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      <title>Klonen von Hilfskärtchen - Gehrungswinkel by </title>
      <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb</link>
      <description></description>
      <language>en-us</language>
      <pubDate>2023-12-12 10:42:03 UTC</pubDate>
      <lastBuildDate>2023-12-12 10:42:04 UTC</lastBuildDate>
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      <item>
         <title>Teilung</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304721</link>
         <description><![CDATA[<div><strong>Teilt</strong> die Bohrlehre in einzelne geometrische Formen <strong>auf</strong>.</div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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      <item>
         <title>BEGINN!</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304722</link>
         <description><![CDATA[<div><strong>Schaut</strong> euch die Hilfskärtchen nach der Reihenfolge <strong>an</strong> und <strong>vergleicht</strong> eure Ergebnisse bzw. Schritte. <strong>Denkt</strong> über die Ergebnisse<strong> nach</strong>!</div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304722</guid>
      </item>
      <item>
         <title>Flächeninhalt vom Halbzeug</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304724</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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      </item>
      <item>
         <title>Formel für die geometrische Form</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304725</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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      <item>
         <title>Formel - Rechteck</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304726</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304726</guid>
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      <item>
         <title>Flächeninhalt vom Halbzeug - Lösung</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304728</link>
         <description><![CDATA[<div><strong><em>1000000 mm² </em></strong></div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304728</guid>
      </item>
      <item>
         <title>Flächeninhalt vom Werkstück</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304729</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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      <item>
         <title>Teilung in (...)</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304730</link>
         <description><![CDATA[<div>-Halbkreis<br>-Rechteck<br>-Rechtwinkliges Dreieck</div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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      <item>
         <title>Teilung - Lösung + Maße</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304731</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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      <item>
         <title>Berechnung von einzelnen geometrischen Formen</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304732</link>
         <description><![CDATA[<div>-<strong>Sucht </strong>nach Formeln für die einzelnen geometrischen Formen.</div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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      <item>
         <title>Formel - Halbkreis</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304735</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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      <item>
         <title>Halbkreis - Lösung</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304736</link>
         <description><![CDATA[<div><strong><em>481,06 mm² </em></strong></div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304736</guid>
      </item>
      <item>
         <title>Formel - Rechteck</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304737</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304737</guid>
      </item>
      <item>
         <title>Rechteck - Lösung</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304738</link>
         <description><![CDATA[<div><strong><em>3360 mm² </em></strong></div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304738</guid>
      </item>
      <item>
         <title>Formel - Rechtwinkliges Dreieck</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304740</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304740</guid>
      </item>
      <item>
         <title>Rechtwinkliges Dreieck - Lösung</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304741</link>
         <description><![CDATA[<div><strong><em>638,75 mm² </em></strong></div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304741</guid>
      </item>
      <item>
         <title>Einzelne Flächen zusammenrechnen</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304742</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304742</guid>
      </item>
      <item>
         <title>Formel - gesamte Fläche</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304743</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304743</guid>
      </item>
      <item>
         <title>Gesamte Fläche vom Werkstück - Lösung</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304744</link>
         <description><![CDATA[<div><strong><em>4479,81 mm² </em></strong></div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304744</guid>
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      <item>
         <title>Prozentualer Verschnitt</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304745</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304745</guid>
      </item>
      <item>
         <title>Flächeninhalt vom Verschnitt - Lösung inklusive Rechenweg</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304746</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304746</guid>
      </item>
      <item>
         <title>Prozentualer Verschnitt - Lösung</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304747</link>
         <description><![CDATA[<div><strong><em>0,0088 %</em></strong></div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
         <guid>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304747</guid>
      </item>
      <item>
         <title>FERTIG!</title>
         <author>hpm6xv5rf6_</author>
         <link>https://padlet.com/hpm6xv5rf6_/cehtiwtzzwfadkqb/wish/2822304748</link>
         <description><![CDATA[<div>Habt ihr noch Fragen bzw. Unklarheiten? Wenn ja, dann <strong>bittet</strong>  die Lehrkraft nach Hilfe!</div>]]></description>
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         <pubDate>2023-12-12 10:42:03 UTC</pubDate>
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