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      <title>GCSE Maths  by </title>
      <link>https://padlet.com/19oevere/4w8qc6yslthr96ag</link>
      <description>Sep 21 - July 22</description>
      <language>en-us</language>
      <pubDate>2021-11-06 17:24:12 UTC</pubDate>
      <lastBuildDate>2025-10-07 19:00:35 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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      <item>
         <title>Indices Basics </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871799612</link>
         <description><![CDATA[<div>Rules:&nbsp;<br>- add powers when multiplying&nbsp;<br>- subtract powers when dividing&nbsp;<br>- multiply powers when using brackets to square/cube&nbsp;<br>- these rules only apply when the integers are equal </div>]]></description>
         <enclosure url="https://www.bbc.co.uk/bitesize/guides/zqtv6yc/revision/1" />
         <pubDate>2021-11-06 17:25:41 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871799612</guid>
      </item>
      <item>
         <title>Indices Fractional </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871800591</link>
         <description><![CDATA[<div>1) Take the denominator of the power and root the integer by the denominator (if numerator is 1)&nbsp;<br>OR <br>2) Take the denominator and root the integer by the denominator, put this in brackets, then apply the numerator as an external power (if the numerator and denominator are both N) </div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=omY_kulfPPg" />
         <pubDate>2021-11-06 17:26:41 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871800591</guid>
      </item>
      <item>
         <title>Negative Indices</title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871800914</link>
         <description><![CDATA[<div>a (0) = 1&nbsp;<br>a (-1) = 1/a<br>a (-2) = 1/a2<br>a (-3) = 1/a3<br>a (-4) = 1/a4</div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=wjMe5KFVNr8" />
         <pubDate>2021-11-06 17:27:01 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871800914</guid>
      </item>
      <item>
         <title>Adding and Subtracting Indices</title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871801949</link>
         <description><![CDATA[<div>1) simplify the indices&nbsp;<br>2) find a fraction or whole number suitable for addition&nbsp;<br>3) (powers cannot be added or subtracted like multiplication)&nbsp;<br>4) add or subtract digits relativley</div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=x5Ig8SK2AHg" />
         <pubDate>2021-11-06 17:27:58 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871801949</guid>
      </item>
      <item>
         <title>Standard Form Basics</title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871802708</link>
         <description><![CDATA[<div>Rules:&nbsp;<br>1) Only numbers between 1 and 9 can be used for standard form&nbsp;<br>2) these numbers can have multiple decimal figures&nbsp;<br>3) powers affect the number if they have decimal digits&nbsp;<br>e.g.&nbsp;<br>8.927 x 10 (3) = 8927&nbsp;<br>8 x 10 (4) = 80000<br>2.926 x 10 (-4) = 0.0002926</div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=qNJ0z1zi3eM" />
         <pubDate>2021-11-06 17:28:48 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871802708</guid>
      </item>
      <item>
         <title>Multiplying and Dividing standard form </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871803094</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://thirdspacelearning.com/gcse-maths/number/multiplying-and-dividing-standard-form/" />
         <pubDate>2021-11-06 17:29:14 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871803094</guid>
      </item>
      <item>
         <title>Adding and Subtracting Standard Form </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871803762</link>
         <description><![CDATA[<div>Method 1:&nbsp;<br>1) Use knowledge of decimal places to make the powers equal on both sides&nbsp;<br>2) Add/subtract whole numbers&nbsp;<br>3) Leave powers the same&nbsp;<br><br>Method 2:&nbsp;<br>1) Translate standard form into whole numbers&nbsp;<br>2) Add/subtract these as whole numbers&nbsp;<br>3) Convert whole number back into standard form (be aware that only numbers 1-9 are used) </div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=5iGgvtBDKKk" />
         <pubDate>2021-11-06 17:29:49 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871803762</guid>
      </item>
      <item>
         <title>Surds Basics </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871805015</link>
         <description><![CDATA[<div>A surd is the square root of a number that cannot be reduced as whole </div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=MaXfdPOheCA" />
         <pubDate>2021-11-06 17:31:07 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871805015</guid>
      </item>
      <item>
         <title>Simplifying Surds </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871805351</link>
         <description><![CDATA[<div>1) Find a square number factor in the surd&nbsp;<br>2) Change the format to (square root x square root)&nbsp;<br>3) Square root the square number&nbsp;<br>4) leave the multiplier number as a square root&nbsp;<br>e.g.&nbsp;<br>,/162 = 81 x 2<br>,/81 x ,/2<br>Ans = 9 ,/2 </div>]]></description>
         <enclosure url="https://www.bbc.co.uk/bitesize/guides/zpbcjty/revision/2" />
         <pubDate>2021-11-06 17:31:27 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871805351</guid>
      </item>
      <item>
         <title>Simplifying Ratio </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871805746</link>
         <description><![CDATA[<div>1) Find a common factor&nbsp;<br>2) Divide both sides of the ratio by this until it cannot be divided as a whole number any more </div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=6uwnkOC5hLI" />
         <pubDate>2021-11-06 17:31:50 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871805746</guid>
      </item>
      <item>
         <title>Sharing Ratios </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871806156</link>
         <description><![CDATA[<div>1) add the two (or more) digits in the ratio together&nbsp;<br>2) divide the total number by this&nbsp;<br>3) times the number you get by each side of the ratio&nbsp;<br>e.g.&nbsp;<br>share 300 into 7 : 8&nbsp;<br>7 + 8 = 15&nbsp;<br>300/15 = 20<br>20 x 7 = 140&nbsp;<br>20 x 8 = 160&nbsp;<br>Ans = 140 : 160 <br><br></div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=STi2ekQySeg" />
         <pubDate>2021-11-06 17:32:16 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871806156</guid>
      </item>
      <item>
         <title>Expressing ratio in N : 1</title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871806580</link>
         <description><![CDATA[<div>9 : 18&nbsp;<br>/18 /18<br>0.5 : 1 </div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=ETaa3FWUDEs" />
         <pubDate>2021-11-06 17:32:44 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871806580</guid>
      </item>
      <item>
         <title>Expressing ratio in 1 : N </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871807197</link>
         <description><![CDATA[<div>8 : 16&nbsp;<br>/8&nbsp; /8&nbsp;<br>1 : 2 </div>]]></description>
         <enclosure url="https://corbettmaths.com/2018/12/31/expressing-as-1n/" />
         <pubDate>2021-11-06 17:33:22 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871807197</guid>
      </item>
      <item>
         <title>Direct Proportion </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871807619</link>
         <description><![CDATA[<div>1) y/x = multiplier&nbsp;<br>2) the goal is to identify the multiplier and complete the grid, or state a relationship between x and y&nbsp;<br><br></div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=kcOwC7uqJNE" />
         <pubDate>2021-11-06 17:33:49 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871807619</guid>
      </item>
      <item>
         <title>Inverse Proportion word equations</title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871808324</link>
         <description><![CDATA[<div>1) K = xy<br>2) K is always constant (the same)&nbsp;<br>3) xy has to equal k for it to be inversely proportional&nbsp;<br>4) k/y = x&nbsp;<br>5) k/x = y </div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=WpDYCq14Oes" />
         <pubDate>2021-11-06 17:34:31 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871808324</guid>
      </item>
      <item>
         <title>Proportional Relationships in tables</title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871809287</link>
         <description><![CDATA[<div>Direct proportion = y/x = multiplier&nbsp;<br>Inverse proportion = k = yx</div>]]></description>
         <enclosure url="https://www.youtube.com/watch?v=NhZmOqgwnzw" />
         <pubDate>2021-11-06 17:35:30 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871809287</guid>
      </item>
      <item>
         <title>Simultaneous Equations</title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871810153</link>
         <description><![CDATA[<div>1) remove x from each side&nbsp;<br>2) remove 1 from each side<br>3) repeat these steps until you have a simple equation with a single side of x </div>]]></description>
         <enclosure url="https://www.bbc.co.uk/bitesize/guides/z9y9jty/revision/1" />
         <pubDate>2021-11-06 17:36:20 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1871810153</guid>
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      <item>
         <title>simultaneous equations </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1917677208</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://youtu.be/hZDJZudXGGg" />
         <pubDate>2021-11-29 11:43:27 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1917677208</guid>
      </item>
      <item>
         <title>simultaneous equations article </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1917680835</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://mathsmadeeasy.co.uk/gcse-maths-revision/simultaneous-equations-gcse-maths-revision/" />
         <pubDate>2021-11-29 11:46:01 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1917680835</guid>
      </item>
      <item>
         <title>substituting formulae article </title>
         <author>19oevere</author>
         <link>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1917681961</link>
         <description><![CDATA[]]></description>
         <enclosure url="https://www.bbc.co.uk/bitesize/guides/z36vcj6/revision/2" />
         <pubDate>2021-11-29 11:46:45 UTC</pubDate>
         <guid>https://padlet.com/19oevere/4w8qc6yslthr96ag/wish/1917681961</guid>
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