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      <title>Triángulos - Ap-04 - Medición de Alturas con un Hipsómetro by profemate</title>
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      <pubDate>2016-08-18 15:42:54 UTC</pubDate>
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         <author>profemate</author>
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         <description><![CDATA[<ul><li><a href="http://profemate.weebly.com/5-triangulos.html#hipsometro"><strong>REGRESAR</strong></a></li></ul>]]></description>
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         <pubDate>2016-08-15 21:51:42 UTC</pubDate>
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         <title>Hallar la altura de un objeto cuando su sombra no se puede medir o es de noche.</title>
         <author>profemate</author>
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         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp;<br>&nbsp; &nbsp; &nbsp;Se trata de medir la altura de un obieto (edificio en este ejemplo) en condiciones tales que no se puede medir su sombra; por ejemplo de noche.<br><br>&nbsp; &nbsp; &nbsp;Para ello debemos usar el hipsómetro que aprendimos a construir en <a href="https://padlet.com/profemate/ziub7cdua8b4"><strong><em>Hipsómetro-Construcción</em></strong></a>.<br><br>&nbsp; &nbsp; &nbsp;Nos colocamos a una distancia <strong><em>d</em></strong> metros del edificio y allí dirigimos la visual verticálmente hacia la parte superior del edificio. Anotamos la medida <strong><em>m</em></strong> <br><br>&nbsp; &nbsp; &nbsp;Los triángulos <strong><em>ACB</em></strong> y <strong><em>A'C'B' </em></strong>son semejantes debido a tener dos ángulos iguales: uno recto y otro, vértices <strong><em>A</em></strong> y <strong><em>A'</em></strong>, formado por lineas perpendiculares entre sí.<br><br>&nbsp; &nbsp; &nbsp;Debido a esta semejanza se puede establecer la siguiente relación entre lados homólogos:<br><br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; <strong>H - h&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; d<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ──── = ───<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; m&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; r</strong><br><br>De donde, despejando <strong>H</strong>:<br><br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;<strong>dm<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; H = ──── + h<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; r</strong><br><br>Siendo <strong>h</strong> la altura del ojo del observador respecto al piso.</div>]]></description>
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         <pubDate>2016-08-16 16:28:13 UTC</pubDate>
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         <pubDate>2016-08-18 22:52:41 UTC</pubDate>
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