Period 1 Universal Law of Gravitation by Thomas E Clark https://padlet.com/tec430/6sua1c1lwyu9 Please Lit 5 key points from the article PLU show work from problems a, b, and c at the end of the article in the Padlet Link. en-us 2016-11-18 15:58:28 UTC 2025-11-01 15:14:55 UTC hello@padlet.com Biren Rama https://padlet.com/tec430/6sua1c1lwyu9/wish/138760894 *The Gravitational force is a variation of the F=M*a equation.
*Gravitational force is universal, both participating objects experience the attraction.
*The universal gravity constant is G = 6.673 x 10^-11 N m^2/kg^2.
*The gravitation constant is just a derivation of the F=M*a equation, and therefore, gravity can be solved in that way as well.
*Gravitation occurs between any two objects with mass. But most are negligible.
A.) 5.98X10^26 kg^2 * (6.673x10^-11)/6.38 x 10^6^2 m^2 = Fg = 980 N
B.) 40* 5.98X10^24 *(6.673x10^-11) /6.38 x 10^6^2 = Fg = 392 N
C.) 70 * 5.98X10^24 kg^2 * (6.673x10^-11)/6.60 x 10^6 m = Fg = 641 N]]> 2016-11-18 16:50:40 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/138760894 Brie Scott https://padlet.com/tec430/6sua1c1lwyu9/wish/138760977 * All objects attract each other with a force of gravitational attraction. 
* Gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.
* More separation distance will result in weaker gravitational forces.]]> 2016-11-18 16:50:52 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/138760977 Nicky Castillo https://padlet.com/tec430/6sua1c1lwyu9/wish/138763826 1. Gravitation is universal, meaning that it is found everywhere in the universe.

]]> 2016-11-18 16:58:30 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/138763826 Cynthia Jackson https://padlet.com/tec430/6sua1c1lwyu9/wish/138857449 1) Gravitational force is directly proportional to the mass of both objects.
2)If the mass of one object increases, the mass of the other object also increases by the same amount.
3)Gravitational force does not exist between Earth and other objects but between all objects.
4)All objects attract proportional to their mass. 
5)More distance-weaker gravitational force. 
Practice Problems 
A)16/4=4 
B)16*4=64
C)16*4=64

]]> 2016-11-19 05:30:31 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/138857449 Bryson https://padlet.com/tec430/6sua1c1lwyu9/wish/139510667 2016-11-23 05:46:30 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/139510667 Bryson Leshkiw https://padlet.com/tec430/6sua1c1lwyu9/wish/139510677 1.The force of gravitational attraction between the Earth and other objects is inversely proportional to the distance separating the earth's center from the object's center. 
 2. The force of gravity acting between the earth and any other object is directly proportional to the mass of the earth/object
 3. Newton's law of universal gravitation is about the universality of gravity. 
 4. All objects attract each other with a force of gravitational attraction, dependent on the masses of both objects and is inversely proportional to the square of the distance that separates their centers. 
 5. The force of gravity is directly proportional to the product of the two masses and inversely proportional to the square of the distance of separation.
A)(100 kg)x(5.98 x1024 kg)/6.38 x 106 m=980N
B)(40 kg)x( 5.98 x1024 kg)/6.38 x 106 m=392N
C)(70 kg)x(5.98 x1024 kg)/6.60 x 106 m=641N
]]> 2016-11-23 05:46:44 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/139510677 JOY MONTES DE OCA https://padlet.com/tec430/6sua1c1lwyu9/wish/139838076 1. Objects attract each other with a gravitational attractions. This specific force pertains to all objects.
2. Gravitational forces have a force that is directly proportional to the object's mass.
3. The gravitational attraction is inversly proportional to the square of the distance of its center. 
4. If you increase the distance of the inversely proportional distance then you ]]> 2016-11-25 05:05:05 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/139838076 Uriah Aldaco https://padlet.com/tec430/6sua1c1lwyu9/wish/140062185 1) The gravitational force between two objects is directly proportional to the mass of both objects. (if one object mass is doubled, then the gF is doubled)
2) The gravitational force between two objects inversely proportional to the square distance between the objects. (if distanced is tripled, then the gF is cut in ninths)
3) Universal Gravitation Constant: 6.673 X 10^-11 N m^2 / kg^2.  which is used in calculating the force of gravitational attraction.
4) Gravitational forces exist between all objects; of course some forces are so small that they are not noticed.
5) All objects attract each other with proportional masses and inverse proportional distance of separation.
a. Fg = (6.673 x 10^-11)(100)(5.98 X 10^24)/(6.38 x 10^6)^2 = 980.5 N
b. Fg = (6.673 x 10^-11)(40)(5.98 X 10^24)/(6.38 x 10^6)^2 = 392.2 N
c. Fg = (6.673 x 10^-11)(70)(5.98 x 10^24)/(6.60 x 10^6)^2 = 641.4 N]]> 2016-11-27 23:43:02 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140062185 Nicky Castillo https://padlet.com/tec430/6sua1c1lwyu9/wish/140230578 1. Gravitation is universal, meaning that it affects all matter.
2. The force of gravitation is dependent on distance between objects and mass of the objects.
3. With the gravitation constant and the universal gravitation formula, one can find the gravitational force between two objects.
4. Distance is a larger factor of the gravitational force than the mass of one object.
5. Multiple objects may have a gravitational pull on one object.
A. Fg=(6.673x10^-11)(100)(5.98x10^24)/(6.38x10^6)^2
Fg=980N
B. Fg=(6.673x10^-11)(40)(5.98x10^24)/(6.38x10^6)^2
Fg=392N
C. Fg=(6.673x10^-11)(70)(5.98x10^24)/(6.60x10^6)^2
Fg=641N]]> 2016-11-28 16:18:13 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140230578 Cori Wong https://padlet.com/tec430/6sua1c1lwyu9/wish/140237103 1. Newton concluded that the force of gravitational attraction between the Earth and other objects is inversly proportional ti the distance separating earth's center from the object's center.  
2. Force of gravitational attraction is directly dependent upon the masses of both objects and inversly proportional to the square of the distance that separates their centers. 
Fgravity=(Gxm1xm2)/d^2 
3. Universal gravitational constant is 6.673x10^-11 Nm^2/kg^2
4. Things will weigh less at higher altitude due to the distance from the core. 
5. Gravitational interactions exist between all objects with an intensity that is directly proportional to the product of their masses.
A. ((6.673x10^-11)(100)(5.98x10^24))/(6.38x10^6)^2=980 N
B. ((6.673x10^-11)(40)(5.98x10^24))/(6.38x10^6)^2=392N
C. ((6.673x10^-11)(70)(5.98x10^24))/(6.60x10^6)^2=641N]]> 2016-11-28 16:32:06 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140237103 https://padlet.com/tec430/6sua1c1lwyu9/wish/140239317 simply are decreasing the gravitational force.
5. The forces have an inverse relationship between separation distance and force of gravity. So you can use the force of gravity equation and the Net force equation. ]]> 2016-11-28 16:37:09 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140239317 https://padlet.com/tec430/6sua1c1lwyu9/wish/140248300 Use Equation
Fgrav =G*M1*M2/d^2

Plugged in the numbers and got these as my answers.
a. Fg = = 980.512 N

b. Fg = = 392.234 N

c. Fg = = 641.447 N]]> 2016-11-28 16:57:45 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140248300 Brie Scott https://padlet.com/tec430/6sua1c1lwyu9/wish/140408444 * All objects attract each other with a force of gravitational attraction.  
* Gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. 
* More separation distance will result in weaker gravitational forces.
*   When the units on G are substituted into the equation above and multiplied by m1• m2 units and divided by d2 units, the result will be Newtons - the unit of force.
* Knowing the value of G allows us to calculate the force of gravitational attraction between any two objects of known mass and known separation distance.
*  Gravitation is universal, meaning that it affects all matter.
equation:
Fgrav= G*M1*M2/D^2
a) Fg= 980.512 N
b) Fg= 392.234 N
c) Fg= 641.447 N

]]> 2016-11-29 06:35:25 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140408444 Jenica Finuliar https://padlet.com/tec430/6sua1c1lwyu9/wish/140410255
1. All objects attract each other with gravitation attraction.
2.  Separation in the objects distances results in weaker gravitational forces. 
3. Gravitational force is proportional to the mass of the objects. 
4. As the mass of the object increases, gravitation attraction increases.
5. The value of G allows you to calculate the force of the gravitation attraction between objects with the mass and the separation distance. 
A. Fg= (6.673x10^-11)(100)(5.98x10^24)/(6.38x10^6)^2    Fg= 980 N
B. Fg=(6.673x10^-11)(40)(5.98x10^24)/(6.38x10^6)^2
Fg=392N
C. Fg=(6.673x10^-11)(70)(5.98x10^24)/(6.60x10^6)^2
Fg=641N]]> 2016-11-29 07:01:31 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140410255 Bhargav Venkatraghavan https://padlet.com/tec430/6sua1c1lwyu9/wish/140551698 -Force of gravitational attraction between the Earth and other objects is inversely proportional to the distance separating the earth's center from the object's center. 
-The force of gravity acting between the earth and any other object is directly proportional to the mass of the earth, directly proportional to the mass of the object, and inversely proportional to the square of the distance that separates the centers of the earth and the object.
-ALL objects attract each other with a force of gravitational attraction.
-Gravity is directly proportional to the product of the two masses and inversely proportional to the square of the distance of separation.
-Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
a. [(6.673*10^-11 N m^2/kg^2)*100 kg*(5.98*10^24 kg)]/(6.38*10^6 m)^2= 980 N
b. [(6.673*10^-11 N m^2/kg^2)*40 kg*(5.98*10^24 kg)]/(6.38*10^6 m)^2= 392 N
c. [(6.673*10^-11 N m^2/kg^2)*70 kg*(5.98*10^24 kg)]/(6.60*10^6 m)^2=641 ]]> 2016-11-29 16:13:03 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140551698 Gareth Usac https://padlet.com/tec430/6sua1c1lwyu9/wish/140559083 5 Key Points
-Fgrav is proportional to (m1*m2)/(d^2) and 
Fgrav=(G*m1*m2)/(d^2)
where G represents universal gravitation constant. 
G= 6.67x10^-11N*m2/kg2
-All objects attract each other with a force of gravitational attraction.
-Since gravitational force is inversely proportional to the square of the separate distance between 2 interacting objects, more separate distance will result in weaker gravitational force
-Since gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.
-Force=mass * acceleration 
This is the gravitational force equation that Newton discovered.
a) (G*100kg*5.98x10^24)/(6.38x10)^2
=980.34 N
b)
(G*40kg*5.98x10^24)/(6.38x10^6)^2
=392.23N
c)
(G*70kg*5.98x10^24)/(6.60x10^6)^2
=641.4N]]> 2016-11-29 16:29:17 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140559083 Noah Sanborn https://padlet.com/tec430/6sua1c1lwyu9/wish/140561284 1.  The force of gravity depends on the distance and mass of objects.
2.  All gravitational forces are universal.
3.  Fgrav = (G*m1*m2)/d^2
4.  G = 6.67*10^-11 N*(m^2)/kg^2
5.  The Force of Gravity interacts between all objects within the universe.
a) m1 = 100kg
m2 = 5.98*10^24kg
d = 6.38*10^6
F = (6.67*10^-11)(100)(5.98*10^24)/(6.38*10^6)^2 = 980N
b)  m1 = 40kg
m2 = 5.98*10^24kg
d = 6.38*10^6
F = (6.67*10^-11)(40)(5.98*10^24)/(6.38*10^6)^2 = 392N
c)  m1 = 40kg
m2 = 5.98*10^24kg
d = 6.60*10^6
F = (6.67*10^-11)(70)(5.98*10^24)/(6.60*10^6)^2 = 641N]]> 2016-11-29 16:33:42 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140561284 Kayla Genio https://padlet.com/tec430/6sua1c1lwyu9/wish/140716120 5 Key Points:
1.) Force depends on mass and acceleration.
2.) All objects attract each other with the force of gravitational attraction.
3.) Gravitational force is directly proportional to mass of both interacting objects.
4.) Gravitational force is inversely proportional to the square of the separation distance between two interacting objects. Thus the more separation, the weaker the gravitational force.
5.) Gravitational interactions exist between all objects with intensity that is directly proportional to the production of their mass.
Problems:
a.)
m1 = 100kg,
m2 = 5.98*10^24kg,
d = 6.38*10^6,
F = (6.67*10^-11)(100)(5.98*10^24)/(6.38*10^6)^2 = 980 N
b.)
m1 = 40kg,
m2 = 5.98*10^24kg,
d = 6.38*10^6,
F = (6.67*10^-11)(40)(5.98*10^24)/(6.38*10^6)^2 = 392N
c.)
m1 = 40kg,
m2 = 5.98*10^24kg,
d = 6.60*10^6,
F = (6.67*10^-11)(70)(5.98*10^24)/(6.60*10^6)^2 = 641N

]]> 2016-11-30 06:04:37 UTC https://padlet.com/tec430/6sua1c1lwyu9/wish/140716120