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      <title>WEP GR12 by Lizelle Swanepoel</title>
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         <author>lizellexs</author>
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         <description><![CDATA[<div><strong>ENERGY = THE ABILITY TO DO WORK<br>WORK = ENERGY TRANSFERRED</strong></div>]]></description>
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         <title>TYPES OF ENERGY</title>
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         <title>WORK</title>
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         <description><![CDATA[<div>Product of force parallel to movement and the displacement of a body</div>]]></description>
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         <title>W = FΔx.cosϴ</title>
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         <description><![CDATA[<ul><li><mark>When is W positive?</mark></li><li><mark>When is W negative?</mark></li></ul>]]></description>
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         <title></title>
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         <title></title>
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         <title>POSITIVE VS NEGATIVE WORK</title>
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         <title>Positive vs negative work</title>
         <author>lizellexs</author>
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         <title>Work done by forces in different directions</title>
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         <title>Is work done on a tray that is carried by a waiter moving at constant speed?</title>
         <author>lizellexs</author>
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         <description><![CDATA[<div>NO.<br>The force applied on the tray is vertically upwards to overcome the force of gravity on the tray, and there is no part (component) of that force that acts in the same direction as the displacement horizontally. </div>]]></description>
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         <title>CONSERVATION OF MECHANICAL ENERGY</title>
         <author>lizellexs</author>
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         <description><![CDATA[<div>Principle of Conservation of Mechanical Energy states: <br><mark>In the absence of external forces, the </mark><strong><mark>total</mark></strong><mark> mechanical energy in a </mark><strong><mark>system</mark></strong><mark> is CONSTANT.</mark><strong><mark><br><br></mark></strong>Def for mechanical energy: <strong><mark><br>Mechanical energy is the sum of gravitational potential energy and kinetic energy at a point.</mark></strong></div>]]></description>
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         <title>ROLLER COASTER PROBLEM</title>
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         <title>Answers Notes</title>
         <author>lizellexs</author>
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         <description><![CDATA[<div>Answers p. 13-16</div>]]></description>
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         <title>Work-Energy Theorem = The work done on an object by a net force is equal to the change in the object&#39;s kinetic energy</title>
         <author>lizellexs</author>
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         <description><![CDATA[<div><strong><mark>W</mark></strong><strong><mark><sub>net</sub></mark></strong><strong><mark> = ΔE</mark></strong><strong><mark><sub>k</sub></mark></strong></div>]]></description>
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         <title>Work done by forces acting on inclined plane</title>
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         <title>WORK DONE AGAINST FRICTION</title>
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         <title></title>
         <author>lizellexs</author>
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         <description><![CDATA[<div><strong>Answers p.19-43 NOTES</strong></div>]]></description>
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      <item>
         <title>Power</title>
         <author>lizellexs</author>
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         <title></title>
         <author>lizellexs</author>
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         <title>End of chapter ANSWERS NOTES </title>
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         <title></title>
         <author>lizellexs</author>
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         <title>EXAM QUESTION </title>
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         <title>MEMO - EXAM QUESTION ABOVE</title>
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         <title>EXAM PAPER - 2019 PHYSICS FINALS</title>
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         <title></title>
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         <description><![CDATA[TEST MEMO]]></description>
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         <title></title>
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         <description><![CDATA[TEST MEMO]]></description>
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         <title></title>
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         <description><![CDATA[TEST MEMO]]></description>
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         <title></title>
         <author>lizellexs</author>
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         <description><![CDATA[TEST MEMO]]></description>
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      <item>
         <title>Principle of Conservation of Mechanical Energy = The total mechanical energy (sum of gravitational potential energy and kinetic energy) in an isolated system remains constant. </title>
         <author>lizellexs</author>
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         <pubDate>2022-02-06 20:19:59 UTC</pubDate>
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         <title>CONSERVATIVE VS NON-CONSERVATIVE FORCES</title>
         <author>lizellexs</author>
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      <item>
         <title>CONSERVATIVE VS NON-CONSERVATIVE FORCES</title>
         <author>lizellexs</author>
         <link>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2031820580</link>
         <description><![CDATA[<div><strong><mark>Wnc&nbsp; = ∆E</mark></strong><strong><mark><sub>k</sub></mark></strong><strong><mark> + ∆E</mark></strong><strong><mark><sub>p</sub></mark></strong></div><div><strong>&nbsp;</strong></div><div><strong>Example:</strong>&nbsp; <br>A sphere of mass <mark>2 kg</mark> is shot vertically upwards from ground level and reaches a maximum height of <mark>4 m </mark>above the ground. A constant <mark>frictional force of 5,4 N</mark> acts on the sphere throughout its motion. <br><mark>Calculate the initial velocity of the sphere.&nbsp;</mark></div>]]></description>
         <enclosure url="https://youtu.be/vFVCluvSrFc" />
         <pubDate>2022-02-06 20:42:15 UTC</pubDate>
         <guid>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2031820580</guid>
      </item>
      <item>
         <title>ANSWER</title>
         <author>lizellexs</author>
         <link>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2034994440</link>
         <description><![CDATA[<div><strong>Wnc&nbsp; = ∆E</strong><strong><sub>k</sub></strong><strong> + ∆E</strong><strong><sub>p</sub></strong><strong>&nbsp;</strong></div><div><strong>&nbsp;</strong></div><div><br><br><br><br><em>W</em><em><sub>nc</sub></em><em> = F</em><em><sub>f</sub></em><em> ∆xcosθ = F</em><em><sub>f</sub></em><em> ∆x cos180 = 5.4 x 4 x (-1) = -21.6 J</em></div><div><em>&nbsp;</em></div><div><em>&nbsp; &nbsp;∆E</em><em><sub>p </sub></em><em>=&nbsp; mgh</em><em><sub>f</sub></em><em> - mgh</em><em><sub>i</sub></em><em> = 2*9.8*4 – 0 = 78.4 J</em></div><div><em>&nbsp;</em></div><div><em>&nbsp; &nbsp;∆E</em><em><sub>k</sub></em><em> = ½ mv</em><em><sub>f</sub></em><em><sup>2</sup></em><em> -½ mv</em><em><sub>i</sub></em><em><sup>2</sup></em><em>&nbsp; &nbsp; = 0 – ½ x 2 x v</em><em><sub>i</sub></em><em><sup>2</sup></em><em> = - v</em><em><sub>i</sub></em><em><sup>2</sup></em></div><div><em>&nbsp;</em></div><div><strong>Wnc&nbsp; = ∆E</strong><strong><sub>k</sub></strong><strong> + ∆E</strong><strong><sub>p</sub></strong><strong>&nbsp;</strong></div><div><em>&nbsp;</em></div><div><em>.: -21.6 = - v</em><em><sub>i</sub></em><em><sup>2</sup></em><em> + 78.4&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;.: v</em><em><sub>i</sub></em><em> = √(21.6 + 78.4) = 10 m.s</em><em><sup>-1</sup></em></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-02-08 08:59:22 UTC</pubDate>
         <guid>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2034994440</guid>
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         <title></title>
         <author>lizellexs</author>
         <link>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2464234613</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-02-01 08:33:56 UTC</pubDate>
         <guid>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2464234613</guid>
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      <item>
         <title>ANSWERS - NOTES 2023</title>
         <author>lizellexs</author>
         <link>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2464235101</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-02-01 08:34:22 UTC</pubDate>
         <guid>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2464235101</guid>
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         <title>Work done by angled forces</title>
         <author>lizellexs</author>
         <link>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2464430281</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-02-01 11:38:34 UTC</pubDate>
         <guid>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2464430281</guid>
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         <title></title>
         <author>lizellexs</author>
         <link>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2464430507</link>
         <description><![CDATA[]]></description>
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         <pubDate>2023-02-01 11:38:48 UTC</pubDate>
         <guid>https://padlet.com/lizellexs/c6xl1vvlznb8y8of/wish/2464430507</guid>
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