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      <title>CHEMISTRY EC015 by YUSMAWATI BINTI YUSOFF BM</title>
      <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm</link>
      <description>KAT1/T2
AKT3/T4</description>
      <language>en-us</language>
      <pubDate>2021-08-02 15:09:39 UTC</pubDate>
      <lastBuildDate>2025-09-25 10:42:59 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title></title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1666843989</link>
         <description><![CDATA[<div>Soalan objektif, jom jwb sama2</div>]]></description>
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         <pubDate>2021-08-02 15:14:35 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1666843989</guid>
      </item>
      <item>
         <title>Nota Kuliah (Live) 1.1 &amp; 1.2</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1666861315</link>
         <description><![CDATA[<div>Nota kuliah 29/7/2021</div>]]></description>
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         <pubDate>2021-08-02 15:35:17 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1666861315</guid>
      </item>
      <item>
         <title>Kuliah Live 29/7/2021</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1666864938</link>
         <description><![CDATA[<div>Topic: Matter<br>Subtopic 1.1 &amp; 1.2</div>]]></description>
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         <pubDate>2021-08-02 15:40:01 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1666864938</guid>
      </item>
      <item>
         <title>Answer for Tutorial 1.2 (1-6)</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1668724058</link>
         <description><![CDATA[<div>1 (a)&nbsp; &nbsp; &nbsp; &nbsp; C<sub>12</sub>H<sub>22</sub>O<sub>11</sub>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 12(12.0) +22(1.0) + 11(16.0) = <em>342</em></div><div>(b)&nbsp; &nbsp; &nbsp; &nbsp; Mg<sub>3</sub>(PO<sub>4</sub>)<sub>2</sub>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 3(24.3) + 2[31.0 + 4(16.0)] = <em>262.9</em></div><div>(c)&nbsp; &nbsp; &nbsp; &nbsp; Ca<sub>3</sub>(PO<sub>4</sub>)<sub>2</sub>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 3(40.1) + 2[31.0 + 4(16.0)] = <em>310.3</em></div><div>(d)&nbsp; &nbsp; &nbsp; &nbsp; (NH­<sub>4</sub>)<sub>2</sub>SO<sub>4</sub>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2[14.0 + 4(1.0)] + 32.07 + 4(16.0) = <em>132.1</em></div><div>(e)&nbsp; &nbsp; &nbsp; &nbsp; CuSO<sub>4</sub>.5H<sub>2</sub>O&nbsp; &nbsp; &nbsp;= 63.6 + 32.07 + 4(16.0) + 5[2(1.0) + 16.0] = <em>249.7<br><br>2. 2.324´10</em><em><sup>-23</sup></em><em> g<br><br>3.(a) 1.260 mol Al(OH)</em><em><sub>3<br>(b) </sub></em><em>64.452 mol Ni</em> <br>(c) <em>4.153´10</em><em><sup>-1</sup></em><em> mol C</em><em><sub>2</sub></em><em>H</em><em><sub>6</sub></em><em>O</em> <br>(d)<em>3.00 ´ 10</em><em><sup>-2</sup></em><em> mol O</em><em><sub>2</sub></em> <br>(e) <em>0.250 mol H</em><em><sub>2</sub></em><em>SO</em><em><sub>4<br>(f) </sub></em><em>0.536 mol N</em><em><sub>2</sub></em>&nbsp;<br><br>4. (a)&nbsp;<strong><em>1.36 x10</em></strong><strong><em><sup>22</sup></em></strong><strong><em>&nbsp; &nbsp;atoms</em></strong>&nbsp;<br>(b)&nbsp;<strong><em>2.79 x10</em></strong><strong><em><sup>22</sup></em></strong><strong><em>&nbsp; &nbsp;atoms<br>(c) 3.956 x10</em></strong><strong><em><sup>24</sup></em></strong><strong><em>&nbsp; &nbsp;molecules</em></strong></div><div>&nbsp;(d)&nbsp;<strong><em>3.956 x10</em></strong><strong><em><sup>24</sup></em></strong><strong><em>&nbsp; &nbsp;molecules</em></strong></div><div>&nbsp;(e) <strong><em>2.68 x 10</em></strong><strong><em><sup>25&nbsp; </sup></em></strong><strong><em>H atoms</em></strong>&nbsp;<br>(f)<strong><em>6.02´10</em></strong><strong><em><sup>23</sup></em></strong><strong><em> atoms C<br><br>5. (a) 323.2 g mol</em></strong><strong><em><sup>–1</sup></em></strong>&nbsp;<br>(b)&nbsp;<strong><em>3.34 ´10</em></strong><strong><em><sup>-3</sup></em></strong><strong><em> mol<br>(c) 2.01 ´10</em></strong><strong><em><sup>21</sup></em></strong><strong><em> molecules</em></strong></div><div>(d)&nbsp;<strong><em>4.02 ´ 10</em></strong><strong><em><sup>22</sup></em></strong><strong><em> H atoms</em></strong></div><div><strong>&nbsp;(e)&nbsp;</strong><strong><em>0.321 g C<br><br>6. (a) 7.95 L<br>(b) 16.35 g<br>(c) 13.81 L<br></em></strong><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2021-08-04 08:46:17 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1668724058</guid>
      </item>
      <item>
         <title>Answer for Tutorial 1.2 (7-17)</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1668730667</link>
         <description><![CDATA[<div>7. (a)&nbsp;<strong><em>3.0 x 10</em></strong><strong><em><sup>-3</sup></em></strong><strong><em> mol NH</em></strong><strong><em><sub>3</sub></em></strong>&nbsp;<br>(b)&nbsp;<strong><em>2.258 ´ 10</em></strong><strong><em><sup>21</sup></em></strong><strong><em> O</em></strong><strong><em><sub>2</sub></em></strong><strong><em> molecule</em></strong></div><div>&nbsp;(c)&nbsp;<strong><em>0.090 g<br><br>8. (a) 4.4 g</em></strong>&nbsp;<br>(b) (i)&nbsp;<strong><em>0.05 mol P</em></strong><strong><em><sub>4</sub></em></strong><strong><em>O</em></strong><strong><em><sub>10</sub></em></strong>&nbsp;<br>(ii)&nbsp;<strong><em>14.2 g<br>(iii) 1.12 L</em></strong>&nbsp;<br>(iv)<strong><em>1.20 L</em></strong>&nbsp;<br><br>9 (a)&nbsp;<strong><em>8.04 x 10</em></strong><strong><em><sup>-4</sup></em></strong><strong><em> mol NO</em></strong><sub>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;<br>(b)&nbsp;</sub><strong><em>0.52%<br><br>10. (a)&nbsp;</em></strong>Empirical formula &nbsp; -&nbsp; &nbsp; &nbsp; formula that shows the <strong>simplest ratio</strong> of atoms of different elements&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; present in a&nbsp; molecule</div><div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Molecular formula&nbsp; &nbsp; -&nbsp; &nbsp; &nbsp;formula that shows the <strong>actual number</strong> of atoms of different elements present in a molecule<br><br>(b)&nbsp;<strong><em>C</em></strong><strong><em><sub>3</sub></em></strong><strong><em>H</em></strong><strong><em><sub>8</sub></em></strong><strong><em>N</em></strong>&nbsp;<br>(c)&nbsp;<strong><em>C</em></strong><strong><em><sub>6</sub></em></strong><strong><em>H</em></strong><strong><em><sub>16</sub></em></strong><strong><em>N</em></strong><strong><em><sub>2<br><br>11.&nbsp;</sub></em></strong><strong>empirical formula: </strong><strong><em>C</em></strong><strong><em><sub>4</sub></em></strong><strong><em>H</em></strong><strong><em><sub>5</sub></em></strong><strong><em>ON</em></strong><strong><em><sub>2</sub></em></strong>&nbsp;<br><strong>Molecular formula&nbsp; =&nbsp; </strong><strong><em>C</em></strong><strong><em><sub>8</sub></em></strong><strong><em>H</em></strong><strong><em><sub>10</sub></em></strong><strong><em>O</em></strong><strong><em><sub>2</sub></em></strong><strong><em>N</em></strong><strong><em><sub>4</sub></em></strong>&nbsp;<br><br>12. b(i)&nbsp;<strong><em>172.4 ml</em></strong> <br>(ii) <strong><em>0.72M</em></strong> <br>(iii) <strong><em>0.73 m</em></strong>&nbsp;<br><br>13.&nbsp;<strong><em>0.891 M</em></strong><em> @ </em><strong><em>mol L</em></strong><strong><em><sup>–1</sup></em></strong><em> @ </em><strong><em>mol dm</em></strong><strong><em><sup>-3<br><br>14. (a)&nbsp;</sup></em></strong><strong><em>0.3 m&nbsp; &nbsp; <br>(b) 0.3 M</em></strong>&nbsp;<br>(c)&nbsp;<strong><em>0.00537<br>(d) 1.723 %</em></strong> <br><br>15. (a) <strong><em>0.159</em></strong>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<br>(b)&nbsp;<strong><em>29.58%</em></strong>&nbsp;<br>(c)&nbsp;<strong><em>9.83 M</em></strong></div><div><strong>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<br>16 (a)&nbsp;</strong><strong><em>27.75 M</em></strong>&nbsp;<br>(b)&nbsp;<strong><em>2.882 ´ 10</em></strong><strong><em><sup>–3</sup></em></strong><strong><em> L</em></strong><em> @ </em><strong><em>2.882 mL</em></strong>&nbsp;<br><br>17. (a)<strong>0.10 M</strong>&nbsp;<br>(b)&nbsp;<strong><em>0.00125 mol H</em></strong><strong><em><sub>2</sub></em></strong><strong><em>SO</em></strong><strong><em><sub>4</sub></em></strong>&nbsp;</div>]]></description>
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         <pubDate>2021-08-04 08:57:29 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1668730667</guid>
      </item>
      <item>
         <title>Pre lab Experiment 1</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1668840319</link>
         <description><![CDATA[<div>Boleh jawab soalan Pre Lab ya..nk bcg esok</div>]]></description>
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         <pubDate>2021-08-04 12:25:38 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1668840319</guid>
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      <item>
         <title>Quiz 1</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1668882901</link>
         <description><![CDATA[<div>1.1 Atoms and Molecules<br>1.2 MOle Concept</div>]]></description>
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         <pubDate>2021-08-04 13:13:48 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1668882901</guid>
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      <item>
         <title>Kuliah Live 5/8/2021</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1669572190</link>
         <description><![CDATA[<div>1.3 Stoichiometry</div>]]></description>
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         <pubDate>2021-08-05 03:33:58 UTC</pubDate>
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      <item>
         <title>Tutorial 1.2 no 15</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1673853921</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-10 07:32:12 UTC</pubDate>
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         <title>Tutorial 1.2 No 11</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1673854629</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-10 07:33:09 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1673854629</guid>
      </item>
      <item>
         <title>Template Report Experiment 1</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1673855366</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-10 07:34:06 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1673855366</guid>
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      <item>
         <title>Video Amali Exp 1</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1673864147</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-10 07:46:11 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1673864147</guid>
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         <title>Tutorial 1.2 No 12</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674252706</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-10 15:23:56 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674252706</guid>
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         <title>Tutorial 1.2 No 16</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674255105</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-10 15:25:45 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674255105</guid>
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         <title>Tutorial 1.2 No 17</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674257600</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://youtu.be/3y-JN3tMeu0" />
         <pubDate>2021-08-10 15:27:31 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674257600</guid>
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      <item>
         <title>Tutorial 1.2 No 14</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674259356</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://youtu.be/6xdeQEaf_gQ" />
         <pubDate>2021-08-10 15:28:46 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674259356</guid>
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      <item>
         <title>Tutorial 1.2 No 13</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674260316</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-10 15:29:28 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1674260316</guid>
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      <item>
         <title>Tutorial 1.3 No 1-2</title>
         <author></author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1675666422</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://youtu.be/jFLsJvq0KlA" />
         <pubDate>2021-08-11 16:00:30 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1675666422</guid>
      </item>
      <item>
         <title>Tutorial 1.3 No 3-9</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1679956672</link>
         <description><![CDATA[<div>3. 8.46<br>4. 36.0<br>5. d) 66.7<br>e) 90.62%<br>6. b) 0.09 g<br>c) 0.067 M<br>d) 0.00262<br>e) 57.14%<br>7 b) (iii) 0.05045 mol<br>8 b) 40.23%<br>9 c) 0.0110 M</div>]]></description>
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         <pubDate>2021-08-16 05:02:05 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1679956672</guid>
      </item>
      <item>
         <title>Tutorial 2.1 </title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1681841064</link>
         <description><![CDATA[<div>4(b) 7.317 x 10<sup>14<br></sup>5 b) i)&nbsp;<strong>97.23 nm</strong> and&nbsp;<strong>= 3.085´10</strong><strong><sup>15</sup></strong><strong> s</strong><strong><sup>-1 <br>ii) </sup></strong><strong>= 1282 nm and&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2.340´10</strong><strong><sup>14 </sup></strong><strong>s</strong><strong><sup>-1<br>6 a) red </sup></strong><strong>= 3.031´10</strong><strong><sup>-19</sup></strong><strong> J @ 3.031´10</strong><strong><sup>-22</sup></strong><strong> kJ</strong></div><div><strong>&nbsp;<br>green= 4.09´10</strong><strong><sup>-19</sup></strong><strong> J @ 4.09´10</strong><strong><sup>-22</sup></strong><strong> kJ</strong> <br><br>blue&nbsp; <strong>= 4.581´10</strong><strong><sup>-19</sup></strong><strong> J @ 4.581´10</strong><strong><sup>-22</sup></strong><strong> kJ</strong> <br>b) red <strong>n</strong><strong><sub>2</sub></strong><strong> =3</strong> <br>green&nbsp; &nbsp; &nbsp; &nbsp;<strong>n</strong><strong><sub>2</sub></strong><strong> =4</strong> <br>blue&nbsp; &nbsp; &nbsp; &nbsp;<strong>n</strong><strong><sub>2</sub></strong><strong> =5</strong>&nbsp;<br><br>7.energy&nbsp;<strong>= - 4.578´10</strong><strong><sup>-19</sup></strong><strong> J @ 4.578´10</strong><strong><sup>-22</sup></strong><strong> kJ<br>wavelength = 4.3447´10</strong><strong><sup>-7</sup></strong><strong> m @ 434.5 nm</strong> <br><br>8. wavelength&nbsp; &nbsp; &nbsp; &nbsp; <strong>= 6.563´10</strong><strong><sup>-7</sup></strong><strong> m @ 656.3 nm&nbsp;<br><br>frequency&nbsp;</strong>&nbsp; &nbsp; &nbsp; &nbsp;<strong>= 4.571´10</strong><strong><sup>14</sup></strong><strong> s</strong><strong><sup>-1<br><br>9. wavelength&nbsp;</sup></strong><strong>= 5.45´10</strong><strong><sup>-8</sup></strong><strong> m @ 54.5 nm</strong> <br>energy = <strong>2195.558 kJ mol</strong><strong><sup>-1</sup></strong>&nbsp;<br><br>10.&nbsp;<strong>&nbsp;= 1312.360 kJ mol</strong><strong><sup>-1</sup></strong>&nbsp;</div>]]></description>
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         <pubDate>2021-08-17 08:21:49 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1681841064</guid>
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      <item>
         <title>Kuliah Live 12/8/2021</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1681845854</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-17 08:26:26 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1681845854</guid>
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      <item>
         <title>Kuliah Live 19/8/2021</title>
         <author>bm2369</author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1688053942</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-08-20 15:06:30 UTC</pubDate>
         <guid>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1688053942</guid>
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      <item>
         <title>TASK GROUP 2</title>
         <author></author>
         <link>https://padlet.com/bm2369/9eib1nzzkrxjpdrm/wish/1735541738</link>
         <description><![CDATA[]]></description>
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         <pubDate>2021-09-13 09:27:31 UTC</pubDate>
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         <pubDate>2021-09-23 14:26:16 UTC</pubDate>
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