-24<br>(x-1)(x-2)=x<sup>2</sup>-3x+2<br>(x+5)(x-5)=x<sup>2</sup>-25<br>5. In (x+p)(x+q)=ax<sup>2</sup>+bx+c, a=1, b=p+q, and c=pq.</div>]]></description>
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         <pubDate>2017-09-04 00:40:18 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184447825</guid>
      </item>
      <item>
         <title>Na</title>
         <author>alansun2002</author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448317</link>
         <description><![CDATA[<div>#4<br>(x+1)(x+7)=x2+8x+7<br>(x-3)(x+8)=x2+5x-24<br>(x-1)(x-2)=x2-3x+2<br>(x+5)(x-5)-x2-25<br><br>#5 (b=p+q,, c+pq)<br> (x+p)(x+q)=ax2+(p+q)x+pq</div>]]></description>
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         <pubDate>2017-09-04 00:46:29 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448317</guid>
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      <item>
         <title></title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448340</link>
         <description><![CDATA[<div>4. (x+4)(x-7)=x^2-3x-28<br>(x-4)(x+7)=x^2+3x-28<br><br>5. (x+p)(x+q)=x^2+(p+q)x+pq</div>]]></description>
         <enclosure url="" />
         <pubDate>2017-09-04 00:46:44 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448340</guid>
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      <item>
         <title></title>
         <author>lynnexiang124</author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448532</link>
         <description><![CDATA[<div>4. (x+1)(x+2)=x^2+3x+2<br>(x-1)(x-2)=x^2-3x+2<br>(x+1)(x-2)=x^2-x-2<br>(x-1)(x+2)=x^2+x-2<br>5.(x+p)(x+q)=x^2+(p+q)x+pq</div>]]></description>
         <enclosure url="" />
         <pubDate>2017-09-04 00:49:02 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448532</guid>
      </item>
      <item>
         <title>QUESTION 4</title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448549</link>
         <description><![CDATA[<div>(x+5)(x+6)=x^2+11x+30<br>5+6=11 5*6=30</div>]]></description>
         <enclosure url="" />
         <pubDate>2017-09-04 00:49:20 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448549</guid>
      </item>
      <item>
         <title>#</title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448571</link>
         <description><![CDATA[<div>（x+1）（x+7）=x ² +8x+7<br>(x-3)(x+8)=x ² +5x-24<br>(x-1)(x-2)=x ² -3x+2<br>(x+5)(x-5)=x ² -25<br><br>#5<br>(x+p)(x+q)=x ²&nbsp;+（p+q）x+pq</div>]]></description>
         <enclosure url="" />
         <pubDate>2017-09-04 00:49:34 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448571</guid>
      </item>
      <item>
         <title>Q4&amp;5</title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448611</link>
         <description><![CDATA[<div>&nbsp; #4 (x+1)(x+7)=x^2+7x+x+7=x^2+8x+7<br>p=1 q=7 b=p+q=8 c=p*q=7<br>ax^2+bx+c=x^2+8x+7<br><br>#5&nbsp;<br>（x+p)(x+q)=ax^2+bx+c=ax^2+(p+q)x+(p*q)</div>]]></description>
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         <pubDate>2017-09-04 00:50:02 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448611</guid>
      </item>
      <item>
         <title>#4&amp;5</title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448634</link>
         <description><![CDATA[<div>(x+1)(x+7)=x^2+8x+7<br>(x-3)(x+8)=x^2+5x-24<br>(x-1)(x-2)=x^2-3x+2<br>(x+5)(x-5)=x^2-25<br><br>p+q=b pxq=c</div>]]></description>
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         <pubDate>2017-09-04 00:50:18 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448634</guid>
      </item>
      <item>
         <title>QUESTION 5</title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448716</link>
         <description><![CDATA[<div>(x+p)(x+q)=ax^2+(p+q)x+pq</div>]]></description>
         <enclosure url="" />
         <pubDate>2017-09-04 00:51:20 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448716</guid>
      </item>
      <item>
         <title>12345</title>
         <author>08436frand</author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448806</link>
         <description><![CDATA[<div>&nbsp;</div><div>When the factorized expression at the form of (x+p)(x+q)<figure class="attachment attachment--preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:21,&quot;url&quot;:&quot;null&quot;,&quot;width&quot;:91}" data-trix-content-type="image"><img src="null" width="91" height="21"><figcaption class="attachment__caption"></figcaption></figure>&nbsp;</div><div>, its standard expression is <figure class="attachment attachment--preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:21,&quot;url&quot;:&quot;null&quot;,&quot;width&quot;:116}" data-trix-content-type="image"><img src="null" width="116" height="21"><figcaption class="attachment__caption"></figcaption></figure>x^2+(p+q)x+pq<figure class="attachment attachment--preview" data-trix-attachment="{&quot;contentType&quot;:&quot;image&quot;,&quot;height&quot;:21,&quot;url&quot;:&quot;null&quot;,&quot;width&quot;:352}" data-trix-content-type="image"><img src="null" width="352" height="21"><figcaption class="attachment__caption"></figcaption></figure></div>]]></description>
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         <pubDate>2017-09-04 00:52:29 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448806</guid>
      </item>
      <item>
         <title>4&amp;5</title>
         <author></author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448852</link>
         <description><![CDATA[<div>(x+1)(x+7)=x^2+8x+7<br>(x-3)(x+8)=x^2+5x-24<br>(x-1)(x-2)=x^2-3x+2<br>(x+5)(x-5)=x^2+25<br>(x+p)(x+q)=x^2+(p+q)x+pq</div>]]></description>
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         <pubDate>2017-09-04 00:52:56 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184448852</guid>
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      <item>
         <title>4.(x+1)(x+7)=x2+8x+7</title>
         <author>yifan0206_shao</author>
         <link>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184449274</link>
         <description><![CDATA[<div>(x-3)(x+8)=x2+5x-24<br>(x-1)(x-2)=x2-3x+2<br>(x+5)(x-5)=x2-25<br>5. a=1 p+q=b pq=c</div>]]></description>
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         <pubDate>2017-09-04 00:59:02 UTC</pubDate>
         <guid>https://padlet.com/jinseopleekcis/dg2uug1nxavp/wish/184449274</guid>
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