P2 Warm Up by Thitiya Karamooz [Escobedo MS]

10/13 - Write an inequality of the question below.

pathatn — 2020-10-13 18:27:15 UTC

The Desert Taxi Cab Company charges a $1.75 flat rate in addition to $0.65 per mile. Jaelyn has no more than $10 to spend on the ride. How many miles can Jaelyn go without exceeding her amount of money?

Maisie Paton

2020-10-13 18:32:54 UTC

$1.75+0.65x>_10

Jackson Davis

2020-10-13 18:33:48 UTC

1.75+0.65m < 10

Hyrum Parry

2020-10-13 18:34:25 UTC

$1.75+0.65

2020-10-13 18:34:35 UTC

$0.65m + 1.75 < 10

Elijah Theos-King

2020-10-13 18:34:37 UTC

$1.75+0.65m

aaron kison

2020-10-13 18:34:44 UTC

$1.75+$0.65 < or = to 10

Sei Valdez

2020-10-13 18:34:46 UTC

1.75+.65x < 10

Dale Flores

2020-10-13 18:34:51 UTC

$0.65m+$1.75

Isabella Zubrick

2020-10-13 18:34:54 UTC

$1.75+$0.65m

Ana Cardenas

2020-10-13 18:34:58 UTC

$.65m+$1.75<_10

Brody Bulloch

2020-10-13 18:35:00 UTC

$1.75+ $0.65x<10

Maggie Brinkman

2020-10-13 18:35:04 UTC

0.65m+$1.75≤10

Michelle S.

2020-10-13 18:35:04 UTC

$1.75+0.65x>$10

Marlon Monteagudo

2020-10-13 18:35:09 UTC

$1.75 + $0.65M ≥ 10

Teira Bell

2020-10-13 18:35:11 UTC

$0.65m+$1.75<_$10

Lewis Kelley

2020-10-13 18:35:15 UTC

$0.65m+1.75

lily brooks

2020-10-13 18:35:16 UTC

$1.75+$0.65m>$10

Angelica Salazar

2020-10-13 18:35:21 UTC

1.75+.65m_<10

Nicholas Kotero

2020-10-13 18:35:36 UTC

$0.65m+$1.75

Nicolas Melgarejo

2020-10-13 18:35:47 UTC

1.75+.65x<_10

Adriel Dionisio

2020-10-13 18:35:51 UTC

$1.75+$0.65m<$10

2020-10-13 18:36:03 UTC

comment 0 Nicholas Kotero Avatar of anonymous Anonymous 1m Nicholas Kotero $0.65m+$1.75

Aamara Dancel

2020-10-13 18:36:25 UTC

$1.75 + $0.65 < $10

Sydnee Roberts

2020-10-13 18:37:06 UTC

$1.75 + $0.65 <_ $10

brandy carson

2020-10-13 18:37:16 UTC

$1.75 + $0.65 < $10

aaron kison

2020-10-13 18:38:15 UTC

$1.75+$0.65 < or = to $10

skylar boehm

skylar_369197 — 2020-10-13 18:38:35 UTC

1.75 + 0.65 < 10

Shallon Severts

2020-10-13 18:40:03 UTC

$1.75+$0.65<$10

isaias gutierrez

2020-10-13 18:40:20 UTC

$1.75 + $0.65

2020-10-13 18:40:29 UTC

Elijah Theos-King Avatar of anonymous Anonymous 1m Elijah Theos-King $1.75+0.65m comment 0 Hyrum Parry Avatar of anonymous Anonymous 1m Hyrum Parry $1.75+0.65 comment 0 more_vert Sei Valdez Avatar of anonymous Anonymous 1m Sei Valdez 1.75+.65x < 10 comment 0 Nicolas Melgarejo Avatar of anonymous Anonymous 1m Nicolas Melgarejo 1.75+.65x<10 comment 0 Ana Cardenas Avatar of anonymous Anonymous 1m Ana Cardenas $.65m+$1.75<10 comment 0 Brody Bulloch Avatar of anonymous Anonymous 1m Brody Bulloch $1.75+ $0.65<10 comment 0 $0.65m + 1.75 < 1 Avatar of anonymous Anonymous 1m $0.65m + 1.75 < 10 Austin May comment 0 Joe Avatar of anonymous Anonymous 1m Joe comment 0 Lewis Kelley Avatar of anonymous Anonymous 1m Lewis Kelley $0.65m+1.75 $10 comment 0 Dale Flores Avatar of anonymous Anonymous 1m Dale Flores $0.65m+$1.75<$10 comment 0 Michelle S. Avatar of anonymous Anonymous 1m Michelle S. $1.75+0.65x>$10 comment 0 Maggie Brinkman Avatar of anonymous Anonymous 1m Maggie Brinkman 0.65m+$1.75≥10 comment 0 Marlon Monteagudo Avatar of anonymous Anonymous 1m Marlon Monteagudo $1.75 + $0.65M ≥ 10 comment 0 lily brooks Avatar of anonymous Anonymous 1m lily brooks $1.75+$0.65m>$10 comment 0 Teira Bell Avatar of anonymous Anonymous 1m Teira Bell $0.65m+$1.75<_$10 comment 0 Angelica Salazar Avatar of anonymous Anonymous 1m Angelica Salazar 1.75+.65m_<10 comment 0 Nicholas Kotero Avatar of anonymous Anonymous 1m Nicholas Kotero $0.65m+$1.75 comment 0 Avatar of anonymous Anonymous 1m Adriel Dionisio $1.75+$0.65m<$10 comment 0 Avatar of anonymous Anonymous 1m comment 0 Nicholas Kotero Avatar of anonymous Anonymous 1m Nicholas Kotero $0.65m+$1.75 comment 0 brandy carson Avatar of anonymous Anonymous 1m brandy carson $1.75 + $0.65 < $10 comment 0 Sydnee Roberts Avatar of anonymous Anonymous 1m Sydnee Roberts $1.75 + $0.65 < $10 comment 0 aaron Avatar of anonymous Anonymous 1m aaron $1.75+$0.65 < or = to $10 comment 0 skylar boehm Avatar of Skylar Boehm [STUDENT] Skylar Boehm [STUDENT] 1m skylar boehm 1.75 + 0.65 < 10 comment 0 $1.75+$0.65 Avatar of anonymous Anonymous 1m $1.75+$0.65 comment 0

2020-10-13 18:40:47 UTC

skylar boehm 1.75 + 0.65 < 10 comment 0 Shallon Severts Avatar of anonymous Anonymous 1m Shallon Severts $1.75+$0.65<$10 comment 0 isaias gutierrez

2020-10-13 18:40:50 UTC

skylar boehm 1.75 + 0.65 < 10 comment 0 Shallon Severts Avatar of anonymous Anonymous 1m Shallon Severts $1.75+$0.65<$10 comment 0 isaias gutierrez

drew ditto

2020-10-13 18:41:15 UTC

1.75+0.65<10

Joe

2020-10-13 18:42:56 UTC

2020-10-13 18:45:37 UTC

Avatar of anonymous Anonymous 2m Joe comment 0 Maisie Paton Avatar of anonymous Anonymous 4m Maisie Paton $1.75+0.65x>_10 comment 0 Elijah Theos-King Avatar of anonymous Anonymous 10m Elijah Theos-King $1.75+0.65m comment 0 Hyrum Parry

10/14 Warm up

pathatn — 2020-10-14 17:33:30 UTC

Write an inequality of the question below.
If 5 times a number is increased by 4, the result is at least 19. Find the least possible number that satisfies theses conditions.

lewis kelley

2020-10-14 18:26:40 UTC

5×3+4≤19

1.75+.65m<10

2020-10-14 18:30:35 UTC

Valdez, Sei
\

Skylar Boehm

skylar_369197 — 2020-10-14 18:31:15 UTC

5x+4≥19

Special symbols (M2)

pathatn — 2020-10-14 18:31:31 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

Alexandra Beckham

alexandr_361016 — 2020-10-14 18:31:33 UTC

5x+4>_19

Teira Bell

2020-10-14 18:31:34 UTC

5x+4≥19

Marlon Monteagudo

2020-10-14 18:31:49 UTC


5x+4≥19

Brody Bulloch

2020-10-14 18:32:00 UTC

5x+4≥19

2020-10-14 18:32:05 UTC

Shallon Severts

2020-10-14 18:33:09 UTC

5x+4≥19

Isabella Zubrick

2020-10-14 18:33:18 UTC

5x+4≥19

Aaron Kison

2020-10-14 18:33:27 UTC

5x+4≥19

Nicholas Kotero

2020-10-14 18:33:27 UTC

5x+4≥19

2020-10-14 18:33:34 UTC

5x+4≥19

Dale Flores

2020-10-14 18:33:45 UTC

5x+4≥19

Aamara Dancel

2020-10-14 18:33:45 UTC

5x+4≥19

Adriel Dionisio

2020-10-14 18:33:46 UTC

5x+4≥19

Nicolas Melgarejo

2020-10-14 18:34:06 UTC

5x+4≥19

Elijah Theos-King

2020-10-14 18:34:42 UTC

5x+4≥19

5x+4≥9

2020-10-14 18:34:46 UTC

jackson davis

lily brooks

2020-10-14 18:35:28 UTC

5x+4≥19

kayla brunson

2020-10-14 18:35:36 UTC

1.75+0.65m < 10

Maisie Paton

2020-10-14 18:36:42 UTC

5x+4≥19

Ana Cardenas

2020-10-14 18:37:10 UTC

5x+4≤19

≥

Sadie Davis

sadie362248 — 2020-10-14 18:37:35 UTC

Maggie Brinkman

2020-10-14 18:37:43 UTC

5x+4≥19

Angelica Salazar

2020-10-14 18:38:27 UTC

5*3

≥19

Sydnee Roberts

2020-10-14 18:38:54 UTC

5x + 4 ≥ 19

Michelle Sampson

2020-10-14 18:38:55 UTC

5x+4≤19

isaias gutierrez

2020-10-14 18:39:34 UTC

5x + 4 >/= 19

Bebe Harris

2020-10-14 18:51:51 UTC

5x+4>/=19

10/15 Warm up

pathatn — 2020-10-15 15:25:06 UTC

Write an inequality of the question below.

You have just purchased a new cell phone. According to the terms of your agreement, you pay a flat fee of $6 per month, plus $0.04 per minute for calls. If you want your total bill to be no more than $10 for the month, how many minutes can you use?

Special symbols (M2)

pathatn — 2020-10-15 15:25:12 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

Lewis Kelley

2020-10-15 18:28:44 UTC

6+0.04x≤10

aaron kison

2020-10-15 18:29:48 UTC

6+0.04x≤10

Marlon Monteagudo

2020-10-15 18:30:36 UTC

6+.04x≤10

Dale Flores

2020-10-15 18:30:47 UTC

6+0.04x≤10

Austin May

2020-10-15 18:30:58 UTC

Brody Bulloch

2020-10-15 18:31:02 UTC

6 + 0.04x ≤ 10

6+$0.04

2020-10-15 18:31:32 UTC

Teira Bell

2020-10-15 18:31:49 UTC

6+0.04x≤10

Aamara Dancel

2020-10-15 18:31:57 UTC

6+0.04x≤10

Jackson Davis

2020-10-15 18:32:00 UTC

6+$0.04≤10

Adriel Dionisio

2020-10-15 18:32:37 UTC

6+0.04x≤10

Alexandra Beckham

alexandr_361016 — 2020-10-15 18:32:37 UTC

6+0.04x≤10

Hyrum Parry

2020-10-15 18:33:14 UTC

6+0.04

≤10

Maisie Paton

2020-10-15 18:33:42 UTC

6+0.04x≤10
x≤100

Ana Cardenas

2020-10-15 18:33:56 UTC

6+0.04m≤10

Skylar Boehm

skylar_369197 — 2020-10-15 18:34:07 UTC

6+0.04m≤10

2020-10-15 18:34:08 UTC

≤

Nicolas Melgarejo

2020-10-15 18:34:21 UTC

6m+0.04x≤10

Angelica Salazar

2020-10-15 18:34:24 UTC

6+.4x

≤10

Nicholas kotero

2020-10-15 18:34:28 UTC

brandy carson

2020-10-15 18:34:34 UTC

6+0.04x≤10

Elijah

2020-10-15 18:34:40 UTC

6+0.04x≤10

lulchloe — 2020-10-15 18:35:15 UTC

Bebe Harris

2020-10-15 18:35:25 UTC

6+0.04x≤10

Isabella Zubrick

2020-10-15 18:35:34 UTC

6+0.04x≤10
x≤100

Shallon Severts

2020-10-15 18:35:47 UTC

6 + 0.04x ≤ 10

Michelle Sampson

2020-10-15 18:35:54 UTC

6+0.04x≤10

Sydnee Roberts

sydnee_335768 — 2020-10-15 18:36:32 UTC

6 + 0.04x ≤10

Jackson Davis

2020-10-15 18:36:34 UTC

6+0.04m≤10

2020-10-15 18:36:39 UTC

6+$0.04≤10

Maggie Brinkman

2020-10-15 18:37:03 UTC

6+0.04x≤10

isaias gutierrez

2020-10-15 18:38:17 UTC

6 + 0.04x ≤ 10

Sei Valdez

2020-10-15 18:41:27 UTC

6+.04m≤ 10

lily brooks

2020-10-15 18:41:30 UTC

6+0.04x≤10

Sei Valdez

2020-10-15 18:49:00 UTC

6+0.4x≤10
x≤100

1) 1 ≤ z ≤ 10

pathatn — 2020-10-19 18:20:39 UTC

A: (1,10)

B: [1,10]

C: [1,10)

D: (1,10]

2) Write the interval notation.

pathatn — 2020-10-19 18:20:56 UTC

11 < y < 21

3) Write the interval notation.

pathatn — 2020-10-19 18:21:03 UTC

9 ≤ z < 19

4) 3 ≤ x ≤ 12

pathatn — 2020-10-19 18:21:21 UTC

(3,12)

5) 7 < x ≤ 15

pathatn — 2020-10-19 18:21:45 UTC

(7,15]

10/19 Warm up

pathatn — 2020-10-19 18:24:02 UTC

Please answer all 5 questions by add the comment below the each question.

Special symbols (M2)

pathatn — 2020-10-19 18:36:30 UTC

You can copy the below symbols to use in your Warm Up.

≤ ≥  ≮ ≯ ≠ ÷ √ ≈ ½ ∛ ∞

View more characters

10/20 Warm up

pathatn — 2020-10-19 21:54:38 UTC

Please expand the post if needed.

| |

Austin May

2020-10-20 18:28:26 UTC

I believe that the error is that they removed the absolute value lines before they put -3 to 5

Maisie Paton

2020-10-20 18:31:17 UTC

The error is that they took away the lines and forgot to add -3 to 5 before taking the lines around x and 1.

aaron kison

2020-10-20 18:31:24 UTC

the error is they removed the absolute value lines between x and -1 before putting -3 to 5.

Shallon Severts

2020-10-20 18:32:01 UTC

The error is that the student didnt put -3 to 5 before taking away the absolute value lines.

Dale Flores

2020-10-20 18:32:12 UTC

The error is that they forgot to add 3 to 5 before removing the absolute value symbols.

Brody Bulloch

2020-10-20 18:32:26 UTC

The error is that they didn't add -3 to 5 before they took away the lines.

Aamara Dancel

2020-10-20 18:33:02 UTC

I think the error is that they forgot to put -3 to 5 before they took the absolute value lines away.

Angelica Salazar

2020-10-20 18:34:02 UTC

For the second part, when they moved the -4, they should've added 4 to both sides so they should've gotten -1

Isabella Zubrick

2020-10-20 18:34:03 UTC

The error is that the first step this student did was remove the absolute value lines which made it so that this student did not solve it in the correct steps. The first step should have been adding 3 to 5 and then removing the absolute value lines. Sense there are absolute value lines the answers on the right are 8 and -8, this student would then add 1 to both 8 and -8 in order to get both answers.

Marlon Monteagudo

2020-10-20 18:34:04 UTC

The error in the solution is that the student removed the value lines from x-1 before adding in -3 and 5.

Teira Bell

2020-10-20 18:34:11 UTC

The error is they took away the absolute value lines around x and 1 before they added -3 and 5

Skylar Boehm

skylar_369197 — 2020-10-20 18:34:19 UTC

The error in their work is the student did not put -3 to 5 before taking away the absolute value lines.

Adriel Dionisio

2020-10-20 18:34:34 UTC

The error is that they did the absolute value lines first when they were supposed to get rid of the -3

Lily Brooks

2020-10-20 18:34:48 UTC

The error is that the student did not put -3 to 5 before they took away the absolute value lines

Maggie Brinkman

2020-10-20 18:35:36 UTC

The mistake was that they didn't do the steps in the right order, they took away the absolute lines before they added

Ana Cardenas

2020-10-20 18:35:51 UTC

the error is that they did the -3 to 5 first instead of taking away the absolute lines first.

Elijah Theos-King

2020-10-20 18:36:38 UTC

They forgot to add the absolute lines around the x--1.

Jackson Davis

2020-10-20 18:36:42 UTC

Sei Valdez

2020-10-20 18:37:01 UTC

The error was that they were supposed put the absolute lines around x-1 and make it x+ 1

Michelle Sampson

2020-10-20 18:37:09 UTC

The error that the student made is that the removed the absolute value lines.

the error is

lulchloe — 2020-10-20 18:37:13 UTC

alexandr_361016 — 2020-10-20 18:38:21 UTC

The error is that there is no absolute value signs. And when the student was solving the prolems she didn't subtract 3 on both sides.

Sadie Davis

sadie362248 — 2020-10-20 18:38:31 UTC

The error is that they didn't do -3 to the other side.

Jackson Davis (again)

2020-10-20 18:44:27 UTC

The person solving the problem got rid of the exxact value signs, throwing him off.

Sydnee Roberts

2020-10-20 18:45:31 UTC

The error is that they didn't add -3 and 5 before removing the absolute value lines.

lewis_368322 — 2020-10-20 18:45:42 UTC

the student took out the absolute value sign

Bebe Harris

2020-10-20 18:45:43 UTC

they didnt subtract three from the other side

10/21 Warm up

pathatn — 2020-10-21 17:29:57 UTC

4Ix-2I = 8x - 4
The student complete solving this equation and get x = -1 and 1 . Check both answers by substitution into the original equation to be sure that the solutions are not extraneous.

aaron kison

2020-10-21 18:30:52 UTC

4|(-1)-2| = 8(-1) - 4
4|-3| = -8-4
4|-3| = -12
12=-12 answer is false
x= -1 is not true

4|(1)-2|=8(1)-4
4|1-2|=8-4
4|-1|=4
4(1)=4
4=4 answer is true
x=1 is true

Marlon Monteagudo

2020-10-21 18:31:00 UTC

4|(-1)-2|=8(-1)-4
4|-1-2|=-8-4
4|-3|=-8-4
4|-3|=-12
12=-12
False

4|(1)-2|=8(1)
4|1-2|=8-4
4|-1|=8-4
4|-1|=4
4(1)=4
4=4
True

Dale Flores

2020-10-21 18:31:01 UTC

4|(-1)-2|=8(-1)-4
4|-1-2|=-8-4
4|-3|=-12
4(3)=-12
12=-12
false

4|(1)-2|=8(1)-4
4|1-2|=8-4
4|-1|=4
4(1)=4
4=4
true

Austin May

2020-10-21 18:31:09 UTC

: 4l(-1)-2l=8(-1)-4
4l(1)-2l=8(1)-4

4l-3l = -8-4
:12 = -12 Answer is false

4l(1)-2l=8(1)-4
4l1-2l=8-4
4l-1l=4
4(1)=4
4=4 This answer is true
Which means x = 1 is true.

Brody Bulloch

2020-10-21 18:31:16 UTC

4l(-1)-2l = 8(-1)-4
4l(1)-2l=8(1)-4

Elijah

2020-10-21 18:31:53 UTC

4|-1-2| = 8(-1) - 4

Shallon Severts

2020-10-21 18:32:12 UTC

4|(-1)-2|=8(-1)-4
4|-3|=-8-4
4|-3|=-12

Jackson Davis

2020-10-21 18:32:37 UTC

4 |(-1)-2|=8(-1)-4
4 |(1)-2|=8(1)-4

The answer is one

Maisie Paton

maisie_2267516 — 2020-10-21 18:32:46 UTC

1)|12|=-12
12=-12
2)|-4|=5
-4=5

Adriel Dionisio

2020-10-21 18:32:59 UTC

4|-1-2|=8(-1)-4
4|-3|=-8-4
4 x 3 = -12
12= -12
x = -1 is False

4|1-2|=8 x 1-4
4|1-2|=8-4
4|-1|=4
4 x 1 = 4
4=4
x= 1 is True

Aamara Dancel

2020-10-21 18:34:12 UTC

4 |x-2| = 8x - 4

4 |(-1) -2| = 8 (-1) -4
4 |-3| = -8 -4
4(3) = -12
12 = -12
False

4 |(1) -2| = 8 (1) -4
4 |-1| = 8 -4
4 |-1| = 4
4(1) = 4
4 = 4
True

Bebe Harris

2020-10-21 18:36:38 UTC

4 |-1-2| = 8x-4 x=1

Lily Brooks

2020-10-21 18:37:00 UTC

4|(-1)-2| = 8(-1) - 4
4|(1)-2| = 8 (-1) -4
|-12| = 3
-12 = 3

Isaias Gutierrez

2020-10-21 18:37:06 UTC

4 |x - 2| = 8x - 4 when x = -1
4 |-1 + -2| = -8 + - 4
4 |-3| = -12
12 = -12 extraneous

4 |x - 2| = 8x - 4 when x = 1
4 |1 - 2| = 8 - 4
4 |-1| = 4
4 = 4

x = 1 is the true answer in the problem

Ana Cardenas

2020-10-21 18:37:17 UTC

4lx-2I=8x-4
4(-1-2)=-8-4
4(-3)=-8-4
4(-3)=-12
12=-12 false

4I(1)-2I=8(1)-4
4I1-2I=8-4
4I-1I=4
4(1)
4=4 true

Sadie Davis

sadie362248 — 2020-10-21 18:37:38 UTC

Skylar Boehm

skylar_369197 — 2020-10-21 18:37:57 UTC

4 I(-1)-2I = 8 (-1) -4
4 I(1)-2I = 8 (-1) -4
I-12I = 3
-12 = 3

Teira Bell

2020-10-21 18:38:22 UTC

4|(-1)-2|=8(-1)-4
4|-1-2|=-8-4
4(-3)=-8-4
4(-3)=-12
12=-12
x=-1
false

4|1-2|=8 (1)-4
4|1-2|=8-4
4|-1|=4
4 x 1 = 4
4=4
x=1
true

Angelica Salazar

2020-10-21 18:39:29 UTC

4 l (-1)-2 l=8 (-1)-4 does not equal negative 1

4 l(1)-2l=8 (1)-4

drew ditto

2020-10-21 18:40:18 UTC

the answer is x=1

alexandr_361016 — 2020-10-21 18:41:19 UTC

Sydnee Roberts

2020-10-21 18:42:07 UTC

4|x-2| = 8x-4
4|(-1)-2|= 8 (-1) - 4
-12=3

drew ditto

2020-10-21 18:42:10 UTC

5x+4>19

lewis_368322 — 2020-10-21 18:42:21 UTC

4Ix-2I = 8x - 4

Maggie Brinkman

2020-10-21 18:44:13 UTC

4|x-2|=8x-4

4|-1-2|=8(-1)-4
4|-3|= -8 - 4
12=-12
false

4|1-2|=8(1)-4
4(1)=8-4
4=4
true

x=1

Sei Valdez

2020-10-21 18:44:48 UTC

4|-1-2|=8(-1)-4
4|3|=-8-4
12=-12 answer is false

4|1-2|=8(1)-4
4|1-2|=8-4
4|-1|=4
4(1)=4
4=4 the answer is true

Isabella Zubrick

2020-10-21 18:45:55 UTC

4 |x - 2| = 8x - 4
4 |-1 + -2| = -8 + - 4
4 |-3| = -12
12=-12 is false

4|1-2|=8(1)-4
4(1)=8-4
4=4 is true

4Ix-2I = 8x - 4

lewis_368322 — 2020-10-21 18:49:45 UTC

x=-1

10/26 Warm up

pathatn — 2020-10-26 18:14:25 UTC

3l3x + 2l = 9x
Find the value of x.

3|3x + 2| = 9x

austin_357412 — 2020-10-26 18:28:15 UTC

|3x+2|=3x
3x+2=3x
2=0 no solution

3|3x+2|=9x
3x+2=-3x
6x=-2
x=-1/3
There is no solution

aaron_359947 — 2020-10-26 18:29:49 UTC

3|3x + 2| = 9x
3x+2=3x
2=0 no solution

3|3x+2|=9x
3x+2=-3x
3x+3x=-2
6x=-2
x=-0.33 or -1/3
no solution

dale_357422 — 2020-10-26 18:30:34 UTC

3|3x+2|=9x
3x+2=3x
2=0
no solution
3|3x+2|=9x
3x+2=-3x
6x+2=0
6x=-2
x=-1/3

Elijah Theos-King

2020-10-26 18:32:45 UTC

3l3x + 2l = 9x
|3x+2|=3x
3x+

3|3x + 2| = 9x

marlon_1584844 — 2020-10-26 18:33:09 UTC

|3x+2|=3x
3x+2=3x
x=2
3|3x2|=9x
3x+2=-3x
no solution

maisie_2267516 — 2020-10-26 18:33:32 UTC

3|3x+2|=9x
3x+2=3x
2=x
3|3x+2|=9x
3x+2=-3x
x=-0.3
no solution

adriel_362134 — 2020-10-26 18:35:48 UTC

3|3x+2|=9x
|3x+2|=3x
3x+2=3x
2=0x
no soulution

3|3x+2|=9x
|3x+2|=3x
3x+2=-3x
2=-6x
x= -1/3

teira_367236 — 2020-10-26 18:35:48 UTC

3l3x+2l=9x
divide both sides by 3
l3x+2l=3x
Subtract 3x on both sides
2=0
No solution
3l3x+2l=-9x
divide both sides by 3
3x+2=3x
subtract both sides by 3x
2=-6x
divide both sides by -6
x=-0.33/-1/3

3|3x+2|=9x

isabella_360123 — 2020-10-26 18:35:49 UTC

divide 3 on both sides
|3x+2|=3x
minus 3 on both sides
2=0
or
3l3x+2l=-9x
divide 3 on both sides
3x+2=-3x
minus three on both sides
2=-6x
divide -6 on both sides
x=-1/3

3l3x + 2l = 9x

alexandr_361016 — 2020-10-26 18:36:30 UTC

divide both sides by 3
|3x+2|=3x
subtract 3x on both sides
2=0
or
3l3x + 2l = -9x
divide both sides by 3
|3x+2|=-3x
subtract both sides by 3x
2=-6x
divide both sides by -6
x=-0.33

3l3x+2l=9x

ana_1899554 — 2020-10-26 18:36:57 UTC

divide by 3 both sides
3x+2=3x
subtract 3x
2=0 no solution
3x+2=-3x
subtract 3x
2=-6x
divide by -6x
x=-0.33

3l3x + 2l = 9x

kayla142359 — 2020-10-26 18:37:36 UTC

3|3x + 2| = 9x

aamarak_2375863 — 2020-10-26 18:39:20 UTC

Divide both sides by 3
|3x + 2| = 3x
Subtract both sides by 3x
2 = 0 (No solution)
or
3|3x + 2| = -9x
Divide both sides by 3
3x + 2 = -3x
Subtract both sides by 3x
2 = -6x
Divide both sides by -6x
x = -0.3

3l 3x + 2l = 9x

brody_228149 — 2020-10-26 18:39:28 UTC

divide 3 on both sides
l3x+2l=3x
subtract 3 on both sides
2=0

sei362905 — 2020-10-26 18:40:39 UTC

3|3x+2|=9x
3x+2=3x
2=0

3x+2= -3x
6x=-2
x= -1/3

3 I3x+2I = 9x

skylar_369197 — 2020-10-26 18:41:29 UTC

Divide by three on both sides
I3x+2I = 3x
subtract three on both sides
2=0

3|3x+2|=9x

shallon_1952206 — 2020-10-26 18:41:56 UTC

3x+2=3x
x=2
3|3x+2|=9x
3x+2=-3x
no solution

Jackson Davis

2020-10-26 18:42:07 UTC

3|3x+2|=9x

lulchloe — 2020-10-26 18:45:20 UTC

3|3x + 2| = 9x

isaias_363676 — 2020-10-26 18:46:31 UTC

divide both sides by 3
3x + 2 = 3x
subtract 3x on both sides
2 = 0
and the second equation is
3x + 2 = -3x
subtract 3x from both sides
2 = -6x
-6x = 2
divide both sides by -6
x = -1/3

elijah_365537 — 2020-10-26 18:46:47 UTC

3l3x + 2l = 9x |3x+2|=3x 3x+

3|3x+2|=9x

maggie_358964 — 2020-10-26 18:49:03 UTC

3|3x+2|=9x
|3x+2|=3x

|3x+2|=3x
2/=0

|3x+2|=-3x
6x+2=0
6x=-2
x=-1/3

Sydnee Roberts

sydnee_335768 — 2020-10-26 18:54:55 UTC

3|3x + 2| = 9x. divide by 3
|3x + 2|= 3x. subtract 3x
2 = 0. no solution

|3x + 2|= -3x. subtract 3x
2 = -6x
-1/3= x

3x+2=3xx=23|3x+2|=9x3x+2=-3x

nicholas1956969 — 2020-10-26 19:18:07 UTC

10/27 Warm up

pathatn — 2020-10-27 18:13:12 UTC

|x+1|<3
Find the value of x.

|x+1|<3

austin_357412 — 2020-10-27 18:28:00 UTC

Condition 1
x + 1 - 1 < 3 - 1 : Subtract 1 from both sides
x < 2

Condition 2
x + 1 > -3
x + 1 - 1 > -3 - 1 : Subtract 1 from both sides
x > -4

X < 2 and x > -4

aaron_359947 — 2020-10-27 18:28:50 UTC

|x+1|<3
x+1<3 subtract 1 from both sides
x<2

|x+1|<-3
x+1<-3 subtract 1 from both sides
x>-4
x < 2, x > -4

Jackson Davis

2020-10-27 18:29:20 UTC

X = 1 or -1

sei362905 — 2020-10-27 18:30:36 UTC

x+1<3
x<2
and
x+1> -3
x> -4

dale_357422 — 2020-10-27 18:30:43 UTC

|x+1|<3
x+1<3
x<2
x+1>-3
x>-4

lx + 1l < 3

brody_228149 — 2020-10-27 18:30:54 UTC

x+1<3
x<2

x+1>-3
x>-4

|x+1| < 3

adriel_362134 — 2020-10-27 18:33:37 UTC

|x+1| < 3
x+1 < 3
x < 2

|x+1| < 3
x+1 < -3
x > -4

x < 2 and x > -4

maisie_2267516 — 2020-10-27 18:33:42 UTC

|x + 1| < 3

aamarak_2375863 — 2020-10-27 18:33:54 UTC

x + 1 < 3
x < 2

|x + 1| < -3
x + 1 < -3
x > -4

teira_367236 — 2020-10-27 18:35:39 UTC

lx+1l < 3
x+1 < 3
x < 2

lx+1l < -3
x+1 < -3
x>-4

shallon_1952206 — 2020-10-27 18:36:52 UTC

|x+1| < 3
x+1< 3
x < 2

|x+1| < -3
x < -4

x < 2 x < -4

Ix+1I < 3

skylar_369197 — 2020-10-27 18:36:53 UTC

x+1<3
x<2

Ix+1I < 3
x+1<-3
x>-4

|x+1| < 3 and |x+1| < -3

sydnee_335768 — 2020-10-27 18:37:09 UTC

subtract one on both problems on both sides
x< 2 x < -4

elijah_365537 — 2020-10-27 18:37:35 UTC

lx+1l < 3
-1 from both sides
x<2

isabella_360123 — 2020-10-27 18:38:25 UTC

|x+1|<3
x+1<3
x<2
or
|x+1|<3
x+1<-3
x>-4

lx+1l<3

ana_1899554 — 2020-10-27 18:38:26 UTC

subtract 1 both sides
x<2
lx+1l<-3
subtract 1 both sides
x>-4

lily brooks

2020-10-27 18:39:04 UTC

x+1<3 x<2 Ix+1I < 3

alexandr_361016 — 2020-10-27 18:39:26 UTC

|X+1|<3
subtract 1
X<3
And
|X+1|>-3
Subtract 1
X>-4

|x+1|<3

marlon_1584844 — 2020-10-27 18:40:32 UTC

x+1<3
x<2

|x+1|<3

bebe_354337 — 2020-10-27 18:41:26 UTC

minus 1
x<2
|x+1|<-3
x<-4

|x+1|<3

michelle_358980 — 2020-10-27 18:41:42 UTC

x+1<3
x<2
x+1>-3
x>-4

angelica375490 — 2020-10-27 18:42:02 UTC

lxlx+1l<3 l
x+1<3
x<2

|x+1|<3

maggie_358964 — 2020-10-27 18:43:46 UTC

|x+1|<3
x<2

|x+1|<-3
x<-4

|x + 1| < 3

isaias_363676 — 2020-10-27 18:47:38 UTC

x + 1 < 3
x < 2

x + 1< -3

lilyana_359965 — 2020-10-27 18:48:44 UTC

x+1<3
x<2

Ix+1I < 3

|x + 1| < 3x + 1 < 3x < 2x + 1< -3

lulchloe — 2020-10-27 18:52:40 UTC

Jackson Davis

jackson_362442 — 2020-10-27 18:53:11 UTC

X=1 or X=-1

10/28 Warm up

pathatn — 2020-10-28 18:12:49 UTC

|x-4|<3
Find the value of x.

aaron_359947 — 2020-10-28 18:29:29 UTC

|x-4|<3
-3-3+4<3
-3+41

dale_357422 — 2020-10-28 18:29:50 UTC

|x-4|<3
-3-3+41

|x-4|<3

austin_357412 — 2020-10-28 18:30:16 UTC

-3 < x - 4 < 3
-3 + 4 < x - 4 + 4 < 3 + 4
(Add 4 to all sides)
1 < x < 7

lx - 4l < 3

brody_228149 — 2020-10-28 18:31:02 UTC

-3-3+4<-4+4<3+4
1

|x-4|<3

bebe_354337 — 2020-10-28 18:33:23 UTC

-31

|x-4|<3

isabella_360123 — 2020-10-28 18:33:32 UTC

-3-3+4<-4+4<3+4
1< x <7

|

shallon_1952206 — 2020-10-28 18:33:35 UTC

|x - 4| < 3

aamarak_2375863 — 2020-10-28 18:33:37 UTC

-3 < x -4 < 3
-3 + 4 < x -4 + 4 < 3 + 4
1 < x < 7

Ix-4I<3

skylar_369197 — 2020-10-28 18:33:42 UTC

-3add four to all sides
answer: 1

|x-4|<3

elijah_365537 — 2020-10-28 18:33:48 UTC

-31 < x < 7

|x-4| < 3

adriel_362134 — 2020-10-28 18:33:59 UTC

-3 < x-4 < 3
-3+4 < x-4+4 < 3+4
1 < x < 7

|x-4|<3

alexandr_361016 — 2020-10-28 18:34:06 UTC

add 4 on both sides
x<7

lx-4l<3

ana_1899554 — 2020-10-28 18:35:28 UTC

-3-3+41

|x-4|< 3

sydnee_335768 — 2020-10-28 18:36:32 UTC

-3 < x-4 < 3
+4 +4 +4
1< x < 7

maisie_2267516 — 2020-10-28 18:36:43 UTC

lilyana_359965 — 2020-10-28 18:37:02 UTC

|x-4|< 3 -3 < x-4 < 3 +4 +4 +4 1< x < 7

lulchloe — 2020-10-28 18:37:45 UTC

|x-4| < 3

|x-4| <3

isaias_363676 — 2020-10-28 18:37:46 UTC

-3-3 + 4 < x -4 + 4< 3+4
1

|x-4|<3

maggie_358964 — 2020-10-28 18:38:36 UTC

|x-4|<3
- 3 < x - 4 < 3
+4 +4 +4
1

sei362905 — 2020-10-28 18:39:49 UTC

x-4<3
x<7
and
x-4>-3
x>1
1

lx-4l<3

angelica375490 — 2020-10-28 18:39:58 UTC

-31x>1 or x<7

teira_367236 — 2020-10-28 18:40:30 UTC

lx+4l<3
-3+4 +4 +4
1

|x-4| < 3

shallon_1952206 — 2020-10-28 18:43:30 UTC

-3 < x-4 < 3
+4 +4 +4
1 < x < 7

lewis_368322 — 2020-10-28 18:44:39 UTC

|x+4|<3
-3-3+41

10/28 Warm up

pathatn — 2020-10-29 17:13:30 UTC

|p + 2| + 4 < 10
Find the value of p.

|p+2|+4<10

aaron_359947 — 2020-10-29 18:29:07 UTC

p+2<6
p<4

p+2>-6
p>-8

p<4 and p>-8

|p + 2| + 4 < 10

austin_357412 — 2020-10-29 18:29:16 UTC

|p + 2| + 4 + -4 < 10 + -4
|p+2| < 6
p + 2 < 6
Condition 1
p + 2 - 2 < 6 - 2 (Subtract 2 from all sides)
P < 4
Condition 2
P + 2 > -6
P + 2 - 2 > -6 -2 (Subtract 2 from all sides)
P > -8
P < 4 and P > -8

lp + 2l + 4 < 10

brody_228149 — 2020-10-29 18:30:39 UTC

-4 -4
p + 2 < 6
-6 < p + 2 < 6

dale_357422 — 2020-10-29 18:30:41 UTC

|p+2|-4<10
|p+2|<6
-6

|p+2| + 4 <10

shallon_1952206 — 2020-10-29 18:31:33 UTC

subtract 4 on both sides
p + 2 < 6
-6 < p + 2 < 6
subtract 2 on both sides
-8 < p < 4

teira_367236 — 2020-10-29 18:34:48 UTC

|p+2|-4<10
|p+2|<6
-6-2 -2 -2
-8 < p < 4

|p+2|+4 <10

adriel_362134 — 2020-10-29 18:35:10 UTC

|p+2| < 6

Ip+2I-4<10

skylar_369197 — 2020-10-29 18:35:16 UTC

p+2=-6
subtract 2 on both sides
p<-8

condition 2
p+2=6
subtract 2 on both sides
p<4

|p + 2| + 4 < 10

aamarak_2375863 — 2020-10-29 18:36:46 UTC

|p + 2| < 6 (Subtract 4 on both sides)
-6 < p + 2 < 6 (Subtract 2 on both sides)

|p+2|-4<10 p+2=6

lulchloe — 2020-10-29 18:37:46 UTC

lp+2l+4<10

ana_1899554 — 2020-10-29 18:38:43 UTC

|p + 2| + 4 < 10

isaias_363676 — 2020-10-29 18:39:07 UTC

subtract 4 on both sides
p + 2 < 6
-6 < p + 2 < 6
subtract 2 on all sides
-8 < p < 4

|p+2| + 4 < 10

sydnee_335768 — 2020-10-29 18:39:24 UTC

p+2 < 6 p+2 > -6
subtract 2 on both sides
p < 4 p > -8

maisie_2267516 — 2020-10-29 18:39:45 UTC

|p+2|+4<10

jackson_362442 — 2020-10-29 18:41:34 UTC

-4 on both sides
p+2<6
-2 on both sides
p<4

sei362905 — 2020-10-29 18:42:00 UTC

p+2<6
p<4

p+2> -6
p>-8

4>p>-8

|p + 2| + 4 < 10

elijah_365537 — 2020-10-29 18:42:20 UTC

-4 on both sides
p+2<6
-6|p+2| < 6

|p+2|-4<10

isabella_360123 — 2020-10-29 18:43:10 UTC

p+2<6 or p+2<-6 +4
p<4 or p>-8

alexandr_361016 — 2020-10-29 19:11:55 UTC