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      <title>  Find the Beehive per. 7 by Mr. P</title>
      <link>https://padlet.com/pontiousl/9erlt6ffzx4f</link>
      <description>Explain you solution 2 different ways</description>
      <language>en-us</language>
      <pubDate>2016-12-14 18:29:52 UTC</pubDate>
      <lastBuildDate>2025-11-17 14:13:09 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title>Mr P</title>
         <author>pontiousl</author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143696557</link>
         <description><![CDATA[<div>Give a detailed explanation of how you arrived at your solution to the system (hive) using graphing &amp; either substitution or elimination</div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:49:54 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143696557</guid>
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      <item>
         <title>Corin and Courtney</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143696926</link>
         <description><![CDATA[<div>using substitution to solve our problem, we first changed each equation into slope intercept form. Then we took the equation y=1/2x - 1 and substituted it for y in the equation 2x+y=4 . You're new equation would be 2x+1/2x - 1 = 4. You combine the X's to get 2.5x-1=4, then add 1 to each side to get 2.5x=5. Next you divide 2.5 from 5 to get X=2. then replace X in the equation 2x+y=4 with 2 to get 2(2)+y=4 . You  get 4+y=4, subtract 4 and you get y=0. So your solution to the equation in (2, 0).  <br><br><br>using graphing to solve our problem, you first change each equation into slope intercept form. then take the equation Y=1/2x-1 and graph it by putting a point at -1 and going up 1 over 2 each time. then take the equation y=-2x+4 and put  point at positive 4 then go down 2 over 1. those two equation meet at (2, 0). </div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:51:00 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143696926</guid>
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         <title></title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143696930</link>
         <description><![CDATA[<div>Ashton and Karissa<br><br>First we had to change 2x+y=4 into y-intercept form which was y=-2x+4. Now scene they both equal y, make them equal each other ( 1/2x -1=-2x=4). Then solve for x to get 2. After that substitute 2 for x in ONE of the equations, solve for y. Then your answer is (2,0). When you graph, put equations&nbsp; in y-intercept form. Graph both equations and the solution is the only point the two lines intersect which is (2,0).  <br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:51:00 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143696930</guid>
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      <item>
         <title>Lena and Chloe</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143697217</link>
         <description><![CDATA[<div>First we had to change the equation to slope intercept, then put our first point on y line ad positive 4 then went down 2 over 1 to the right. Next we drew our line down. After we put our point at negative 1 and went up 1 over to the right 2 times and drew our line. Last we found the point that both of the lines met at and it was (2,0). For substitution, we plugged in 1/2x-1 into 2x+y=4. We got 2x+1/2x-1. We simplified it to 5/2x-1=4. Add 1 to 4 then to get x by itself, we multiplied 2/5 to both sides. 5 times 2/5 equals 2. Plug 2 back in for x to get y. 1/2(2)-1=0. 1-1 =0. Y is 0. (2,0). </div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:51:46 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143697217</guid>
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         <title>Catrina Gretchen and Breanna</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143697546</link>
         <description><![CDATA[<div>First, change the equation 2x+y=4 into slope-intercept form by subtracting 2x on both sides of the equaion. This will equal y=-2x+4.<br>Then, plot the y intercept of the first equation on the graph (4). Since the slope is -2, you have to go down 2 and over 1. After that, graph the second equation. Plot the y intercept on the same graph and go up 1 over 2. Both lines will intersect at (2,0). This is your solution. </div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:52:38 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143697546</guid>
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      <item>
         <title>Zayda and Jessica </title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143697774</link>
         <description><![CDATA[<div>We started by changing the equation into slope intercept form ( y= -2x + 4).&nbsp; We then graphed to get the solution (2,0). &nbsp;<br><br>Substitution : Use substitution to substitute, 1/2x into 2x+y=4. Solve. Then&nbsp; plug in answer for x. Solve, to get solution (2,0).<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:53:07 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143697774</guid>
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      <item>
         <title>Lijah $ Adryan </title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143697868</link>
         <description><![CDATA[<div>We first made the equations in slope intercept form. Because that made it easy to plot the points of the yInterxept&nbsp; whixh was&nbsp;4 and negative 1. The you follow the points of the slope and they meet @ (2,0)</div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:53:20 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143697868</guid>
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      <item>
         <title>Joshua Baucom, Thomas Coder, and Cope Brewer</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698269</link>
         <description><![CDATA[<div>I graphed it by using the 2 equations and putting one in slope intercept form, then just recorded the points</div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:54:26 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698269</guid>
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      <item>
         <title>mason and chance</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698342</link>
         <description><![CDATA[<div>first you had to put the equation in slope intercept form, them you graph it and find were the point intersect. </div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:54:40 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698342</guid>
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      <item>
         <title>Yliana and Nyla</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698548</link>
         <description><![CDATA[<div>First, we changed the equation 2x+y=4  into slope-intercept form, which changed into y=-2x+4. We then graphed the two equations, which intercepted on the point (2,0)</div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:55:24 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698548</guid>
      </item>
      <item>
         <title>Will ; Zach</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698563</link>
         <description><![CDATA[<div>Put the equation in slope intercept form.  Then you graph 4 on the y int. Then you graph the slope. Do the same for the other equation. (2,o)<br><br>-2x+4=1/2x-1<br>+2x___+2x___<br>4+2 1/2x-1<br>+1_______+1<br>2 1/2x=5<br>---------    ------<br>2 1/2     2 1/2<br>x=2<br>Plug it in</div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:55:26 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698563</guid>
      </item>
      <item>
         <title>Kobe and Trevin</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698574</link>
         <description><![CDATA[<div>Part D:<br>We first took the first bee´s path and started at y=4. Then, we went down 2, over to the right 1 until we hit the x-axis. Afterward, we took the second bee´s path and started at y=-1. Then, we went up 1, over to the right 2 until we hit the x-axis again. The bee hive was at (2 , 0), where the bees meet.<br><br>Part E:<br>We used substitution to prove our answer. First, we took 1/2x-1 and plugged it into 2x+y=4, the result was 2x+1/2x-1=4. If you evaluate the equation, the answer will be x=2. Then, we took x=2 and plugged it back into y=1/2x-1, the result was y=1/2(2)-1. If you evaluate the equation, the answer will be y=0. This proves that the solution to the system is (2 , 0)</div>]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:55:30 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698574</guid>
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      <item>
         <title>      Carl y Cody              using graphing the first step we took was to change the both the equations to the same form. So, we changed both problems to slope-intercept form. for example the equation 2x+y=4 turns into y=-2x+4. Then you put the first point at -1 and then you go up one over two and put the next point and keep going up one over one. For the next line you put the first point at 4 and then you go up 1 over 2</title>
         <author></author>
         <link>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698645</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2016-12-14 18:55:43 UTC</pubDate>
         <guid>https://padlet.com/pontiousl/9erlt6ffzx4f/wish/143698645</guid>
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