Motion by https://padlet.com/jasleensaini/5p9wetft88t1isps Jasleen Kaur Saini en-us 2020-09-10 12:44:59 UTC 2023-05-21 06:34:30 UTC hello@padlet.com Answer the following questions: jasleensaini https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/734665433 1. On a 120 km track, a train travels the first 30 km at a uniform speed of 30 km/h.  How fast must the train travel the next 90 km so as to average 60 km/h for the entire trip?
2. An object travels 16 m in 4 s and then another 16 m in 2 s. What is the average speed of the object?
3. Usha swims in a 90 m long pool. She covers 180 m in one minute by swimming from one end to the other and back along the same straight path. Find the average speed and average velocity of Usha.
4. A train 100 m long moving on a straight level track passes a pole in 5 s. Find (a) the speed of the train (b) the time it will take to cross a bridge 500 m long.


Solve the above numerical step wise. Don't write just answers. ]]> 2020-09-10 12:46:57 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/734665433 Vidhi Patel IX E https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/734891574 2020-09-10 13:36:02 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/734891574 Arham Bhansali https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/734919125 STD 9th A
1. Distance d1 = 30 km
    Velocity v1 = 30 kmph
    Time taken = t1 = d1/v1 = 1 hour
As the total distance = 120 km


→ Average speed = 60 kmph 
Total time duration = 120 / 60 = 2 hours 
Time taken for the first 30 km =  30 km /30 kmph = 1 hours
Hence, time remaining to cover the remaining 90km = 2 hrs - 1 hrs = 1 hour
Speed during 90 km 
= 90 kmph

2. total distance /total time
    16+16/4+2
     =32/6
     =5.33m/s

3. Total distance covered by Usha is 1 min is 180m
Displacement of usha in 1 min = 0m
Average speed=total distance covered /total time taken
=180m/1 min
=180m/1min ×1min/60second
=180/60
=3m/s
Average velocity =Displacement/total time taken
=0m/60second
=0m/second
The average speed of Usha is 3m/s and her average velocity is 0m/s

4. a)
   d=100m
    t=5sec
    v=?
    v=d\t
   =100\5
   =20m\s



(b)
  d=500m
    t=?
    v=20m\s
    v=d\t
     t=d\v
     =500\20
      =25sec


]]> 2020-09-10 13:41:13 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/734919125 Khushi Joshi [IX-C] https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/734965099 2020-09-10 13:49:42 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/734965099 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735057074 Aesha Maniar IX A]]> 2020-09-10 14:06:24 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735057074 Malav Shah IX E https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735223866 1. Distance D1=30 km
  Average Speed 1=30 km/hr
  Total time T1=30/30=1 hr
  Total Distance=120 km
  Average speed 2=60 km/hr
  Total time T2=120/60=2 hr
  Time left=2-1(hr)= 1 hr
 Speed during 90 km=
 90  km/hr   

2. Average Speed=Total distance/ Total time taken
=16+16/4+2
=32/6= 5.33 m/s

3. Average Speed=Total distance/ Total time taken
=180/60 (1 minutes= 60 seconds)
=3 m/s

Average velocity= Displacement/Total time taken
=0/180 (she comes back to initial position)

4.(a)Speed=Distance/Time
   =100/5
    =20 m/s

   (b)Time=Distance/Speed
      =500/20
=25 seconds

   
     ]]> 2020-09-10 14:36:01 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735223866 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735403958 Veera 9D

]]> 2020-09-10 15:08:04 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735403958 Dev Pareshkumar Patel (9th B) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735435751 1. =>Distance (D1)= 30 km 
=>velocity(V1)= 30 km/hr
=>Total time = T1=d1/v1= 1hr
=>Total distance=120 km
=>Average speed=60 km/hr
=>Total =>time=t2=120/60=2 hr
=>Time left=2 hr-1 hr= 1hr
Hence, time remaining to cover 90 km= 90 km/hr

Ans= 90 km/hr

2. =>Average speed = total distance/total time taken
=>16+16/4+2= =>32/6=5.33m/s

Ans= 5.33 m/s

3. =>Average speed=Total distance/total time taken
=> 1 minute = 60 seconds
=>180/60 = 3m/s

=>Total distance covered by Usha in 1min=180m
=>Displacement of Usha=0m (because she comes back to her initial position)

=>Average velocity=displacement/total time taken
=>0m/60sec
=>0 m/s

4.(a) speed= distance/time
=>100/5 m/s
=> 20 m/s

(b) time taken= distance/speed
=>500/20
=>25 seconds



]]> 2020-09-10 15:13:48 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735435751 BRONA (IX E) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735436880 2020-09-10 15:14:00 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735436880 Hiya https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735437504 1. Average speed=Total distance Total time taken
Vav​=t/d
For 120 km,
t=60 km/hr120 km​=2 hr ......(i)
For 1st 30 km,t1​=30 km/hr30 km​=1 hr
For remaining 90 km,
t2​=t−t1​=2−1=1 hr
speed=time/distance​ 
​​=90/1
=90 km/hr

2.  Total distance = 16m + 16m = 32m
Total time = 4s + 2s = 6s

Average speed = Total distance / Total time
                        = 32/6
                       = 5.33 m/s

3. Total displacement =0
Time taken, t=1 min=60sec

Average velocity (Vav)= 
total time taken/
Total Displacement
​
Vav = 60/0
 =0 m/s

4. length of train = 100 m 

To pass a pole train ll cover the distance equal to its length

So distance cover by train = 100 m
Time taken = 5 s
Speed of train = distance covertime taken = 1005 = 20 m/s

 Total distance to cover to cross a bridge = length of bridge + length of train = 500 + 100 = 600 m
Speed = 20 m/s
time taken = distance coverspeed =
 600/20 
=  30 s]]> 2020-09-10 15:14:07 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735437504 Kathan(IX C) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735484823 1) Distance d1 =30km
velocity d1 = 30kmph
time taken=t1= d1/v1=1 hour
As the total distance = 120k 
avergae speed =60 kmph 
total time duration 120/60 =2 hour
Time taken for the first 30 km =  30 km /30 kmph = 1 hours
Hence, time remaining to cover the remaining 90km = 2 hrs - 1 hrs = 1 hour
Speed during 90 km 
= 90 kmph 

2) total distance /total time
    16+16/4+2
     =32/6
     =5.33m/s



3. Total distance covered by Usha is 1 min is 180m
Displacement of usha in 1 min = 0m
Average speed=total distance covered /total time taken
=180m/1 min
=180m/1min ×1min/60second
=180/60
=3m/s
Average velocity =Displacement/total time taken
=0m/60second
=0m/second
The average speed of Usha is 3m/s and her average velocity is 0m/s

4. a)
   d=100m
    t=5sec
    v=?
    v=d\t
   =100\5
   =20m\s



(b)
    d=500m
    t=?
    v=20m\s
    v=d\t
     t=d\v
     =500\20
      =25sec




]]> 2020-09-10 15:22:34 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735484823 Riya shah (9-E) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735541848 motion numericals]]> 2020-09-10 15:32:42 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735541848 EKANSHA MAROJU 9E https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735592021 1)  Total distance= 120km
       Average speed=60km/hr
        Total time taken= distance/speed
        120/60=2hr
        Distance-1= 30km
        speed-1= 30km/hr
       time taken= distance/speed
                          = 30/30= 1hr
        Distance-2= 90km
        time taken= total time - time-1
                            = 2hr-1hr= 1hr
        Speed-2= Distance/time
                      = 90/1= 90km/hr

2) total distance= 16+16= 32m
     total time= 4+2= 6s
     average speed= distance/time
                               = 32/6
                               = 5.33 m/s

3)  Total distance= 180m
      Total time= 1min= 60sec
      Average speed= distance/time
                                 = 180/60
                                 = 3 m/s
     Displacement= 0
     Average velocity= displacement/time
                                   = 0/60
                                   = 0 m/s

4) a. Distance= 100m
          Time taken= 5s
        Average speed= distance/time
                                   = 100/5
                                   = 20 m/s
    b. Distance= 500m
         Speed= 20 m/s
        Time taken= distance/speed
                            = 500/20
                            = 25s

]]> 2020-09-10 15:41:36 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735592021 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735617477 Greeva Yava (9thC)]]> 2020-09-10 15:46:25 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735617477 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735627990 Esha patel 9B]]> 2020-09-10 15:48:15 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735627990 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735642565 Esha patel 9B]]> 2020-09-10 15:50:50 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735642565 Astha Sinha https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735653735 9A]]> 2020-09-10 15:52:55 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735653735 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735705983 Nishant Trivedi ]]> 2020-09-10 16:03:19 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735705983 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735722431 2020-09-10 16:06:24 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735722431 Kanan Parikh (IX C ) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735728695 2020-09-10 16:07:31 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735728695 Rudraksh Sharma ( IX A) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735740905 1. Average speed=Total distance /Total time taken
V average ​=t/d
For 120 km,
t=60 km/hr 120 km​=2 hr
For 1st 30 km,t 1​=30 km/hr 30 km​=1 hr
For remaining 90 km,
t2​=t−t1​=2−1=1 hr
speed=time/distance​
​​=90/1
=90 km/hr                                                                                   
Total distance = 16 m + 16 m = 32m
Total time = 4 s + 2 s = 6 seconds

Average speed = Total distance / Total time
                        = 32/6
  Average speed   = 5.33 ms-1
Total displacement =0
Time taken, t=1 min=60 sec

Average velocity (V av)=
total time taken/
Total Displacement
​
V av = 60/0
 =0 m/s

4. a. length of train = 100 m

To pass a pole train ll cover the distance equal to its length

So distance covered  by train = 100 m
Time taken = 5 s
Speed of train = distance cover / time taken = 100/5 = 20 m/s

 b. Distance= 500 m
         Speed= 20 m/s
        Time taken= distance/speed
                            = 500/20
                            = 25 seconds 
 ]]> 2020-09-10 16:09:47 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735740905 Jhalak Dogra- IX A https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735870988 1. Average speed= Total Distance/Total time taken
: Vav= d/t
For 120km 
: 60km/h= 120km/ t  
: t= 120km/ 60km/hr
: t= 2hours or 120mins
For 1st 30km
: 30km/h= 30km/t
: t1= 30km/ 30km/h
: t1= 1hr Or 60mins
For remaining 90km
t2= t-t1= 2hr-1hr= 1hr
Speed= distance/time= 90/1= 90km/h

2. Total time: 4sec+2sec= 6sec
Total distance= 16m+16m= 32m
Average speed= Total Distance/Total time taken
: Vav= d/t
: Vav= 32/6=16/3= 5.33m/s

3. Usha covers distance= 180m
Time taken by usha: 1min Or 60sec
Displacement= 0m
Average speed= Total Distance/Total time taken= d/t = 180/60= 3m/s
Average Velocity= Displacement/time= 0/60= 0/ms

4. 
a) Distance= 100m
Time= 5sec
Speed=? 
:Speed= distance/time= d/t= 100/5= 20m/s

b) Distance= 500m
Time= ? 
Speed= 20m/s
: Speed= distance/time
: Time= distance/speed= 500/20= 25m/s]]> 2020-09-10 16:33:47 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735870988 Dhruv Makhija (IX A) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735935760 2020-09-10 16:46:01 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735935760 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735955703 Param ambalia IX A page 1]]> 2020-09-10 16:49:50 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735955703 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735985087 Param ambalia IX A page 2]]> 2020-09-10 16:55:23 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/735985087 Pretty shah https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/736125194 2020-09-10 17:21:08 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/736125194 Mahek Shah https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/736325133 1. Distance=d1=30 km
   Velocity=v1=30kmph
    Time taken=t1=d1/v1= 1hour
    Total distance=120 km
Average speed=60kmph
  Total time=120/60=2 hrs
  Total time taken for the first 30km= 30km/30 kmph=1hr
   The time remaining for 90 km= 2hrs-1hr=1hr
  Speed during 90km= 90 kmph

2. Average Speed= Total Distance/Total time taken
  =16+16/4+2 = 32/6= 5.33m/s 

3. Average Speed= Total Distance/Total time 
 = 180m/1min= 3m/sec 
  Displacement =0m 
   Average velocity= Displacement/Total time taken 
   =0/60= 0m/sec 

4. (a) Distance=100m 
        Time= 5s 
Speed = D/T
   v= 100/5 =20 m/s 
 (b) Distance=500m 
  Speed=20m/sec 
  Speed=Distance/Time 
   20 m/s= 500/T
   T= 500/20= 25 sec. 
  
]]> 2020-09-10 17:57:08 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/736325133 Anchal Patel (IX-C) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737459477 2020-09-11 01:33:59 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737459477 Inshrah Shaikh https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737656107 2020-09-11 03:17:34 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737656107 Diyancy https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737760879 2020-09-11 04:31:06 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737760879 Abhas Tripathi https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737828093
1. Average speed= Total Distance/Total time taken
average speed= d/t
For 120km 
Vav=d/t  
time= 120km/ 60km/hr
time = 2hours or 120mins
For 1st 30km
 30km/h= 30km/t
time1= 30km/ 30km/h
time1= 1hr Or 60mins
For remaining 90km
time2= t-time1= 2hr-1hr= 1hr
Speed= distance/time= 90/1= 90km/h

2.Total time taken = 6s
Total distance covered= 32m
Vav=d/t
Average speed = (32/6) m/s
=5.333333..... m/s

3. length of pool= 90 m
length covered in 60 secs = 180 m
that means 2 lengths of pool
displacement = 0 ( returned to initial point)
Average speed= Total Distance/Total time taken= d/t = 180/60= 3m/s
Average Velocity= Displacement/time= 0/60= 0/ms

4.. a) Distance = 100m
time = x
speed = 5 seconds
speed = d/t
(100/5) m/s= 20 m/s

b) Distance= 500m
Time= x 
Speed= 20m/s
Speed= distance/time
Time= distance/speed= 500/20= 25m/s= x]]> 2020-09-11 05:19:15 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737828093 https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737830532 Shrey]]> 2020-09-11 05:21:22 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737830532 Hardil Deasi(IX C) https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737834150 1.  Average speed=Total distance Total time taken
Vav​=td​ort=Vav​d​
For 120 km,
t=60 km/hr120 km​=2 hr ......(i)
For 1st 30 km,t1​=30 km/hr30 km​=1 hr
For remaining 90 km,
t2​=t−t1​=2−1=1 hr
speed=timedistance​ or v2​=t2​d2​​=190​=90 km/hr


2. Total distance = 16m + 16m = 32m
Total time = 4s + 2s = 6s

Average speed = Total distance / Total time
                       = 32/6
                       = 5.33 m/s



3.          
Distance = 180 m


Time = 1 min = 60sec


Average speed = total distance covered / total time taken

= 180m / 60 sec

= 3m/s


Displacement = 0m/s ( as usha come back along the same path so, the intial and final position is same )


Average velocity = displacement/ time

= 0m / 60 s

= 0m/s



4. 

(a) d=100m     
t=5sec     
 v=?   
Therefore,             
 v=d\t       
=100\5                       
=20m\s






(b) d=500m     
t=?     
v=20m\s
Therefore,                 
v=d\t                 
 t=d\v                   
 =500\20                   
=25sec

-Hardil Desai

]]> 2020-09-11 05:24:19 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737834150 Vashishtha https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737839282 Motion Numericals ]]> 2020-09-11 05:28:52 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737839282 Tanisha Patel https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737908437 Motion Numericals ]]> 2020-09-11 06:26:36 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737908437 Preet Punjabi https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737927873 2020-09-11 06:44:54 UTC https://padlet.com/jasleensaini/5p9wetft88t1isps/wish/737927873