https://padlet.com/lucdunoyer/bktaofq2e29h Made with a bold sensibility en-us 2016-07-06 15:03:24 UTC 2023-05-24 05:14:04 UTC hello@padlet.com https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116012513 We performed the chi-squared goodness of fit test on the cricket data in order to determine whether or not the outcome in pairwise interactions between male house crickets was actually influenced by the residency status of the crickets. We found a p-value of 1.00 with one degree of freedom. This means that we fail to reject the null hypothesis that the resident-intruder results would be 50-50. This indicates that residency does not have a significant effect on cricket behavior. This study may have some limitations in that it does not take into account other factors that may have affected cricket interactions such as body size, speed, or recent fighting history. Perhaps the resident crickets did not have enough time to establish residency and therefore the residency effect was not fully present. The scientific community could expand upon this study by examining other motivating factors crickets could have had. ]]> 2016-07-06 16:19:09 UTC https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116012513 https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116012998 2016-07-06 16:28:08 UTC https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116012998 https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013113 We used a chi-square because both the independent and dependent variables were discrete. Chi squared equals 0.205 with 1 degrees of freedom. The 2 totaled P value equals 0.6506. By conventional criteria, this difference is considered to be NOT statistically significant. ]]> 2016-07-06 16:30:28 UTC https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013113 https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013531 2016-07-06 16:40:10 UTC https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013531 https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013655 A chi-squared test was determined to be the best statistical method for this experiment because both variables are discrete. The chi-squared value of this data was 0.205. Because the degrees of freedom is 1, the two-tailed p-value was 0.6506. This means that the data is not statistically significant and thus we cannot reject the null hypothesis. There is no statistical difference between the wins of a resident cricket and an intruder cricket.]]> 2016-07-06 16:41:08 UTC https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013655 https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013764 2016-07-06 16:43:14 UTC https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013764 https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013880 The statistical chi-squared test was performed because both the dependent and independent variables were discrete. The residents won a total of 41 aggressive interactions and the intruders won a total of 37 interactions. There were 78 interactions total amongst 18 trials at ten minutes a piece. The chi-squared number was equal to 0.205 with one degree of freedom. The two-tailed p value was equal to 0.6506 which is greater than 0.05. This shows that the null hypothesis can not be rejected. With 95% assurance it can be determined that the results are not statistically significant. Perhaps the sample size was not large enough, or the intruder crickets were made to be more aggressive by capturing and painting on them. Another experiment could be conducted with far more crickets. Additionally, another way of tagging the intruder cricket could be found. ]]> 2016-07-06 16:44:55 UTC https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116013880 https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116014215 2016-07-06 16:51:41 UTC https://padlet.com/lucdunoyer/bktaofq2e29h/wish/116014215