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      <title>Popcorn Discussions Week Ending 6/03/22 by Felix Mariano</title>
      <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16</link>
      <description>Write your response to the topic on every column as well as your reactions to other classmate comments</description>
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      <pubDate>2022-05-29 14:48:09 UTC</pubDate>
      <lastBuildDate>2022-06-03 16:23:44 UTC</lastBuildDate>
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      <item>
         <title>Dasneidy </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2205450921</link>
         <description><![CDATA[<div>If two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords ¯AC and ¯BD intersect at point E . So, <strong>AE⋅EC=DE⋅EB</strong> .</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 04:18:32 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2205450921</guid>
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      <item>
         <title></title>
         <author>jhilliard21</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206307397</link>
         <description><![CDATA[<div>If two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords ¯AC and ¯BD intersect at point E . So, <strong>AE⋅EC=DE⋅EB</strong> .</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 15:59:20 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206307397</guid>
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      <item>
         <title></title>
         <author>chernandez338</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206307765</link>
         <description><![CDATA[<div>&nbsp;two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords ¯AC and ¯BD intersect at point E . So, <strong>AE⋅EC=DE⋅EB</strong> .</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 15:59:40 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206307765</guid>
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      <item>
         <title>Rueucris</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206309582</link>
         <description><![CDATA[<div>two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords ¯AC and ¯BD intersect at point E . So, <strong>AE⋅EC=DE⋅EB</strong> .</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:01:04 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206309582</guid>
      </item>
      <item>
         <title>Leslie</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206310410</link>
         <description><![CDATA[<div>two chords intersect in a circle , then the products of the measures of the segments of the chords are equal. In the circle, the two chords ¯AC and ¯BD intersect at point E . So, <strong>AE⋅EC=DE⋅EB</strong> ..</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:01:48 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206310410</guid>
      </item>
      <item>
         <title>Allison </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206310473</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:01:52 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206310473</guid>
      </item>
      <item>
         <title>Mariam</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206311403</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div><div><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:02:39 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206311403</guid>
      </item>
      <item>
         <title></title>
         <author>rmald27</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206314918</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:05:17 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206314918</guid>
      </item>
      <item>
         <title>Nolasca</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206320156</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:09:21 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206320156</guid>
      </item>
      <item>
         <title>Noel</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206320536</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:09:39 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206320536</guid>
      </item>
      <item>
         <title>Laniya Peters</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206320755</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:09:51 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206320755</guid>
      </item>
      <item>
         <title>Amanda </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206323269</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:11:37 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206323269</guid>
      </item>
      <item>
         <title>sharniece </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206323451</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:11:47 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206323451</guid>
      </item>
      <item>
         <title>Kiara </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206324276</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:12:22 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206324276</guid>
      </item>
      <item>
         <title>Darina </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206324632</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:12:40 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2206324632</guid>
      </item>
      <item>
         <title></title>
         <author>jhilliard21</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207380570</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 11:21:31 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207380570</guid>
      </item>
      <item>
         <title>Amanda </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207439055</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 12:25:13 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207439055</guid>
      </item>
      <item>
         <title>Leslie</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207735210</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:12:30 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207735210</guid>
      </item>
      <item>
         <title></title>
         <author>chernandez338</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207735686</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:12:59 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207735686</guid>
      </item>
      <item>
         <title></title>
         <author>rmald27</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207736504</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:13:42 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207736504</guid>
      </item>
      <item>
         <title>Noel</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207737243</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:14:25 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207737243</guid>
      </item>
      <item>
         <title>Rueucris </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207737864</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:14:59 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207737864</guid>
      </item>
      <item>
         <title>mariam</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207738190</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div><div><br></div><div><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:15:16 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207738190</guid>
      </item>
      <item>
         <title>Allison </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207738378</link>
         <description><![CDATA[<div>A segment is an interior region of a<br>circle. The area enclosed by a<br>segment and the angle subtended<br>by a segment is called a sector.<br>The area of the segment of a circle<br>is determined by subtracting the<br>triangle formed inside the sector<br>from the sector which has the<br>segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:15:26 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207738378</guid>
      </item>
      <item>
         <title> Dasneidy </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207738550</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:15:37 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207738550</guid>
      </item>
      <item>
         <title>jennifer</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207738804</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:15:51 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207738804</guid>
      </item>
      <item>
         <title>Di Ventura</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207739596</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:16:37 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207739596</guid>
      </item>
      <item>
         <title>Di Ventura</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207739902</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:16:52 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207739902</guid>
      </item>
      <item>
         <title>sharniece</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207740857</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:17:48 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207740857</guid>
      </item>
      <item>
         <title>Laniya Peters</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207742090</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:18:57 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207742090</guid>
      </item>
      <item>
         <title>Nolasca</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207745477</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:21:58 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207745477</guid>
      </item>
      <item>
         <title>Justin</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207750733</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:26:26 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207750733</guid>
      </item>
      <item>
         <title>Justin</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207751160</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:26:48 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207751160</guid>
      </item>
      <item>
         <title>Kiara</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207754329</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. The area enclosed by a segment and the angle subtended by a segment is called a sector. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:29:24 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207754329</guid>
      </item>
      <item>
         <title>Darina </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207754735</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 16:29:39 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2207754735</guid>
      </item>
      <item>
         <title>mariam</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2208319066</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula  A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 02:41:47 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2208319066</guid>
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      <item>
         <title>Dasneidy </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2208320047</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 02:42:35 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2208320047</guid>
      </item>
      <item>
         <title>Rueucris </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209118897</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 15:29:45 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209118897</guid>
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      <item>
         <title></title>
         <author>jhilliard21</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209152343</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 15:58:51 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209152343</guid>
      </item>
      <item>
         <title>samia</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209153078</link>
         <description><![CDATA[<div>If two chords intersect in a circle<br>then the products of the measures<br>of the segments of the chords are<br>equal. In the circle, the two chords<br>"AC and BD intersect at point E.<br>So, AE-EC=DE EB</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 15:59:27 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209153078</guid>
      </item>
      <item>
         <title>samia</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209153332</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. <strong>The area enclosed by a segment and the angle subtended by a segment is called a sector</strong>. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 15:59:42 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209153332</guid>
      </item>
      <item>
         <title>samia</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209153487</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 15:59:52 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209153487</guid>
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      <item>
         <title>Di Ventura</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209156587</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:02:48 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209156587</guid>
      </item>
      <item>
         <title>Nolasca </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209156938</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:03:08 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209156938</guid>
      </item>
      <item>
         <title>James</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209156944</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:03:08 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209156944</guid>
      </item>
      <item>
         <title>kiara</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209157180</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:03:22 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209157180</guid>
      </item>
      <item>
         <title>Allison</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209157930</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:04:01 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209157930</guid>
      </item>
      <item>
         <title>sharniece</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209158062</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:04:08 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209158062</guid>
      </item>
      <item>
         <title>amanda</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209158180</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:04:16 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209158180</guid>
      </item>
      <item>
         <title></title>
         <author>rmald27</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209158422</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:04:30 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209158422</guid>
      </item>
      <item>
         <title>Justin</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209158451</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div><div><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:04:31 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209158451</guid>
      </item>
      <item>
         <title></title>
         <author>chernandez338</author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209200243</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:40:32 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2209200243</guid>
      </item>
      <item>
         <title>Leslie</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2210346871</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-03 16:03:31 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2210346871</guid>
      </item>
      <item>
         <title>Laniya Peters</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2210349176</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-03 16:06:19 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2210349176</guid>
      </item>
      <item>
         <title>Leslie</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2210358097</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-03 16:16:21 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2210358097</guid>
      </item>
      <item>
         <title>Leslie</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2210363676</link>
         <description><![CDATA[<div>You would calculate the area of a segment in a circle by using the formula&nbsp; A = (½) × r <sup>2</sup> × [(π/180) θ – sin θ]</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-03 16:22:48 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/5wzi8d10higw0e16/wish/2210363676</guid>
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