AFL 11G1 Math 20th Jan 2022 by Lakshmi Sathyanarayanan https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w Find the derivative of (cos x) /(1 + sinx) en-us 2022-01-20 05:39:12 UTC 2026-01-12 22:20:34 UTC hello@padlet.com Jui https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002090574 2022-01-20 05:47:05 UTC https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002090574 Sharvi https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002093196 Diff: -1/1+sinx]]> 2022-01-20 05:49:30 UTC https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002093196 Urvi https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002094460 2022-01-20 05:50:36 UTC https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002094460 Angela https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002096694 cosx/(1+sinx)
f'(x) = d(cosx)(1+sinx) - cosx d(1+sinx) / (1+sinx)^2
f'(x) = -sinx ( 1+sinx) - cosx (cosx) / (1+sinx)^2
f'(x) = -sinx (1+sinx) - cos^2x / (1+sinx)^2
f'(x) = - (sin^2x +cos^2x)/(1+sinx)
f'(x) = -1/ (1+sinx)]]> 2022-01-20 05:52:38 UTC https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002096694 druthi https://padlet.com/boomasathyanarayanan/76ruel2f96bjze9w/wish/2002103889 cosx/1+sinx
f'(x) = (1+sinx)(-sinx)-cos^2x/ (1+sinx)^2
f'(x) = -sinx-(sin^2x-cos^2)/ (1+sinx)^2
f'(x) = -sinx -1/(1+sinx)^2
f'(x) = -1/(1+sinx)

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