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      <title> Bài 3: Giải bài toán by phuong thanh</title>
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      <description>Được tạo bằng một vầng hào quang bí ẩn</description>
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      <pubDate>2021-12-06 09:25:34 UTC</pubDate>
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         <title>lê vy</title>
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         <description><![CDATA[<div>lơp 3a co so hoc sinh la<br>&nbsp; 3x9=27[hoc sinh]<br>     dap so:27hoc sinh</div>]]></description>
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         <title>Kiều Anh</title>
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         <title>Đăng</title>
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         <title>Hân</title>
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         <title>Thanh Thảo</title>
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         <description><![CDATA[<div>Bài giải<br>Số học sinh lớp 3A có là:<br>9×3=27 ( học sinh )<br>Đáp số :27 học sinh</div>]]></description>
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         <title>THIÊN PHƯỚC</title>
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         <description><![CDATA[<div>Bài giải:<br>Số học sinh lớp 3A là .<br>9x3=27 (học sinh)<br>Đáp số: 27 học sinh</div>]]></description>
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         <title>THIÊN PHƯỚC</title>
         <author>huynhngoctran2021</author>
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         <description><![CDATA[<div>Bài giải:<br>Số học sinh lớp 3A là .<br>9x3=27 (học sinh)<br>Đáp số: 27 học sinh</div>]]></description>
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         <title>Thanh Thủy</title>
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         <title>Quỳnh Anh ♑</title>
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         <description><![CDATA[<div>&nbsp; &nbsp; Lớp 3A có số học sinh là :<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;9×3=27 ( học sinh )<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Đáp số : 27 học sinh.<br>&nbsp;</div>]]></description>
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         <title>Xuân Tiến</title>
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         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Bài giải<br>&nbsp;Lớp 3A có số học sinh là:<br>&nbsp; 9×3=27(học sinh)<br>   Đáp số:27 học sinh</div>]]></description>
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         <title>Đan</title>
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         <description><![CDATA[<div>Bài giải<br>Số học sinh lớp 3a có là<br>&nbsp; &nbsp; 3×9=27(học sinh)&nbsp;<br>           Đáp số: 27 học sinh</div>]]></description>
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         <title>Minh Vy</title>
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         <description><![CDATA[<div>Bài giải<br>Lớp 3A có số học sinh là:<br>9×3=27 (học sinh)<br>Đáp số: 27 học sinh</div>]]></description>
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         <title>Bảo Nguyên</title>
         <author>huynhngoctran2021</author>
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         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Bài giải<br>Số học sinh lớp 3A là :<br>9x3=27 (học sinh)<br>Đáp số: 27 học sinh .</div>]]></description>
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         <title>Hoàng Nam</title>
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         <description><![CDATA[<div>Lớp 3A có số học sinh là:&nbsp;<br>&nbsp; &nbsp; &nbsp; &nbsp;9x3= 27 (học sinh)&nbsp;<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Đáp số: 27 học sinh<br><br></div>]]></description>
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         <title>Bảo Châu</title>
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         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Giải<br>&nbsp; &nbsp; Số học sinh lớp 3A là :<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;9×3=27 (học sinh)<br>               Đáp số: 27 học sinh</div>]]></description>
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         <title>Nguyễn Hoàng Nhật Minh</title>
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         <description><![CDATA[<div>Bài giải<br>Số học sinh lớp 3A có là:<br>9x3= 27(học sinh)<br>Đáp số : 27 học sinh</div>]]></description>
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         <title>Hân</title>
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         <description><![CDATA[<div>Bài giải<br>Số học sinh của lớp 3a là:<br>9×3=27(học sinh)<br>Đáp số:27 học sinh</div>]]></description>
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         <title>Bảo Ân:</title>
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         <description><![CDATA[<div>Lớp 3a có số học sinh là:<br>3×9=27(học sinh)<br>Đáp số:27 học sinh</div>]]></description>
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         <title>Bảo anh </title>
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         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp;Bài giải&nbsp;<br>Lớp 3a có số học sinh là:<br>&nbsp; &nbsp; &nbsp; &nbsp;3×9=27(học sinh)<br>          Đáp số:27 học sinh </div>]]></description>
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         <title>Tín</title>
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         <title>Phạm Phương Linh</title>
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         <title>Võ Thanh Tú Như </title>
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         <description><![CDATA[<div>&nbsp; &nbsp; Lớp 3A có số học sinh là:<br>&nbsp; &nbsp; &nbsp; &nbsp;3×9=27(học sinh)<br>        Đáp số:27 học sinh </div>]]></description>
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         <title>MẾN</title>
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         <description><![CDATA[<div>Số học sinh có là:<br>9×3=27(học sinh)<br>Đáp số:27 học sinh</div>]]></description>
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         <title>Minh Anh</title>
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         <description><![CDATA[<div>bài giải<br>Số học sinh lớp 3A có là:<br>&nbsp; &nbsp; &nbsp; 3x9=27 ( học sinh )<br>          Đáp số: 27 học sinh</div>]]></description>
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         <title>Thùy lâm </title>
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         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Giải<br>&nbsp;Số học sinh lớp3A là:<br>&nbsp; &nbsp;9×3=27 (học sinh )<br>      Đáp số:27 học sinh</div>]]></description>
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         <title>Bảo trinh</title>
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         <description><![CDATA[<div>Lớp 3a có số học sinh là:&nbsp;<br>&nbsp; &nbsp; &nbsp; &nbsp;9x3=27(học sinh)<br>               Đáp số:27 học sinh</div>]]></description>
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         <title>Như ý </title>
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         <description><![CDATA[<div>Bài giải&nbsp;<br>Số học sinh lớp 3A có là :<br>9 x3 =27 (học sinh )<br>Đáp số : 27 học sinh </div>]]></description>
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         <title>THANH TRA</title>
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         <description><![CDATA[<div>Lop 3A co so hoc sinh la:<br>3x9 =27 [hoc sinh]<br>dap so :27 hoc sinh.</div>]]></description>
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         <title>Bích ngọc</title>
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         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Bài giải<br>&nbsp; Số học sinh lớp 3A có là :<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 3 x 9 = 27[ học sinh]&nbsp;<br>                  Đáp số : 27 học sinh</div>]]></description>
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         <title>Thanh Thủy</title>
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         <description><![CDATA[<div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Bài giải<br>Lớp 3A có số học sinh là<br>&nbsp; &nbsp; &nbsp; &nbsp; 3×9=27( học sinh)<br>             Đáp số:27 học sinh</div>]]></description>
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         <title>GIA HUY</title>
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         <description><![CDATA[<div>SÔ HOC SÏNH LOP 3A LÀ :<br>9 X 3 =27 (HOC SINH)<br>DÁP SÔ:27 HOC SINH<br><br></div>]]></description>
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         <title>Bảo Nam</title>
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         <title>Nguyễn thị thảo nguyên </title>
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         <description><![CDATA[<div>bài giải &nbsp;<br>Lớp 3a có số học sinh Là&nbsp;<br>9 x3 =27 [học sinh]<br>Đáp số : 27 học sinh</div>]]></description>
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