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      <title>FIT2014 @ W9 - F2 by Wong Kok Sheik</title>
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      <language>en-us</language>
      <pubDate>2023-09-19 04:30:23 UTC</pubDate>
      <lastBuildDate>2023-09-19 05:59:48 UTC</lastBuildDate>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710155893</link>
         <description><![CDATA[<div>whats the difference between M and M'<br><br></div>]]></description>
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         <pubDate>2023-09-19 05:26:19 UTC</pubDate>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710157534</link>
         <description><![CDATA[<div><br>So we can say that M halts on input M if and only if M' halts on any input ? and with this we can say that halt for any input is undecidable ?</div>]]></description>
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         <pubDate>2023-09-19 05:27:29 UTC</pubDate>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710167615</link>
         <description><![CDATA[<div>I don't understand how running M on M suddenly proves Half for Input Zero</div>]]></description>
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         <pubDate>2023-09-19 05:35:19 UTC</pubDate>
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         <title>So when M be the input for itself for a HP or a DHP, for every no input it is possible for the Turing Machine to loop making it undecidable. Is my logic right?</title>
         <author></author>
         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710169539</link>
         <description><![CDATA[<div><br>In the case of proving HFIZ, does the mapping of DHP to HFIZ mean we are trying to run HFIZ with DHP as the input?</div>]]></description>
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         <pubDate>2023-09-19 05:36:49 UTC</pubDate>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710176043</link>
         <description><![CDATA[<div>Isn't the process of mapping the inputs this way just assuming that inputs of HFIZ will lead to the same result as DHP instead of actually proving it?</div>]]></description>
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         <pubDate>2023-09-19 05:42:09 UTC</pubDate>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710177029</link>
         <description><![CDATA[<div>So the input for DHP, M which is a TM is modified to M' to prove HFIZ is undecidable </div>]]></description>
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         <pubDate>2023-09-19 05:43:02 UTC</pubDate>
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         <title></title>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710182124</link>
         <description><![CDATA[<div>Is it because we don know if M’ will halts on any input so its undecidable</div>]]></description>
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         <pubDate>2023-09-19 05:47:18 UTC</pubDate>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710193671</link>
         <description><![CDATA[<div>Can you explain again why the first one is undecidable? (Question: Input turing machine P and string x, does P accept x )</div>]]></description>
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         <pubDate>2023-09-19 05:56:34 UTC</pubDate>
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         <title></title>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710194242</link>
         <description><![CDATA[<div>Can you explain why the question "does P accept X " is undecidable ? is it because we dont know if it can halt or not because there might be a loop in the middle ?</div>]]></description>
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         <pubDate>2023-09-19 05:57:02 UTC</pubDate>
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         <link>https://padlet.com/wongkoksheik/9drvlf7y6yg2ws1n/wish/2710195588</link>
         <description><![CDATA[<div>Why does switching accept and reject gives a sometimes halt<br><br>So for this does this refer to the complement </div>]]></description>
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         <pubDate>2023-09-19 05:57:58 UTC</pubDate>
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