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      <title>Chapter 5 by Phong Yung Liang (Student)</title>
      <link>https://padlet.com/y102023001/d6au9eqmcmcseatb</link>
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      <pubDate>2024-04-24 00:12:03 UTC</pubDate>
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         <title>Chapter 5: Chemical Formulae and Equation</title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967120777</link>
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         <pubDate>2024-04-24 00:13:29 UTC</pubDate>
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         <title>5.1 Chemical Formulae</title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967126939</link>
         <description><![CDATA[<p>What is molecular formula &amp; empirical formula?</p><ul><li><p>The&nbsp;<strong>molecular</strong>&nbsp;<strong>formula</strong>&nbsp;is the formula that shows the&nbsp;<strong>number&nbsp;</strong>and&nbsp;<strong>type&nbsp;</strong>of each atom in a molecule</p><ul><li><p>E.g. the molecular formula of ethanoic acid is C<sub>2</sub>H<sub>4</sub>O<sub>2</sub></p></li></ul><p><br></p></li><li><p>The&nbsp;<strong>empirical</strong>&nbsp;<strong>formula</strong>&nbsp;is the simplest whole number ratio of the atoms of each element present in one molecule or formula unit of the compound</p><ul><li><p>E.g. the empirical formula of ethanoic acid is CH<sub>2</sub>O</p></li></ul><p><br></p></li><li><p><strong>Organic molecules&nbsp;</strong>often have&nbsp;<strong>different</strong>&nbsp;empirical and molecular formulae</p></li><li><p>The formula of an<strong>&nbsp;ionic</strong>&nbsp;<strong>compound&nbsp;</strong>is always an<strong>&nbsp;empirical formula</strong></p></li></ul>]]></description>
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         <pubDate>2024-04-24 00:18:35 UTC</pubDate>
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         <title>Calculate Empirical &amp; Molecular Formulae</title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967131665</link>
         <description><![CDATA[<p><strong>Empirical formula: </strong>gives the <strong>simplest whole number ratio</strong> of atoms of each element in the compound</p><ul><li><p>It is calculated from knowledge of the ratio of masses of each element in the compound</p></li></ul><p><br></p><p><strong>Example: </strong>A compound that contains 10 g of hydrogen and 80 g of oxygen has an empirical formula of H<sub>2</sub>O. This can be shown by the following calculations:<br><br>Amount of hydrogen atoms = mass in grams ÷ A<sub>r</sub> of hydrogen = (10 ÷ 1) = <strong>10 moles<br></strong>Amount of oxygen atoms = mass in grams ÷ A<sub>r</sub> of oxygen = (80 ÷ 16) = <strong>5 moles</strong></p>]]></description>
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         <pubDate>2024-04-24 00:21:53 UTC</pubDate>
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         <title>Example</title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967133433</link>
         <description><![CDATA[<p>Since equal numbers of moles of atoms contain the same number of atoms, the ratio of hydrogen atoms to oxygen atoms is 2:1. Hence the <strong>empirical formula</strong> is H<sub>2</sub>O<br><strong>Molecular formula: </strong>gives the exact numbers of atoms of each element present in the formula of the compound</p><ul><li><p>Divide the relative formula mass of the molecular formula by the relative formula mass of the empirical formula</p></li><li><p>Multiply the number of each element present in the empirical formula by this number to find the molecular formula</p></li></ul>]]></description>
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         <pubDate>2024-04-24 00:23:08 UTC</pubDate>
         <guid>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967133433</guid>
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         <title></title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967134864</link>
         <description><![CDATA[]]></description>
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         <pubDate>2024-04-24 00:24:11 UTC</pubDate>
         <guid>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967134864</guid>
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         <title>5.2 Chemical Equations</title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967140580</link>
         <description><![CDATA[<p><strong>Writing Equations</strong></p><p><br></p><p><strong>Nothing created - nothing destroyed</strong></p><ul><li><p>New substances are made during chemical reactions</p><ul><li><p>However, the same atoms are always present before and after reaction</p></li><li><p>They have just joined up in different ways</p></li><li><p>Atoms cannot be created or destroyed, so if they exist in the reactants then they absolutely must be in the products!</p></li></ul></li><li><p>Because of this the total mass of reactants is always equal to the total mass of products</p></li><li><p>This idea is known as the <strong>Law of Conservation of Mass</strong></p></li></ul><p><br></p><p><strong>Conservation of Mass</strong></p><ul><li><p>The<strong> Law of Conservation of Mass</strong> enables us to balance chemical equations, since no atoms can be lost or created</p></li><li><p>You should be able to:</p><ul><li><p>Write word equations for reactions outlined in these notes</p></li><li><p>Write formulae and balanced chemical equations for the reactions in these notes</p></li></ul></li></ul>]]></description>
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         <pubDate>2024-04-24 00:27:58 UTC</pubDate>
         <guid>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967140580</guid>
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         <title>Word Equations</title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967144292</link>
         <description><![CDATA[<p><br/></p><ul><li><p>These show the&nbsp;<strong>reactants</strong>&nbsp;and&nbsp;<strong>products</strong>&nbsp;of a chemical reaction using their full chemical names</p></li><li><p>The reactants are those substances on the&nbsp;<strong>left-hand side&nbsp;</strong>of the arrow and can be thought of as the chemical<strong>&nbsp;ingredients&nbsp;</strong>of the reaction</p></li><li><p>They react with each other and form new substances</p></li><li><p>The products are the new substances which are on the&nbsp;<strong>right-hand side</strong>&nbsp;of the arrow</p></li><li><p>The arrow (which is spoken as “<em>goes to</em>” or “<em>produces</em>”) implies the&nbsp;<strong>conversion</strong>&nbsp;of reactants into products</p></li><li><p>Reaction&nbsp;<strong>conditions</strong>&nbsp;or the name of a&nbsp;<strong>catalyst</strong> (a substance added to make a reaction go faster) can be written above the arrow</p></li><li><p>An example is the reaction of sodium hydroxide (a base) and hydrochloric acid produces sodium chloride (common table salt) and water:</p></li></ul><p><br/></p><p><strong>               sodium hydroxide + hydrochloric acid ⟶ sodium chloride + water</strong></p>]]></description>
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         <pubDate>2024-04-24 00:30:21 UTC</pubDate>
         <guid>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967144292</guid>
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         <title>Representing reactions as equations</title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967147497</link>
         <description><![CDATA[<p><br></p><ul><li><p>Chemical equations use the chemical symbols of each reactant and product</p></li><li><p>When balancing equations, there has to be the&nbsp;<strong>same number of atoms</strong> of each element on either side of the equation in accordance with the Law of Conservation of Mass</p></li><li><p>A symbol equation uses the formulae of the reactants and products to show what happens in a chemical reaction</p></li><li><p>A symbol equation must be balanced to give the correct ratio of reactants and products:<strong>&nbsp; &nbsp;</strong></p></li></ul><p><br></p><p><strong>S + O<sub>2</sub>&nbsp;→ SO<sub>2</sub></strong></p><p><br></p><ul><li><p>This equation shows that one atom of sulfur (S) reacts with one&nbsp; molecule of oxygen (O<sub>2</sub>) to make one molecule of sulfur dioxide (SO<sub>2</sub>)</p></li><li><p>The following non-metals must be written as molecules: H<sub>2</sub>, N<sub>2</sub>, O<sub>2</sub>, F<sub>2</sub>, Cl<sub>2</sub>, Br<sub>2</sub>&nbsp;and I<sub>2</sub></p></li><li><p>To balance an equation you work across the equation from left to right, checking one element after another</p></li><li><p>If there is a group of atoms, for example a nitrate group (NO<sub>3</sub><sup>–</sup>) that has not changed from one side to the other, then count the whole group as one entity rather than counting the individual atoms</p></li><li><p>Examples of chemical equations:</p><ul><li><p>Acid-base neutralisation reaction:</p></li></ul><p><br></p></li></ul><p><br></p><p><strong>NaOH (aq) + HCl (aq)&nbsp; ⟶ NaCl (aq) + H<sub>2</sub>O (l)&nbsp;</strong></p><ul><li><p>Redox reaction:</p><p><br></p></li></ul><p><br></p><p><strong>2Fe<sub>2</sub>O<sub>3&nbsp;</sub>(aq) + 3C (s) ⟶ 4Fe (s) + 3CO<sub>2</sub>&nbsp;(g)</strong></p><p><br></p><ul><li><p>In each equation there are equal numbers of each atom on either side of the reaction arrow so the equations are balanced</p></li></ul>]]></description>
         <enclosure url="" />
         <pubDate>2024-04-24 00:32:35 UTC</pubDate>
         <guid>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967147497</guid>
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         <title>Writing ionic equations</title>
         <author>y102023001</author>
         <link>https://padlet.com/y102023001/d6au9eqmcmcseatb/wish/2967151884</link>
         <description><![CDATA[<ul><li><p>In aqueous solutions ionic compounds dissociate into their ions, meaning they separate into the component ions that formed them, e.g. hydrochloric acid and potassium hydroxide dissociate as follows:</p></li></ul><p>HCl (aq) → &nbsp;H<sup>+</sup> (aq) + Cl<sup>-</sup>(aq)&nbsp;</p><p>KOH (aq) &nbsp;→ K<sup>+ </sup>(aq) &nbsp;+ OH<sup>- </sup>(aq)&nbsp;</p><p><br></p><p><br></p><ul><li><p>It is important that you can recognise common ionic compounds and their constituent ions</p></li><li><p>These include:</p><ul><li><p>Acids such as HCl and H<sub>2</sub>SO<sub>4</sub></p></li><li><p>Group I and Group II hydroxides e.g. sodium hydroxide</p></li><li><p>Soluble salts e.g. potassium sulfate, sodium chloride</p></li></ul></li><li><p>Follow the example below to write ionic equations&nbsp;</p></li></ul>]]></description>
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         <pubDate>2024-04-24 00:35:29 UTC</pubDate>
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