Popcorn Discussions Week Ending 4/29/22 by Felix Mariano https://padlet.com/felixmariano2/5rirefd852nw182n Write your response to the topic on every column as well as your reactions to other classmate comments en-us 2022-04-23 13:13:59 UTC 2026-03-17 09:09:53 UTC hello@padlet.com https://padlet.net/icons/png/1f9d4.png Tiona https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2156942434 sin(90∘−θ)=cosθ,cos(90∘−θ)=sinθ,tan(90∘−θ)=cotθ,cot(90∘−θ)=tanθ]]> 2022-04-25 16:49:43 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2156942434 Fabian https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2156953217 sin(90∘−θ)=cosθ,cos(90∘−θ)=sinθ,tan(90∘−θ)=cotθ,cot(90∘−θ)=tanθ

]]> 2022-04-25 16:55:44 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2156953217 Franky https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2156954476 sin(90∘−θ)=cosθ,cos(90∘−θ)=sinθ,tan(90∘−θ)=cotθ,cot(90∘−θ)=tanθ,sec(90∘−θ)=cscθ,csc(90∘−θ) why so long….?]]> 2022-04-25 16:56:28 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2156954476 cipriano https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2156957090 Trigonometric ratios of complementary angles: sin(90∘−θ)=cosθ,cos(90∘−θ)=sinθ,tan(90∘−θ)=cotθ,cot(90∘−θ)=tanθ,sec(90∘]]> 2022-04-25 16:57:58 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2156957090 cipriano https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2158906046  The the ration between the side opposite the angle and the side adjacent to the angle . and vice versa. The cosecant of any acute angle is equal to the secant of its complement and vice versa.]]> 2022-04-26 16:54:18 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2158906046 Tiona https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2158906268 The tangent of any angle is opposite over adjacent so tanB=ACBC and tanA=BCAC. These are inverses of each other, therefore the tangents of complementary angles are inverses of each other.]]> 2022-04-26 16:54:24 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2158906268 Chris https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2158919107 Some of ours similar to each other are the same yes]]> 2022-04-26 17:01:41 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2158919107 Jaden A https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2158920055 The sine of any acute angle is equal to the cosine of its complement and vice versa.]]> 2022-04-26 17:02:13 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2158920055 Trigonometric ratios of complementary angles: sin(90∘−θ)=cosθ,cos(90∘−θ)=sinθ,tan(90∘−θ)=cotθ,cot(90∘−θ)=tanθ,sec(90∘ zpolanco https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2160328872 2022-04-27 13:05:41 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2160328872 The proportion between the angle's opposite side and the angle's adjacent side. and the other way around. Any acute angle's cosecant is equal to its complement's secant, and vice versa. zpolanco https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2160330197 2022-04-27 13:06:26 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2160330197 The simple reason is that the length of the sides of a right triangle are always less than the length of the hypotenuse zpolanco https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2160334477 2022-04-27 13:08:56 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2160334477 jay63rd https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2161097024 Trig ratio of complementary angles is 90(cos) etc.]]> 2022-04-27 21:03:19 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2161097024 jay63rd https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2161097248 The angel is adjancted]]> 2022-04-27 21:03:34 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2161097248 jay63rd https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2161097409 Because there always less ]]> 2022-04-27 21:03:47 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2161097409 c https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2163002628 The simple reason is that the length of the sides of a right triangle are always less than the length of the hypotenuse]]> 2022-04-28 17:00:24 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2163002628 Kimora https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2165019365 sin(90∘−θ)=cosθ,cos(90∘−θ)=sinθ,tan(90∘−θ)=cotθ,cot(90∘−θ)=tanθ]]> 2022-04-30 01:39:07 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2165019365 Kimora https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2165019543 The tangent of any angle is opposite over adjacent so tanB=ACBC and tanA=BCAC. These are inverses of each other, therefore the tangents of complementary angles are inverses of each other.]]> 2022-04-30 01:39:31 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2165019543 Kimora https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2165019791 The simple reason is that the length of the sides of a right triangle are always less than the length of the hypotenuse.]]> 2022-04-30 01:40:09 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2165019791 Kimora https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2182038985 1) Press [MODE] key. 2) Scroll down to "RADIAN", scroll right to highlight "DEGREE" and press [ENTER].]]> 2022-05-12 23:40:55 UTC https://padlet.com/felixmariano2/5rirefd852nw182n/wish/2182038985