<?xml version="1.0"?>
<rss version="2.0">
   <channel>
      <title>Parallel Lines by Ashley Judy</title>
      <link>https://padlet.com/ashley_judy/55rkln7w554nxsjr</link>
      <description>It&#39;s your turn to try!</description>
      <language>en-us</language>
      <pubDate>2020-05-05 16:31:16 UTC</pubDate>
      <lastBuildDate>2021-11-10 18:45:51 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url></url>
      </image>
      <item>
         <title>Directions</title>
         <author>ashley_judy</author>
         <link>https://padlet.com/ashley_judy/55rkln7w554nxsjr/wish/552637674</link>
         <description><![CDATA[<div>Choose ONE of these problems, answer the question, and then post your answer.  Be sure to tell us which problem you solved!<br>If a problem has already been solved, try another one! (Put your first name in the title)</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-05-05 16:35:19 UTC</pubDate>
         <guid>https://padlet.com/ashley_judy/55rkln7w554nxsjr/wish/552637674</guid>
      </item>
      <item>
         <title>Problems</title>
         <author>ashley_judy</author>
         <link>https://padlet.com/ashley_judy/55rkln7w554nxsjr/wish/553089802</link>
         <description><![CDATA[<div>(1) Write the equation of a line parallel to y=x+4 through (2,2)<br><br>(2) Write the equation of a line parallel to y=3x+2 through (2,-4)<br><br>(3) Write the equation of a line parallel to y=-x+2 through (4,-1)<br><br>(4) Write any equation that is parallel to y=(1/8)x+2<br><br>(5) Write any equation that is parallel to y=(-2/5)x+3<br><br>(6) Is the line y=(1/4)x–9 parallel to a line that passes through the points (0,-2) and (4,-1)?<br><br>(7) Is the line y=2x–14 parallel to a line that passes through the points (0,-1) and (2,0)?</div>]]></description>
         <enclosure url="" />
         <pubDate>2020-05-05 19:33:41 UTC</pubDate>
         <guid>https://padlet.com/ashley_judy/55rkln7w554nxsjr/wish/553089802</guid>
      </item>
   </channel>
</rss>
