Year 7 Challenge questions by Harriet Pilkington https://padlet.com/harriet_pi/year7_challenge_questions Share any challenging problems that you have found and answer posted problems. en-us 2016-08-30 11:19:49 UTC 2024-06-04 17:09:55 UTC hello@padlet.com 1)The first challenge question of the year! Post your solutions with your working if you can show it :)  harriet_pi https://padlet.com/harriet_pi/year7_challenge_questions/wish/120519242 2016-08-30 11:33:13 UTC https://padlet.com/harriet_pi/year7_challenge_questions/wish/120519242 2) harriet_pi https://padlet.com/harriet_pi/year7_challenge_questions/wish/120529113 You must arrive at the answer of 7 by using the formula

 (a x b) ± c, 

where a b c are three unique digits from 2-9.

If (5 x 2) – 3 = 7, list the other FOUR ways of making 7, keeping to the above rules. 

There may be more than 1 answer!


]]> 2016-08-30 12:30:21 UTC https://padlet.com/harriet_pi/year7_challenge_questions/wish/120529113 3)  harriet_pi https://padlet.com/harriet_pi/year7_challenge_questions/wish/120530306
Using the numbers 3 5 5 once each, with + – x ÷available, which FOUR numbers from the following list are NOT mathematically possible to make:

1  4  7  10  13  15  18  20  22  25  28  30

For the numbers which can be made show how you did it.
]]> 2016-08-30 12:35:53 UTC https://padlet.com/harriet_pi/year7_challenge_questions/wish/120530306 26,424,655÷26,424,655=126,424,655÷26,424,655=1 https://padlet.com/harriet_pi/year7_challenge_questions/wish/120747571 2016-08-31 05:04:22 UTC https://padlet.com/harriet_pi/year7_challenge_questions/wish/120747571 Question 2 https://padlet.com/harriet_pi/year7_challenge_questions/wish/120748094 2016-08-31 05:10:34 UTC https://padlet.com/harriet_pi/year7_challenge_questions/wish/120748094