https://padlet.com/berrypiz/bqxt9ivnizp01g3v en-us 2020-08-19 12:46:48 UTC 2026-01-17 09:03:05 UTC hello@padlet.com berrypiz https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/686913019 2020-08-19 12:53:51 UTC https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/686913019 berrypiz https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/698383549 2020-08-25 19:14:46 UTC https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/698383549 https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700920455 each side can make three less diagonals than the number of sides (not each neighbor or itself). So for 8 sides, each vertex can make 5 diagonals. So the total number of diagonals is the number of vertices multiplied by the number of diagonals. But wait! Then we have too many diagonals because we have counted each diagonal twice, so divide by 2!

[x(x-3)]/2]]> 2020-08-26 18:50:50 UTC https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700920455 https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700922783 First person shakes hands with 8 then the next one shakes hands with 7 and so on . These values can then be added ]]> 2020-08-26 18:51:33 UTC https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700922783 https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700930699 Formula for second question]]> 2020-08-26 18:54:02 UTC https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700930699 https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700935069 problem #1

A -> B,C,D,E
B -> A,C,D,E
C -> A,B,D,E
D -> A,B,C,E
E -> A,B,C,D

4X5 = 20 HANDSHAKES

N(N-1)

]]> 2020-08-26 18:55:31 UTC https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700935069 berrypiz https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700941042 2020-08-26 18:57:30 UTC https://padlet.com/berrypiz/bqxt9ivnizp01g3v/wish/700941042