이차함수의 뜻과 함숫값(3학년) by 박현정

학번 이름

hyeonjeong1976 — 2025-06-03 23:55:47 UTC

1) 이차함수 1개 만들기

2) 함숫값 구하기

3) 121쪽 찍어서 올리기

30205 김호균

2025-06-04 00:40:27 UTC

30215 정민재

2025-06-04 00:41:40 UTC

y=x²+2x+14

1= 5

2= 20

3= 5

오윤우

2025-06-04 00:41:52 UTC

3(x^2-1)

30202 김설

haseongs230020 — 2025-06-04 00:42:12 UTC

1)이차함수 만들기

[y=2x^+12]

2)함숫값 만들기

-f(3)=30

-f(-2)=20

-f(1)=14

30211 이다정

haseongs230028 — 2025-06-04 00:42:25 UTC

y=x+x(1-x)

→ y=2x-x^2

2025-06-04 00:43:51 UTC

30212

haseongs230012 — 2025-06-04 00:44:32 UTC

1.y=x²

5,20, 5

30201 김나준

2025-06-04 00:44:40 UTC

f(x)= x^2-5x+2

1.f(3)=5

2.f(-2)=20

3.f(1)=5

30206민재영

2025-06-04 00:45:03 UTC

1) 이차함수 1개 만들기

y=x 2+2x+1

2) 함숫값 구하기

3) 121쪽 찍어서 올리기

30218 홍준엽

2025-06-04 00:45:04 UTC

1)y=x²

2)1=-5,2=20,3=5

30204 김하율

2025-06-04 00:45:07 UTC

y=3x²+6x+9
f(x)=x²-4x+8
f(3)=(3)²-4(3)+8=5
f(-2)=(-2)²-4(-2)+8=20
f(1)=(1)²-4(1)+8=5

30209-윤규빈

2025-06-04 00:45:10 UTC

1)y=3x(2-x)

1)9

2)-6

3)3

2025-06-04 00:45:31 UTC

30207 염예진

haseongs230007 — 2025-06-04 00:45:51 UTC

y=x^
5 20 5

30217 한찬비

2025-06-04 00:46:21 UTC

Y=x^

30102 김병도

2025-06-05 05:07:56 UTC

y=x^2-4x+7

f(1)=5

f(2)=3

30114정승현

2025-06-05 05:09:01 UTC

30101 김규리

2025-06-05 05:09:41 UTC

30106봉정훈

2025-06-05 05:09:46 UTC

30116천서진

2025-06-05 05:10:25 UTC

y=3x^2-2x+1

30112 이승원

2025-06-05 05:10:39 UTC

y=x^

30117-최정현

haseongs230017 — 2025-06-05 05:10:51 UTC

y=2(x−1)^2+3

y=2x^2−4x+5

30109ㅇㅊㅁ

2025-06-05 05:11:36 UTC

1.f(x)=x^2−4x+3

2.f(1)=4

f(2)=3

30105 백이다

2025-06-05 05:12:07 UTC

f(x)=3(x^2-2x+1)

f(1)=3{(1)^2-2(1)+1}=0

f(0)=3{(0)^2-2(0)+1}=3

f(2)=3{(2)^2-2(2)+1}=9

30111 이소율

haseongs230029 — 2025-06-05 05:12:15 UTC

1.이차함수 만들기

y=x^+21

f(1)=4

f(2)=3

30107안재희

haseongs230006 — 2025-06-05 05:12:31 UTC

30118 한석현

2025-06-05 05:12:43 UTC

y=x+x(2-2x)+2

y=-2x^2+3x+2 (3) f(1)=4 f(2)=3

30115정우창

haseongs230032 — 2025-06-05 05:12:55 UTC

y=3x^2-10x+3

x=1/3 or x=3

30119 황태준

2025-06-05 05:14:47 UTC

30113이승은

haseongs230013 — 2025-06-05 05:15:19 UTC

2.y=2x^2+2x=15

3.f(1)=4

f(2)=3

30104박한진

2025-06-05 05:15:23 UTC

1.y = -2x^2+ 4x + 1

y=x^2-4x+7

f(2)

30108 엄지우

2025-06-05 05:15:36 UTC

.y=x^3-x^2(x+3)

..f(1)=4

...f(2)=3

30103 박아령

haseongs230004 — 2025-06-05 05:17:12 UTC

y=2x^2+7

f(1)=4, f(2)=3