Circle Theorem by Divya Nair

divvyanair — 2020-09-21 19:12:00 UTC

divvyanair — 2020-09-21 19:14:52 UTC

divvyanair — 2020-09-21 19:15:53 UTC

divvyanair — 2020-09-30 06:47:34 UTC

divvyanair — 2020-09-30 06:47:52 UTC

divvyanair — 2020-09-30 06:48:11 UTC

divvyanair — 2020-09-30 06:48:28 UTC

divvyanair — 2020-09-30 08:07:41 UTC

divvyanair — 2020-09-30 08:08:10 UTC

divvyanair — 2020-09-30 08:10:17 UTC

Manal

2020-09-30 08:29:30 UTC

For Angle AOC, the answer is 136 if we follow Theorm 1

Angle AOC = 136

2020-09-30 08:29:44 UTC

68 x 2 = 136
(theorem 1) the angle at the center is twice the angle at the circumference
ramsha

Labiba

2020-09-30 08:31:11 UTC

Angle ABC = 112
the angles at the cyclic quadilateral are supplimentary.
AOC=136 the angle at the center is twice the angle at he circumference. so 68*2=136

Sana

2020-09-30 08:32:47 UTC

ABC = 112
AOC = 136

Maliha Q1

2020-09-30 08:33:01 UTC

ABC = 180-68 = 112
AOC = 136

ABC=112

2020-09-30 08:33:27 UTC

opposite angles of a cyclic quadrilateral are supplimentary
Q3.a. PQS= 41
PTS= 75
Amnah

Eman Shakeel

2020-09-30 08:34:22 UTC

AOC= 68X2 = 136
Theorem 1

ramsha

2020-09-30 08:34:28 UTC

Angle abc = 180 -68 = 112 (cyclic quadrilateral)

humdia

2020-09-30 08:34:45 UTC

ABC=112 (cyclic quad)
AOC=136 (angle at center)

2020-09-30 08:34:58 UTC

Munahil-180-68=112(cyclic quadrilateral, opposite angles add up to 180)

2020-09-30 08:35:41 UTC

Ayesha safdar

2020-09-30 08:35:43 UTC

Angle AOC is 68*2 = 136 as theorem 1 which means the angle at the center is twice the angle subtended at the circumference, applies here

Manahil Zahra

2020-09-30 08:36:11 UTC

Cyclic quadrilateral : 112 (180-68)

Ayesha safdar

2020-09-30 08:36:26 UTC

Angle ABC is 112 using the theorem of cyclic quadrilateral

yumna

2020-09-30 08:37:01 UTC

2020-09-30 08:37:24 UTC

Munahil-AOC=68*2=136(the angle in the center is twice of that at the circumference)

Eman Shakeel

2020-09-30 08:38:16 UTC

ABC= D+B will make 180
so, 68+B=180
180-68= 112 ABC= 112
the opposite angles of the cyclic quadrilateral are supplementary (theorem 6)

Labiba

2020-09-30 08:38:25 UTC

2) Alternate angles are equal
Alternate segment theorem.

zainab

2020-09-30 08:38:27 UTC

AOC=136 ( the angle at the center is twice)
ABC= 112 ( the cyclic quadrilateral)

Sana

2020-09-30 08:39:40 UTC

AED = 47 (alternate angle)
BCD = 124 (cyclic theorum)
ADB = 47 (alternate segment)

Maliha Q2

2020-09-30 08:39:50 UTC

BCD = 180-56 = 124 (cyclic quadrilateral)
AED = 47 (alternate angles)
ADB = 47 (alternate segment theorem)

Ramsha

2020-09-30 08:40:34 UTC

Q2) angle AED = 47 because alternate angle
Angle BCD = 180 - 56 = 124 because cyclic quadrilateral

Manahil Zahra

2020-09-30 08:41:48 UTC

AED=47 (alternate angles)

Eiman Adil

2020-09-30 08:42:36 UTC

Angle ABC= 112 ( Cyclic Quadrilateral theorem)
Angle AOC= 136 (Angle made at the centre by an arc is twice the angle made at the circumference by the same arc)

2020-09-30 08:42:57 UTC

Munahil-AED=47( the two lines are parallel and they make a Z)

Eman Shakeel

2020-09-30 08:43:38 UTC

AED= 47
As all alternate angles are equal
BCD= 180-56= 124
(Cyclic quadrilateral theorem)
ADB= 47
(Alternate segment theorem)

Ayesha safdar

2020-09-30 08:43:45 UTC

Angle AED makes an alternate angle so its 47
Angles BCD is 124 as it makes the cyclic quadrilateral with 56 on the opposite side so 180-56= 124

2020-09-30 08:46:30 UTC

Munahil=BCD=124(quadrilateral cyclic theorim)

humdia

2020-09-30 08:47:03 UTC

aed=47 alt angles
bcd=124 cyclic quad
adb=47 alt seg

2020-09-30 08:47:15 UTC

zainab

2020-09-30 08:47:23 UTC

Q2) AED=47 ( alt angle)
BCD=180-56=124 (cyclic quadrilateral )

yumna

2020-09-30 08:47:27 UTC

2020-09-30 08:49:24 UTC

Tehreem

2020-09-30 08:50:41 UTC

Eiman Adil

2020-09-30 08:51:37 UTC

Angle AED= 47 ( Alternate angles are equal)
Angle BCD= 124 ( Cyclic Quadrilateral, opposite angle add up to 180)
Angle ADB= 47 ( Alternate angles are equal)