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      <title>Year 11 Smart wall by Chemistry Super Stars!!</title>
      <link>https://padlet.com/georgea6/63gknt9pwrqq</link>
      <description>Year 11</description>
      <language>en-us</language>
      <pubDate>2018-01-31 11:48:36 UTC</pubDate>
      <lastBuildDate>2026-02-28 22:47:45 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url></url>
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      <item>
         <title>Year 11 LO&#39;s (Continue)</title>
         <author>georgea6</author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/226506359</link>
         <description><![CDATA[<div><strong><mark>Global Context: Orientation in space and time</mark></strong><br>1. Convert between the amount of substance in moles and number of atoms, molecules, ions, electrons &amp; formula units”<br>2. Convert between the number of moles and mass and molar mass of atoms, molecules.<br>3. Calculate the number of moles from concentration and volume <strong><br></strong><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-01-31 11:49:22 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/226506359</guid>
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      <item>
         <title>ONLINE ICT TOOL (Padlet)</title>
         <author>georgea6</author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/226507849</link>
         <description><![CDATA[<div><strong><mark>Starter:</mark></strong><strong><br></strong>1. What is a mole?<br>2. Write all the formulas you have learnt to find the number of moles.<br>Extension:<br>3. Five moles of apples would make how many apples?</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-01-31 11:54:44 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/226507849</guid>
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      <item>
         <title>Activity</title>
         <author>georgea6</author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/226508009</link>
         <description><![CDATA[<div>Class Differentiated Task sheet</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-01-31 11:55:15 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/226508009</guid>
      </item>
      <item>
         <title>Kahoot (Fun Learning Activity)</title>
         <author>georgea6</author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/226949334</link>
         <description><![CDATA[<div><a href="https://create.kahoot.it/details/moles/937dca50-7456-48ea-9d8d-cbc576aadaab">https://create.kahoot.it/details/moles/937dca50-7456-48ea-9d8d-cbc576aadaab</a></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-01 09:45:21 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/226949334</guid>
      </item>
      <item>
         <title>End of Lesson Reflection</title>
         <author>georgea6</author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227816986</link>
         <description><![CDATA[<div>Reflect on what you have learnt today</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-04 07:15:12 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227816986</guid>
      </item>
      <item>
         <title>Aaron </title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959368</link>
         <description><![CDATA[<div>1. A mole is 6.022 x10^23 atoms which is a unit of measurement of the amount of atoms in a substance<br>2. n = Na/L, n = M/m, n = CV, C1V1 = C2V2<br>3. (6.022 x 10^23)(5) apples<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:04:04 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959368</guid>
      </item>
      <item>
         <title>Prady</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959389</link>
         <description><![CDATA[<div>1. A mole is 6.022 x 10^23 elementary components which is equal to the amount of atoms in 12 grams of Carbon 12<br><br>2. n=Na/L<br><br>n=m (mass) /M ( molar mass)<br><br>n=CV<br><br>C1V1=C2V2<br><br>3. 3.011 x 10^24 apples<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:04:14 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959389</guid>
      </item>
      <item>
         <title>Karla</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959396</link>
         <description><![CDATA[<div><strong>Starter:</strong><br><strong>1.</strong> quantity of atoms/ elements/ ions/ particles/ compounds in an area <br>(Avogdro's number--&gt; 6.02 x 10^23)<br><br><strong>2.</strong> n= na/l<br>n=m/M<br>n= C x V<br><br>n= number of moles<br>na= number of atoms<br>l= Avogadro's number<br>m=mass<br>M= molar mass<br>c= concentration<br>v= volume<br><br><strong>3.</strong> n= Na/l<br>5= Na/ 6.02 x 10^23<br>Na= 6.02 x 10^23<br>Na= 3.01 x 10^24 apples<br><br><strong>Worksheet:<br>Basic:<br>1. 0.05 moles<br>2. 2.408 x 10^23<br>3. 19.9 moles<br>4. 7.525 x 10^24<br><br>Moderate:<br></strong><br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:04:16 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959396</guid>
      </item>
      <item>
         <title>Varun</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959426</link>
         <description><![CDATA[<div>1. A mole is a fundamental unit of measurement used to measure the amount of a substance. It is equal to 6.022 x 10^23.&nbsp;<br>2. n=N/L, n=M/m, n=CV<br>3. 3.011 x 10^24</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:04:28 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959426</guid>
      </item>
      <item>
         <title>Rhea</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959430</link>
         <description><![CDATA[<div>Differentiated questions(responses):<br>Basic:<br>1. n=0.05 mols<br>2. Na= 2.408x10^24<br>3.n=19.9 mols<br>4. Na=7.525x10^24<br><br>Moderate:<br>1. n=0.64 mols<br>2. m=800g<br>3. n=11.3 mols<br>4. n=151.83 mols<br><br>Extension:<br>a) 294 g/mol<br>b) n=0.04 mol<br>c) m= 2.408x10^23</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:04:29 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959430</guid>
      </item>
      <item>
         <title>Shamma</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959434</link>
         <description><![CDATA[<div><strong>Starter:<br>1.</strong> A mole is equal to exactly the number of atoms in exactly 12 grams of Carbon-12, which is equal to Avogadro's Number (6.022 x 10^23 [of any substance])<br><strong>2.</strong> <br>Number of moles = Mass/Molar Mass<br><br>Number of moles = Number of atoms/Avogadro's Number<br><br>Number of moles = Concentration x Volume<br><br><strong>3. </strong>3.011 x 10^24 Apples<br><br><strong>Worksheet:<br>Easy</strong><br><strong>1.</strong> 0.500 moles<br><strong>2.</strong> 2.4088 x 10^24 molecules<br><strong>3.</strong> 19.9 moles<br><strong>4.</strong> 7.5275 x 10^24 formula units<br><strong>Moderate</strong><br><strong>1.</strong> 0.636 moles<br><strong>2.</strong> 800 g<br><strong>3.</strong> 11.3 moles<br><strong>4.</strong> 151.8 g<br><strong>Extension<br>1.</strong> 294<br><strong>2.</strong> 0.0357 moles<br><strong>3.</strong> 2.15 x 10^22 molecules<br><strong>4.</strong>&nbsp;4.92 x 10^21</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:04:31 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959434</guid>
      </item>
      <item>
         <title>Diya</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959532</link>
         <description><![CDATA[<div>1. The mole is most simply expressed as the relative formula mass in g of the defined chemical species and is the same as a carbon-12 atom. It contains <em>6.022 x 1023 atoms / ions / molecules.</em><strong><em><br><br></em></strong>2. n=cv<strong><em><br></em></strong>n=Na/L<br>n=m/M<br><br>3. (6.022 x 10^23)(5) apples<br><br><strong>Worksheet Answers:</strong><br>BASIC:<br>1) 0.05 mol<br>2) 2.4088 x 10^24<br>3) 19.9 mol<br>4) 7.5275 x 10^24<br>MODERATE:<br>1) 0.63 mol<br>2) 800 g<br>3) 11.3 mol<br>4) 151.8 g<br>EXTENSION:<br>1) 294 g/mol<br>2) 0.036 mol<br>3) 2.17 x 10^22 molecules<br>4) 4.8 x 10^21 atoms</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:05:14 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959532</guid>
      </item>
      <item>
         <title>Tim, Jade Gyuri</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959535</link>
         <description><![CDATA[<div>1. Scientific unit for measuring large quantities of small particles (atom)<br>6.022x10<sup>23<br></sup>2.N=CV <br>N.L=Na<br>n=m.M<br>3.<br>5(6.02x10<sup>23</sup>)<br>Basic:<br>1)3.01x10^22/6.02x10^23= 0.5<br>2) 4x6.02x10^23=2.4088x10^24<br>3) 1.20x10^25/6.02x10^23=<br>19.9<br>4) 12.5x6.02x10^23=7.525e+24<br>Moderate:<br>1) 28/32+12= 0.64<br>2) 5=m/56x2+16x3=800g<br>3)452/40=11.3<br>4)3.45=m/12+16x2=151.8<br>Extension:&nbsp;<br>1) 294<br>2) 10.5/294=0.036<br>3)10.5/294=0.036<br>4) 1.2/294=4081632653e-03x2x6.02x10^23=&nbsp;<br>4.914285714e+21</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:05:15 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959535</guid>
      </item>
      <item>
         <title>Andrea</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959585</link>
         <description><![CDATA[<div>1. A unit of measurment to calculat the number of atoms, equal to the number of atoms in 12 grams of carbon 12<br> <br>2. n=m/M , nNa/L, n=CV</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:05:34 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959585</guid>
      </item>
      <item>
         <title>Shashwat</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959605</link>
         <description><![CDATA[<div>1. A unit of measurement, equal to Avogadro's number, 6.022 x 10^23<br>Used to measure number of atoms<br><br>2. n=Na/L; n = M/m; n = CV<br><br>3. 3.011 x 10^24</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:05:40 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959605</guid>
      </item>
      <item>
         <title>Sanjita</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959663</link>
         <description><![CDATA[<div>1.A mole is a unit of measurement for atoms which follow the units of Avogadros number 6.022x10^23<br>2.n=N^A/L<br>n=m/M<br>n=CxV<br>3-3.011x24<br><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:06:10 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959663</guid>
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      <item>
         <title>Adhvaitha </title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959828</link>
         <description><![CDATA[<div> 1. What is a mole? <br> A mole corresponds to the mass of a substance that contains 6.023 x 10<sup>23</sup> particles of the substance. <br><br>2. Write all the formulas you have learnt to find the number of moles.<br><br>Formula 1 : N= CV<br>Formula 2 = C1 x V1 = C2 x V2 <br>Formula 3= n = Na/L<br>Formula 4 = N= m/M (Molecular )<br><br></div><div><br><br> </div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:07:02 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227959828</guid>
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      <item>
         <title>Dymitr</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227960297</link>
         <description><![CDATA[<div>A mole is a fundamental unit of measurement used to measure the amount of a substance.<br>N=CV<br>n=Na/L<br>n=m/M</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:10:03 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227960297</guid>
      </item>
      <item>
         <title>Ananya</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227960492</link>
         <description><![CDATA[<div>1. A mole is a unit of measurement of the amount of atoms in a substance (6.022 x 10^23)<br><br>2. Formula 1: n= Na/L<br>&nbsp; &nbsp; Formula 2: N = m/M<br>&nbsp; &nbsp; Forumla 3: C1 x V1 = C2 x V2<br>&nbsp; &nbsp; Formula 4: N = cv<br><br>N&nbsp; = Number of moles<br>Na = Number of atoms or particles<br>L = Avogadro's number<br>m = mass<br>M = Molar Mass<br>C = Concentration<br>V = Volume<br><br>3. [(6.022 x 10^23) x 5 ] apples</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:11:09 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227960492</guid>
      </item>
      <item>
         <title>Wikipedia</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227960984</link>
         <description><![CDATA[<div>1. The <strong>mole</strong> is the <a href="https://en.m.wikipedia.org/wiki/Units_of_measurement">unit of measurement</a> for <a href="https://en.m.wikipedia.org/wiki/Amount_of_substance">amount of substance</a> in the <a href="https://en.m.wikipedia.org/wiki/International_System_of_Units">International System of Units</a> (SI). The unit is defined as the amount or sample of a <a href="https://en.m.wikipedia.org/wiki/Chemical_substance">chemical substance</a> that contains as many constitutive particles, e.g., <a href="https://en.m.wikipedia.org/wiki/Atom">atoms</a>, <a href="https://en.m.wikipedia.org/wiki/Molecule">molecules</a>, <a href="https://en.m.wikipedia.org/wiki/Ion">ions</a>, <a href="https://en.m.wikipedia.org/wiki/Electron">electrons</a>, or <a href="https://en.m.wikipedia.org/wiki/Photon">photons</a>, as there are atoms in 12 <a href="https://en.m.wikipedia.org/wiki/Gram">grams</a> of <a href="https://en.m.wikipedia.org/wiki/Carbon-12">carbon-12</a> (<sup>12</sup>C), the <a href="https://en.m.wikipedia.org/wiki/Isotope">isotope</a> of <a href="https://en.m.wikipedia.org/wiki/Carbon">carbon</a> with <a href="https://en.m.wikipedia.org/wiki/Standard_atomic_weight">standard atomic weight</a> 12 by definition. This number is expressed by the <a href="https://en.m.wikipedia.org/wiki/Avogadro_constant">Avogadro constant</a>, which has a value of approximately 6.022140857×10<sup>23</sup> mol<sup>−1</sup>. The mole is an <a href="https://en.m.wikipedia.org/wiki/SI_base_unit">SI base unit</a>, with the unit symbol <strong>mol</strong>.</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:13:54 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227960984</guid>
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      <item>
         <title>Varun Worksheet Answer</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964123</link>
         <description><![CDATA[<div>BASIC:<br>1) 0.05 mol<br>2) 2.4088 x 10^24<br>3) 19.9 mol<br>4) 7.5275 x 10^24<br>MODERATE:<br>1) 0.63 mol<br>2) 800 g<br>3) 11.3 mol<br>4) 151.8 g<br>EXTENSION:<br>1) 294 g/mol<br>2) 0.036 mol<br>3) 2.17 x 10^22 molecules<br>4) 4.8 x 10^21 atoms</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:40:13 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964123</guid>
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      <item>
         <title>Aaron - Extension Answers</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964150</link>
         <description><![CDATA[<div>1. 0.05 moles<br>2. 2.408x10^24 molecules<br>3. 19.9 moles<br>4. 7.525x10^24<br>5. 0.636 moles<br>6. 800 grams<br>7. 11.3 moles<br>8. 151.8 grams<br>9. 294&nbsp;<br>10. 0.0357 moles<br>11. 2.14914 x 10^22<br>12. 4.91222 x 10^21</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:40:31 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964150</guid>
      </item>
      <item>
         <title>Esketit</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964211</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:41:08 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964211</guid>
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      <item>
         <title>Prady Extension Answers</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964311</link>
         <description><![CDATA[<div><br><br>1) 0.05 mol<br>2) 2.4088 x 10^24<br>3) 19.9 mol<br>4) 7.5275 x 10^24<br>5) 0.63 mol<br>6) 800 g<br>7) 11.3 mol<br>8) 151.8 g<br>9) 294 g/mol<br>10) 0.036 mol<br>11) 2.17 x 10^22 molecules<br>12)4.8 x 10^21 Nitrogents</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:42:08 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964311</guid>
      </item>
      <item>
         <title>Shashwat Worksheet Answers</title>
         <author></author>
         <link>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964960</link>
         <description><![CDATA[<div><br>1) 0.05 mol<br>2) 2.4088 * 10^24<br>3) 19.9 mol<br>4) 7.5275 * 10^24<br>5) 0.636363 mol<br>6) 800g<br>7) 11.3 mol<br>8) 151.8g<br>a) 294 g/mol<br>b) 0.036 mol<br>c) 2.16792*10^22<br>d) 4.8179*10^21 atoms</div>]]></description>
         <enclosure url="" />
         <pubDate>2018-02-05 04:47:21 UTC</pubDate>
         <guid>https://padlet.com/georgea6/63gknt9pwrqq/wish/227964960</guid>
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