https://padlet.com/sherrera24/6yc0jp513yeywb7p DRIECTIONS: Write your name and answer the following question posted en-us 2020-10-09 14:58:39 UTC 2020-10-09 15:31:21 UTC hello@padlet.com https://padlet.net/icons/png/1f913.png sherrera24 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/816972240 2020-10-09 14:59:34 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/816972240 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817064893 You would find the solution by looking the x intercept]]> 2020-10-09 15:24:16 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817064893 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817064971 You would find solutions by finding the points that are on the x-axis. Graphically they're called parabolas. ]]> 2020-10-09 15:24:17 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817064971 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817065720 Inputting the equation in demos and it giving you your x intercepts which are solutions and vertext which can either be a min or max and the opposite of your solution answer is your factored form ]]> 2020-10-09 15:24:29 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817065720 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817065870 You would find solutions graphically of quadratic equations by plotting the points in which you'd factor out the equations and then find your solutions(x-intercepts) and then after you'd use the opposite value of solutions given to show you the correct factored form. They are called x-intercepts. ]]> 2020-10-09 15:24:31 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817065870 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817066052 You would find solutions in graphically of quadratic equations by looking at the x intercept. ]]> 2020-10-09 15:24:34 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817066052 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817066629 i believe you would have to find the two points that are on the x intercept on the parabola]]> 2020-10-09 15:24:43 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817066629 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817066853 you'd find the solutions by finding the points on the parabola]]> 2020-10-09 15:24:47 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817066853 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817067707 The solutions are where the line/parabola meets the x-axis. I think they would be called x-intercept.]]> 2020-10-09 15:25:02 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817067707 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817067729 you would find solutions graphically of quadratic equations by using desmos after you factor your equations to then find your solutions x-intercept and vertex]]> 2020-10-09 15:25:02 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817067729 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817069549 you would have to find the x and y and find the vertex ]]> 2020-10-09 15:25:34 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817069549 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817070919 If your graph intercepts through the x axis, then it is considered a solution]]> 2020-10-09 15:25:58 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817070919 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817072835 You would find the solutions by the parabola meets the x axis. Which is the x intercept]]> 2020-10-09 15:26:30 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817072835 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817074337 you would find the solutions from]]> 2020-10-09 15:26:54 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817074337 https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817087051 Quadratic expressions are reflected over the y-axis, so you have to point only one in the middle and only positive x-coordinates.]]> 2020-10-09 15:30:27 UTC https://padlet.com/sherrera24/6yc0jp513yeywb7p/wish/817087051