Calculating Ka from pH. by UAE Abu Dhabi

--------------(Mrs. Ghada)----------------

uaeoo2021 — 2021-03-07 01:16:58 UTC

Reem Ali

2024-01-29 05:06:31 UTC

[H+] = 4.17 × 10^-3

[initial formic acid] = 0.096

Ka = 1.8 × 10^-4

Noura Khaled

2024-01-29 05:06:36 UTC

[H+] = 4.2x10^-3M

[H+] = [HCOO-]

Ka= (4.2x10^-3)^2 / (0.1-4.2x10^-3)

Ka = 1.8x10^-4

Alyaziyah Abdullah

2024-01-29 05:06:37 UTC

[H+]= antilog(-2.38)

[H+]= 4.2x10^-3M

Ka= (4.2x10^-3)^2 / 0.100-4.2x10^-3)

Ka= 1.8x10^-4M

Fatima Nasser

2024-01-29 05:06:48 UTC

[H+]+4.2x10^-3M

[H+]=[HCOOH-]

Ka=(4.2x10^-3)^2/0.1-4.2x10^-3

ka=1.8x10^-4

Raghad ameer

2024-01-29 05:07:15 UTC

Ka= 1.81x10^-4

Shamayel

2024-01-29 05:07:26 UTC

1.8x10^-4

reem g

2024-01-29 05:07:33 UTC

ka=1.8x10^-4

Yumna Rami

2024-01-29 05:07:43 UTC

[H]= 4.17X10^-3

[HCOOH]=0.095

Ka= 1.8x10^-4

Rama Hammadi

2024-01-29 05:07:50 UTC

1.8x10^-4

Aldemani Alyammahi

2024-01-29 05:07:50 UTC

[H+]= antilog(-2.38)

[H+]= 4.2x10^-3M

ka= (4.2x10^-3)^2 / 0.100-4.2x10^-3)

Ka= 1.8x10^-4M

Alyazyah Ahmed

2024-01-29 05:07:55 UTC

[H+] = 4.17 × 10^-3

[initial formic acid] = 0.096

Ka = 1.18 × 10^-4

layan

2024-01-29 05:08:30 UTC

[H]=4.16x10^-3

4.16x10^-3x4.16x10^-3/0.100-4.16x10^-3

=1.8x10-4

fatima muhannad

2024-01-29 05:08:31 UTC

1.8x10^-4

lulwa

2024-01-29 05:08:36 UTC

Ka=1.8 x 10^-4

Yassmen Mohammed

2024-01-29 05:08:40 UTC

(4.17x10^-5)^2/0.1-4.17x10^5

=1.813x10^-4

Fatima Eissa

2024-01-29 05:09:12 UTC

Ka =1.8x10^-4

Jawhara Ayman

2024-01-29 05:09:32 UTC

[H+]=10^-2.38 = 4.16x10^-3

Ka= (4.16x10^-3)(4.16x10^-3)/(0.100-4.16x10^-3)

=1.8x10^-4

2024-01-29 05:10:00 UTC

Ka=1.8x10^-4

Noora Abdulaziz

2024-01-29 05:10:47 UTC

Ka= (4.2*10^-3)^2 /0.100-4.3*10^-3

Ka= 1.8*10^-4M