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      <title>МЕТОДЫ РЕШЕНИЯ КВАДРАТНЫХ УРАВНЕНИЙ by Irina Tankman</title>
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      <description>Made with a curious mind</description>
      <language>en-us</language>
      <pubDate>2017-11-07 22:05:03 UTC</pubDate>
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         <title>a+b+c=0</title>
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         <description><![CDATA[<div>1)x= 1<br>2)x=c:a</div>]]></description>
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         <pubDate>2017-11-08 08:15:42 UTC</pubDate>
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         <title>a+b=c</title>
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         <description><![CDATA[<div>1)x1=-1<br>2)x2=-c:a<br><br></div>]]></description>
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         <pubDate>2017-11-08 08:16:49 UTC</pubDate>
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         <title>D=b2 - 4ac</title>
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         <description><![CDATA[<div>1)Если D&gt;0, то уравнение имеет 2 корня <figure class="attachment attachment--preview"><img src="http://www.egesdam.ru/F221/004.gif" width="203" height="64"><figcaption class="attachment__caption"></figcaption></figure>2)Если D&lt;0, то x принадлежит пустому множеству<br>3)Если D=0,то уравнение имеет 1 корень<br>x=-b:2<br> </div>]]></description>
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         <pubDate>2017-11-08 08:18:03 UTC</pubDate>
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         <title>Т.Виета</title>
         <author>ojadan</author>
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         <description><![CDATA[<div>x*x+px+q<br>X1+X2=-p<br>x1*x2=q<figure class="attachment attachment--preview"><img src="https://upload.wikimedia.org/wikipedia/commons/thumb/6/6a/Francois_Viete.jpeg/267px-Francois_Viete.jpeg" width="267" height="363"><figcaption class="attachment__caption"></figcaption></figure></div>]]></description>
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         <pubDate>2017-11-08 08:21:09 UTC</pubDate>
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         <title>Кто в группе?</title>
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         <pubDate>2017-11-08 08:22:31 UTC</pubDate>
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         <title>d/4, b-четн.</title>
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         <description><![CDATA[<div>d/4= (b/2)(b/2) - ac<br>x1,2= (- (b/2)+/ -  √ d/4)/a</div>]]></description>
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         <pubDate>2017-11-08 08:22:49 UTC</pubDate>
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         <title>Куватова</title>
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         <description><![CDATA[<div>Ояла<br>Ленская<br>Корниенко<br><br></div>]]></description>
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         <pubDate>2017-11-08 08:24:38 UTC</pubDate>
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         <title>d/4, a=1,b-четн.</title>
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         <description><![CDATA[<div>d/4=(b/2)(b/2)-c<br>x1,2=-(b/2)+/-d/4</div>]]></description>
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         <pubDate>2017-11-08 08:29:48 UTC</pubDate>
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         <title>вынесение общего множителя за скобку, с=0</title>
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         <description><![CDATA[<div>ax*x+bx=0<br>x(ax+b)=0</div>]]></description>
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         <pubDate>2017-11-08 08:35:34 UTC</pubDate>
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         <title>Метод султанова</title>
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         <description><![CDATA[<div>x*x+2x-3=0<br>(x-1)(x+3)=0</div>]]></description>
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         <pubDate>2017-11-09 08:09:14 UTC</pubDate>
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         <title>x*ax+c=0</title>
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         <description><![CDATA[<div>x*x=-c:a</div>]]></description>
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         <pubDate>2017-11-09 08:13:09 UTC</pubDate>
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         <description><![CDATA[<div>работает при a целых положительных</div>]]></description>
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         <pubDate>2017-11-09 17:55:11 UTC</pubDate>
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         <pubDate>2017-11-09 18:01:21 UTC</pubDate>
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