Period 7 Coulumb's Law Practice 2 by Thomas E Clark https://padlet.com/tec430/bg5k079rv02t (Problems 6-8 attatched in Schoology) en-us 2017-04-25 20:43:01 UTC 2025-11-13 00:07:24 UTC hello@padlet.com Sakshi,Diana, and Catlan https://padlet.com/tec430/bg5k079rv02t/wish/168244840 6. The third arrangement (+ + .+ +) will have the greatest net force because the all charges are all the same. This is cause the charges to repel away from each other. The strongest repulsion will be on the ends because the charges are closer together there, but the charges will also repel the similar charges against the neutral dot. In the first arrangement (- +. - +) the charges will cancel each other out on the ends. The opposite charges will still be arranged to the opposite charge across the dot but the charges will be more strongly attracted to the charge near them. In the second arrangement(+ - . - +) the ends will still cancel each other out but because the like charges are both closer to the dot, they will be attracted to the outside because they will repel the like charge against the dot and be attracted to the opposite charge on the ends. 
IF THE CENTER WAS POSITIVE
In the third arrangement, in the center will receive a strong repulsion force because the center will repel the outside and the outsides will repel the center. Overall the net force will be outward on both sides of center charge. In the second arrangement, the center charge will be more strongly attracted to the right side of the line of charges because the positive center charge will be attracted to the negative on the right side and repelled by the like positive charge on the left side. In the first arrangement, the center charge will attract the two negative charges from the outside but because the ends are positive they will also be attracted to the negative charges meaning the overall net force is inward, towards the center of the line.
7. F=k*Q1*Q2/(r^2)
F=(8.998*10^9)*(1.602*10^-19)*(1*10^-7)/(0.05)^2
F=5.76*10^-14
(5.76*10^-14)*2=1.15*10^-13 N/C
8. ]]> 2017-04-25 22:04:41 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168244840 Tamera 和 Bonny https://padlet.com/tec430/bg5k079rv02t/wish/168244902 6. The third central charge has the greatest net force acting on it because the same charges on each side repulse each other, applying force to the central charge. In the first central charge, the opposite charges on each side attract each other, so there is no force applied to the central charge. In the second central charge, the opposites also attract on each side, so there is no force on the central charge.
7. Use Coulomb's law to find the electrical force from above, from the top right (diagonal, so use pythagorean theorem to find the r), and from the force to the right of the lower left. After we find the three electrical forces, we add all of the electrical forces together to find the total magnitude of the force exerted on the charge at the lower left corner. We got -0.108N.
8. ]]> 2017-04-25 22:05:17 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168244902 Hiwot Ena Yohe https://padlet.com/tec430/bg5k079rv02t/wish/168245009 6) The third one has the strongest force , since the same sign charge repulse each other. While the first and second one have  opposite signs, but the force cancel  out so their is no net charge. 
7) First find the three forces that are acting on the left most point using Coulomb's law. For the third force that is from the top right forms a diagonal so using the property of a right triangle we can find the distance. After finding the forces we added them together and we found the force to be -.108 N.
8)

]]> 2017-04-25 22:06:22 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168245009 Alex https://padlet.com/tec430/bg5k079rv02t/wish/168245107 6. The third arrangement has the strongest force since they have the same forces, repulsing each other and applying more force on the central force. The first and second arrangements have opposite signs so they have no net force. 
7. F= (k*Q1*Q2)/d^2
F= ]]> 2017-04-25 22:07:49 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168245107 Caitlin and Ruth https://padlet.com/tec430/bg5k079rv02t/wish/168245153 6. The third  arrangement will be the one that will have a net force on the central charge. The second and first arrangement will have a net force of zero. If the central charge is positive, then it will exert a force. 
7. F= k(2q)(q)/(a^2)
F= k(2q)(q)/square root of (2a)^2 
F= k(2q)(2q)/(a^2) ]]> 2017-04-25 22:08:40 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168245153 Jose https://padlet.com/tec430/bg5k079rv02t/wish/168245465 6) 3 has the strongest net force focused on the central charge. Same place.
7)]]> 2017-04-25 22:12:45 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168245465 Caitlin https://padlet.com/tec430/bg5k079rv02t/wish/168508258 F= ]]> 2017-04-26 21:55:32 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168508258 Sitara https://padlet.com/tec430/bg5k079rv02t/wish/168509179 6. The third charge has the greatest net force because the same sign charge repulses each other. If they had different signs, the force would cancel it out so there would be no net charge.
7. F=k(2q)(q)/(a^2)

]]> 2017-04-26 22:08:25 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168509179 Jose I https://padlet.com/tec430/bg5k079rv02t/wish/168509895 7)F=K* (Q1)(Q2)/r^2]]> 2017-04-26 22:17:48 UTC https://padlet.com/tec430/bg5k079rv02t/wish/168509895 Hiwo and Yohe https://padlet.com/tec430/bg5k079rv02t/wish/169038954 8) The weight force acts downward. (1.0x1^-6)(9.8)/tan6= 9x10^9(q^2)/(.25)^2

q=6.3x10^-9]]> 2017-04-30 04:31:58 UTC https://padlet.com/tec430/bg5k079rv02t/wish/169038954 Caitlin and Ruth https://padlet.com/tec430/bg5k079rv02t/wish/170100873 7. F= k(2q)(q)/(a^2) = 0.072 N 
F= k(2q)(q)/square root of (2a)^2 = 0.036 N
F= k(2q)(2q)/(a^2) = 0.144 N
= .036(cos45)+.144 = .17 N
= .17 N - .072 N = -0.05 N
Fe = 0.18 N
8. 1.0x10^-6 (9.8)/tan60 = 9x10^9(q2)(.25)^2
q = 6.3x10^-9 C 
]]> 2017-05-05 05:51:31 UTC https://padlet.com/tec430/bg5k079rv02t/wish/170100873