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      <title>Probability Problem Paragraph by skyler laney</title>
      <link>https://padlet.com/skylerlaney/7pzooeblt91fl5c0</link>
      <description>Block 3 Discrete Math</description>
      <language>en-us</language>
      <pubDate>2021-04-19 15:55:17 UTC</pubDate>
      <lastBuildDate>2021-04-19 16:21:01 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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      <item>
         <title>Jasmine, Wayan, Carlton</title>
         <author></author>
         <link>https://padlet.com/skylerlaney/7pzooeblt91fl5c0/wish/1433830631</link>
         <description><![CDATA[<div>Problem 1 is asking about the probability of a student guessing the correct answer on a multiple choice question on a test. Since each question on the test has 6 answer choice to choose from, we put the 6 in the denominator position in the fraction. The question only has 1 correct answer, we put 1 in the numerator position. It can't be simplified further, so we were left with 1/6.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-04-19 16:02:57 UTC</pubDate>
         <guid>https://padlet.com/skylerlaney/7pzooeblt91fl5c0/wish/1433830631</guid>
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      <item>
         <title>Hunter, DeQuan, Eusebio </title>
         <author></author>
         <link>https://padlet.com/skylerlaney/7pzooeblt91fl5c0/wish/1433836967</link>
         <description><![CDATA[<div>So our group had decided to choice question 4, The question is to select a random card from a deck of cards, then determine the probability that the card was a 5. We knew that there was four suites so there was four 5's and there was 52 cards in the deck. After that we simplify 4/52 to 1/13 and that would be our answer.  </div>]]></description>
         <enclosure url="" />
         <pubDate>2021-04-19 16:04:06 UTC</pubDate>
         <guid>https://padlet.com/skylerlaney/7pzooeblt91fl5c0/wish/1433836967</guid>
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      <item>
         <title>Kaliyah, Haylee, Jamari</title>
         <author></author>
         <link>https://padlet.com/skylerlaney/7pzooeblt91fl5c0/wish/1433837826</link>
         <description><![CDATA[<div>To solve problem number 1 part A, you have to put the total amount of answer choices for the denominator which is 6. Your next step is to find your numerator which will end up being 1 because only one of the answers is correct. For problem 1 part B since you have to eliminate one of the answer your denominator changes to 5. Your numerator is 1 because you can only get 1 answer correct.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-04-19 16:04:16 UTC</pubDate>
         <guid>https://padlet.com/skylerlaney/7pzooeblt91fl5c0/wish/1433837826</guid>
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      <item>
         <title>Eddie, Kimathi, Maurisio</title>
         <author>edwardgaston7</author>
         <link>https://padlet.com/skylerlaney/7pzooeblt91fl5c0/wish/1433842951</link>
         <description><![CDATA[<div>Problem 4 ask you to determine the probability that the card selected is a 5. there are 52 cards in a deck excluding the jokers. There are 4 types of 13 cards which are called the suits, Because of this we can safely say there are 4 5's in the deck. This means there is a 4 out of a 52 chance we pick a card that is a 5. We can simplify this down to 1 out of 13.</div>]]></description>
         <enclosure url="" />
         <pubDate>2021-04-19 16:05:09 UTC</pubDate>
         <guid>https://padlet.com/skylerlaney/7pzooeblt91fl5c0/wish/1433842951</guid>
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