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      <title>TEAM HÓA 9 by NT Kim Loan</title>
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      <description>2021-2022</description>
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      <pubDate>2021-10-17 08:04:23 UTC</pubDate>
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         <author>nguyenthikimloan2590</author>
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         <pubDate>2022-01-16 11:46:05 UTC</pubDate>
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         <title>Quyên </title>
         <author>nguyenthikimloan2590</author>
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         <pubDate>2022-01-16 11:52:58 UTC</pubDate>
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      <item>
         <title>Nhi </title>
         <author>nguyenthikimloan2590</author>
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         <pubDate>2022-01-16 11:53:29 UTC</pubDate>
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      <item>
         <title>Thuận </title>
         <author>nguyenthikimloan2590</author>
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         <pubDate>2022-01-16 11:53:52 UTC</pubDate>
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      <item>
         <title>Quân </title>
         <author>nguyenthikimloan2590</author>
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         <pubDate>2022-01-16 11:55:03 UTC</pubDate>
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         <title>Quỳnh Anh</title>
         <author>nguyenthikimloan2590</author>
         <link>https://padlet.com/nguyenthikimloan2590/dfvz4l3itn84lt4/wish/1994172143</link>
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         <pubDate>2022-01-16 11:55:29 UTC</pubDate>
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         <link>https://padlet.com/nguyenthikimloan2590/dfvz4l3itn84lt4/wish/1994172903</link>
         <description><![CDATA[<div><a href="https://cunghocvui.com/chat-hoa-hoc/Fe"><strong>Fe</strong></a>&nbsp; <strong>+</strong> <a href="https://cunghocvui.com/chat-hoa-hoc/HCl"><strong>2HCl</strong></a> ⟶ <a href="https://cunghocvui.com/chat-hoa-hoc/FeCl2"><strong>FeCl</strong><strong><sub>2</sub></strong></a> <strong>+</strong> <a href="https://cunghocvui.com/chat-hoa-hoc/H2"><strong>H</strong><strong><sub>2</sub></strong></a><strong><sub><br></sub></strong>Fe + <strong>2</strong>AgNO<sub>3</sub> → Fe(NO<sub>3</sub>)<sub>2</sub> + <strong>2</strong>Ag<br><a href="https://cunghocvui.com/chat-hoa-hoc/Cl2"><strong>3Cl</strong><strong><sub>2</sub></strong></a>  <strong>+</strong> <a href="https://cunghocvui.com/chat-hoa-hoc/Fe"><strong>2Fe</strong></a>  ⟶  <a href="https://cunghocvui.com/chat-hoa-hoc/FeCl3"><strong>2FeCl</strong><strong><sub>3</sub></strong></a></div>]]></description>
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         <pubDate>2022-01-16 11:56:46 UTC</pubDate>
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         <title>FeCl3+ 3NaOH-&gt; Fe(OH)3+3NaCl </title>
         <author>vongocthaonhi0602</author>
         <link>https://padlet.com/nguyenthikimloan2590/dfvz4l3itn84lt4/wish/1994173105</link>
         <description><![CDATA[]]></description>
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         <pubDate>2022-01-16 11:57:04 UTC</pubDate>
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         <title></title>
         <author>dominhquan372</author>
         <link>https://padlet.com/nguyenthikimloan2590/dfvz4l3itn84lt4/wish/1994173883</link>
         <description><![CDATA[<div>Cu + 2H2SO4(đặc nóng) --&gt; CuSO4 + 2H2O + SO2</div>]]></description>
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         <pubDate>2022-01-16 11:58:09 UTC</pubDate>
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         <author>lequynhanh317</author>
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         <pubDate>2022-01-16 11:58:27 UTC</pubDate>
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         <description><![CDATA[<div>25 - Thuận&nbsp;<br>26 - Quyên&nbsp;<br>27 - Vy&nbsp;<br>28 - Nhi&nbsp;<br>29 - Quỳnh Anh<br>30 - Quân</div>]]></description>
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         <pubDate>2022-01-16 12:01:13 UTC</pubDate>
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         <author>lequynhanh317</author>
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         <pubDate>2022-01-16 12:05:09 UTC</pubDate>
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         <link>https://padlet.com/nguyenthikimloan2590/dfvz4l3itn84lt4/wish/1994178670</link>
         <description><![CDATA[<div>Câu 28)</div>]]></description>
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         <author>dinhthanhvy2007</author>
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         <pubDate>2022-01-16 12:06:20 UTC</pubDate>
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         <description><![CDATA[<div>Câu 25</div>]]></description>
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         <pubDate>2022-01-16 12:08:59 UTC</pubDate>
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         <description><![CDATA[<div>FeCl3 + 3NaOH -&gt; Fe(OH)3 + 3NaCl<br><br></div><div>0,05&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 0,15<br><br></div><div>nFeCl3= 0,1.0,5= 0,05 mol<br><br></div><div>CMNaOH= 0,15/0,5= 0,3M<br><br></div>]]></description>
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         <pubDate>2022-01-16 12:10:42 UTC</pubDate>
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         <title></title>
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         <description><![CDATA[<div>/ Cho biết:Cu = 64; Al= 27; H = 1; Cl = 35,5. Cho 40 g hỗn hợp 2 kim loại Cu và Al vào dung dịch HCl dư, người ta thu được 3,7185 lít khí sinh ra (đkc). Phần trăm khối lượng của Al và Cu lần lượt có trong hỗn hợp ban đầu là:’<br><br></div><div>&nbsp;</div><div>2AL+6HCL= 2ALCL3+&nbsp; 3H2</div><div>2&nbsp; &nbsp; 6&nbsp; &nbsp; &nbsp;2&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3</div><div>0,1 &nbsp; 0,3 &nbsp; 0,1&nbsp; &nbsp; &nbsp; &nbsp;0,15</div><div>n=Vkhí /24,79=3,7185/24,79=0,15</div><div>m = n.M=0,1.27=2.7</div><div>%m=m/mhh.100%=2.7/40 .100%=6,75%</div><div>100%-6,75%=93,25%/ Cho biết:Cu = 64; Al= 27; H = 1; Cl = 35,5. Cho 40 g hỗn hợp 2 kim loại Cu và Al vào dung dịch HCl dư, người ta thu được 3,7185 lít khí sinh ra (đkc). Phần trăm khối lượng của Al và Cu lần lượt có trong hỗn hợp ban đầu là:’</div><div>&nbsp;</div><div>2AL+6HCL= 2ALCL3+&nbsp; 3H2</div><div>2&nbsp; &nbsp; 6&nbsp; &nbsp; &nbsp;2&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3</div><div>0,1 &nbsp; 0,3 &nbsp; 0,1&nbsp; &nbsp; &nbsp; &nbsp;0,15</div><div>n=Vkhí /24,79=3,7185/24,79=0,15</div><div>m = n.M=0,1.27=2.7</div><div>%m=m/mhh.100%=2.7/40 .100%=6,75%</div><div>100%-6,75%=93,25%</div>]]></description>
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         <pubDate>2022-01-16 12:16:46 UTC</pubDate>
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         <author>lequynhanh317</author>
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         <pubDate>2022-01-23 11:59:01 UTC</pubDate>
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         <title>mdd = V dd . d </title>
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         <description><![CDATA[<div>d = ... g/ml&nbsp;<br>Vdd (ml)</div>]]></description>
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         <pubDate>2022-01-23 12:10:39 UTC</pubDate>
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         <pubDate>2022-01-23 12:11:22 UTC</pubDate>
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         <description><![CDATA[<div>bài của duy do</div>]]></description>
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         <pubDate>2022-01-23 13:31:59 UTC</pubDate>
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         <pubDate>2022-01-23 13:32:14 UTC</pubDate>
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