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      <title>Electrochemistry by karla fakhry</title>
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      <description>Balancing redox reactions</description>
      <language>en-us</language>
      <pubDate>2019-01-17 17:06:53 UTC</pubDate>
      <lastBuildDate>2019-02-04 20:53:30 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
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         <title>Rules for balancing redox reactions in acidic and basic medium:</title>
         <author>karla_fakhry_1</author>
         <link>https://padlet.com/karla_fakhry_1/4v9urszixbti/wish/321797617</link>
         <description><![CDATA[<ol><li>Balance elements in the equation other than O and H.</li><li>Balance the oxygen atoms by adding the appropriate number of water (H<sub>2</sub>O) molecules to the opposite side of the equation.</li><li>Balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom) by adding H<sup>+</sup> ions to the opposite side of the equation.  </li><li>Add up the charges on each side. Make them equal by adding enough electrons (e<sup>-</sup>) to the more positive side. (Rule of thumb: e<sup>-</sup> and H<sup>+</sup> are almost always on the same side.)</li><li>The e<sup>-</sup> on each side must be made equal; if they are not equal, they must be multiplied by appropriate integers (the lowest common multiple) to be made the same.</li><li>The half-equations are added together, canceling out the electrons to form one balanced equation. Common terms should also be canceled out.</li></ol><ul><li>(If the equation is being balanced in a basic solution, through the addition of one more step, the appropriate number of OH<sup>-</sup> must be added to turn the remaining H<sup>+</sup> into water molecules.)</li><li>The equation can now be checked to make sure that it is balanced</li></ul><div><br></div>]]></description>
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         <pubDate>2019-01-17 17:17:40 UTC</pubDate>
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         <title>Balance the following redox reactions in acidic medium</title>
         <author>karla_fakhry_1</author>
         <link>https://padlet.com/karla_fakhry_1/4v9urszixbti/wish/321799744</link>
         <description><![CDATA[<div> 1-  H<sub>2</sub>O<sub>2</sub> + Cr<sub>2</sub>O<sub>7</sub> <sup>2-</sup>  → O<sub>2</sub> + Cr<sup>3+</sup> <br> 2- TeO<sub>3</sub> <sup>2-</sup> + N<sub>2</sub>O<sub>4</sub> → Te + NO<sub>3</sub><sup> - </sup><br>3-  ReO<sub>4</sub> <sup>-</sup> + IO<sup>-</sup> → IO<sub>3</sub><sup> -</sup> + Re <br>4-  PbO<sub>2</sub> + I<sub>2</sub> → Pb<sup>2+</sup> + IO<sub>3</sub> <sup>- </sup></div>]]></description>
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         <pubDate>2019-01-17 17:20:59 UTC</pubDate>
         <guid>https://padlet.com/karla_fakhry_1/4v9urszixbti/wish/321799744</guid>
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      <item>
         <title>Balance each half reaction in basic solution. </title>
         <author>karla_fakhry_1</author>
         <link>https://padlet.com/karla_fakhry_1/4v9urszixbti/wish/321802819</link>
         <description><![CDATA[<div>1-  Cr<sub>2</sub>O<sub>7</sub><sup>2-</sup>      → Cr<sup>3+</sup><br>2-   NO → NO<sub>3</sub><sup>-</sup><br>3-   SO<sub>4</sub><sup>2-</sup> → SO<sub>2 <br>4-   </sub> MnO<sub>2</sub> → Mn<sub>2</sub>O<sub>3</sub> <br><br><br></div>]]></description>
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         <pubDate>2019-01-17 17:26:12 UTC</pubDate>
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