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      <title>CONCEPT FORMATION (GROUP 3) by Christy Namae Bellingan</title>
      <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93</link>
      <description>In this activity, you will form the concept of solving quadratic equations by the SQUARE ROOT PROPERTY, the ZERO PRODUCT PRINCIPLE, and by COMPLETING THE SQUARE.</description>
      <language>en-us</language>
      <pubDate>2022-09-13 09:08:32 UTC</pubDate>
      <lastBuildDate>2022-09-18 14:00:24 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <url>https://padlet.net/icons/png/1f3dd.png</url>
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         <title>Steps on Solving Quadratic Equations by the Zero Product Property </title>
         <author>cgmaglipac</author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2294284870</link>
         <description><![CDATA[<div><em>Factoring Method: <br>these are the steps in solving quadratic equations by factoring:<br></em><strong>1.) Write the equation in the form </strong><strong><mark>ax</mark></strong><strong><mark><sup>2</sup></mark></strong><strong><mark> + bx + c = 0 </mark></strong><strong><br>2.) Factor the left-hand side of the equation.<br>3.) Apply the zero product theorem </strong><em><mark>(set each factor equal to zero).</mark></em><strong><br>4.) Solve the equations&nbsp;<br>5.) Check the results in the original equation.</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-13 13:26:43 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2294284870</guid>
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      <item>
         <title>Solving Quadratic Equations through the Square Root Property</title>
         <author>hhali</author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2296159796</link>
         <description><![CDATA[<div><br>{ If x²=d, then x=±√d }<br>1.) Transpose if needed in order to isolate x²<br>2.) Simplify your equation<br>3.) Find the square root of both sides of your equation<br>4.) Consider two roots of the equation.<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-14 11:22:28 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2296159796</guid>
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      <item>
         <title>Zero Product Property </title>
         <author>cgmaglipac</author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2296475260</link>
         <description><![CDATA[<div><strong>Zero Factor theorem:</strong><br><em>&nbsp;- If p and q are algebraic expressions, then pq = 0, if and only if p=0 or q=0<br></em><br>This theorem states that <strong>&nbsp;ax</strong><strong><sup>2</sup></strong><strong> + bx + c = 0</strong> can be written as a product of two-first degree polynomials, then the solutions can be found by setting each factor equal to zero.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-14 14:32:18 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2296475260</guid>
      </item>
      <item>
         <title>Quadratic Equation</title>
         <author>cgmaglipac</author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2296486247</link>
         <description><![CDATA[<div>&nbsp;A quadratic equation is an equation of the form&nbsp;<strong>&nbsp;ax</strong><strong><sup>2</sup></strong><strong> + bx + c = 0, </strong><mark>where a, b, and c represent real numbers</mark><strong> and a </strong>≠ 0. In standard form a must be a positive real number. The <mark>solutions</mark> to a quadratic equation are called its <mark>roots.&nbsp;</mark></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-14 14:37:52 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2296486247</guid>
      </item>
      <item>
         <title>Square Root Property </title>
         <author>cgmaglipac</author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2296494033</link>
         <description><![CDATA[<div>The process in solving x² = d is referred to as taking the square root of the equation<br>&nbsp; &nbsp;                       &nbsp; &nbsp; &nbsp;<strong><em>If x² = d, then x= +√d</em></strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-14 14:41:43 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2296494033</guid>
      </item>
      <item>
         <title>Example of equation using the Square Root Property</title>
         <author>liparadero</author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2297173409</link>
         <description><![CDATA[<div><strong><em>1. x²=169</em></strong><br><strong>Find the square root of:</strong> √x²=√169<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;x=13<br><strong>The solutions of the equation: </strong>13, -13<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-14 23:19:23 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2297173409</guid>
      </item>
      <item>
         <title>Example of equation using the Zero Product Property</title>
         <author>liparadero</author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2297178715</link>
         <description><![CDATA[<div><br><em>1. x</em><strong><em>²+8x=20</em></strong><strong><br>Transpose: </strong>x<strong>²+8x-20=0<br>Factor: (x-10) (x+2) - </strong><strong><em>you can use the triangle method to find the factors</em></strong><strong><br>Solutions of the equation: 10, -2</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-14 23:27:09 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2297178715</guid>
      </item>
      <item>
         <title>Solving Quadratic Equation By Completing the Squares</title>
         <author>ngauraki</author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2297358722</link>
         <description><![CDATA[<div><strong>in completing the squares we must be familiar of the square of a binomial and perfect square trinomial. <br>we must remember that we only apply&nbsp; completing the squares if the equation or the expression cannot be solved through extracting the square root or factoring techniques. <br>for example: <br>we have x</strong><strong><sup>2</sup></strong><strong> + 6x + 1 = 0 , so this equation cannot be solved by factoring, because 1 doesn't have a factor that when we add it it will be equal to&nbsp; 6, we also can't use extracting the square root in this situation, therefor, we must solve this by completing the square, <br>1. first is we must isolate the constant,&nbsp; transpose 1<br>it will be x</strong><strong><sup>2</sup></strong><strong> + 6x = -1&nbsp; <br>2. we must make those a perfect square trinomial, <br>so x</strong><strong><sup>2</sup></strong><strong> + 6x + _ = -1 + _ , to make this a PST we must divide the 6x into 2 , which is 3 squared by two is equal to 9 <br>so&nbsp; x</strong><strong><sup>2</sup></strong><strong> + 6x + 9 = -1 + 9 now that this is a perfect square trinomial<br>3.&nbsp; we must transform it into binomial <br>x</strong><strong><sup>2</sup></strong><strong> + 6x + 9 = -1 + 9<br>we get the square root of </strong><strong><mark>x</mark></strong><strong><mark><sup>2</sup></mark></strong><strong> + 6x +</strong><strong><mark> 9</mark></strong><strong>&nbsp; &nbsp;then -1 + 9 = 8&nbsp; so we got&nbsp; </strong><strong><mark>[X + 3]</mark></strong><strong><mark><sup>2</sup></mark></strong><strong><mark> = 8</mark></strong><strong><br>4. now we remove the&nbsp; square, by&nbsp; using the extracting the square root method, <br>√[X + 3]</strong><strong><sup>2</sup></strong><strong> =√8<br>x + 3 = +-√8<br>5. now we simplify it to&nbsp; x + 3 = +-4√2 SIMPLIFY AGAIN&nbsp;<br>x + 3 = +-2√2<br>then transpose 3 ,&nbsp;</strong></div><var><strong><mark>X = +-2√2 -3  so this is our final answer.</mark></strong></var><div><br>BY GAURAKI</div><div><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-15 01:41:18 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2297358722</guid>
      </item>
      <item>
         <title>Prince Ziaul-haq B. Mocsir</title>
         <author></author>
         <link>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2297523178</link>
         <description><![CDATA[<h1>“Sample of Solving Quadratic Equations by Completing the Square”</h1><div>&nbsp;</div><div>Complete the Square of a Binomial Expression</div><div><br>In the last section, we were able to use the Square Root Property to solve the equation (y−7) ²=12 because the left side was a perfect square.<br><br></div><div>(y−7) ²=12</div><div>y−7= ± √12</div><div>y−7= ± 2√3</div><div>y=7±2√3</div><div>We also solved an equation in which the left side was a perfect square trinomial, but we had to rewrite it the form (x−k) ² (x−k)2 in order to use the Square Root Property</div><div><br></div><div><br>&nbsp;<br><br></div><h1>&nbsp;</h1><div>What happens if the variable is not part of a perfect square? Can we use algebra to make a perfect square?</div><div><br>Let’s look at this example to help us recognize the patterns.<br><br></div><h1>&nbsp;</h1><div>&nbsp; &nbsp; &nbsp;(x+9) ²<br><br></div><div>(x+9)(x+9)<br><br></div><div>x²+9x+9x+81<br><br></div><div>x²+18x+81</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-09-15 03:47:14 UTC</pubDate>
         <guid>https://padlet.com/iamchristynamaebellingan/78pzy5n2tqtsjb93/wish/2297523178</guid>
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