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      <title>pHs by </title>
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      <language>en-us</language>
      <pubDate>2022-10-05 08:20:03 UTC</pubDate>
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         <title>Calculating pHs</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327178493</link>
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         <pubDate>2022-10-05 08:20:37 UTC</pubDate>
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         <title>Calculating pH in Strong Acids</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327185290</link>
         <description><![CDATA[<div>HA → H⁺ + A⁻<br>Relationship between HA and H⁺ is 1:1 therefore:<br>[H⁺] = [HA]<br>pH = -log[HA]</div>]]></description>
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         <pubDate>2022-10-05 08:25:56 UTC</pubDate>
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         <title>Definition of pH</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327186451</link>
         <description><![CDATA[<div>pH = -log[H⁺]</div>]]></description>
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         <pubDate>2022-10-05 08:26:48 UTC</pubDate>
         <guid>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327186451</guid>
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         <title>Calculating pH in Weak Acids</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327187330</link>
         <description><![CDATA[<div>HA ⇄ H⁺ + A⁻<br>Therefore:<br>K<sub>a</sub> = [H⁺] [A⁻] / [HA]<sub>eqm</sub><br>Since [H⁺] = [A⁻],<br>K<sub>a</sub> = [H⁺]<sup>2</sup> / [HA]<sub>eqm</sub><br>and since [HA]<sub>start</sub> = [HA]<sub>eqm</sub><br>K<sub>a</sub> = [H⁺]<sup>2</sup> / [HA]<sub>start</sub><br>By rearranging we can get:<br>[H⁺] = √(K<sub>a</sub> [[HA]<sub>start</sub>)<br>pH = -log√(K<sub>a</sub> [HA]<sub>start</sub>)</div>]]></description>
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         <pubDate>2022-10-05 08:27:31 UTC</pubDate>
         <guid>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327187330</guid>
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         <title>Assumptions for calculating pH in Weak Acids</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327215733</link>
         <description><![CDATA[<div>1) The concentration of H⁺, [H⁺] is equal to the concentration of A⁻, [A⁻] during equilibrium.<br>2) The change is concentration of HA at the start, [HA]<sub>start</sub> to HA in equilibrium, [HA]<sub>eqm</sub> is negligible enough that [HA]<sub>start </sub>= [HA]<sub>eqm</sub><br>3) We can ignore any H⁺ from the dissociation of water as it is negligible in comparison to the concentration of H⁺ from the acid.</div>]]></description>
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         <pubDate>2022-10-05 08:49:43 UTC</pubDate>
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         <title>Assumptions of calculating pH in Strong Acids</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327227831</link>
         <description><![CDATA[<div>1) We can ignore any H⁺ from the dissociation of water as it is negligible in comparison to the concentration of H⁺ from the acid.<br>2) The acid fully dissociates into its ions.</div>]]></description>
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         <pubDate>2022-10-05 08:58:28 UTC</pubDate>
         <guid>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327227831</guid>
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         <title>Equilibrium constant of acid dissociation, Kₐ</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327246148</link>
         <description><![CDATA[<div>K<sub>a</sub> = [H⁺] [A⁻] / [HA]<sub>eqm</sub><br>Equilibrium Constant changes with temperature.</div>]]></description>
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         <pubDate>2022-10-05 09:13:34 UTC</pubDate>
         <guid>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327246148</guid>
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      <item>
         <title>Equilibrium constant of water dissociation, Kw</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327254050</link>
         <description><![CDATA[<div>K<sub>w</sub> = [H⁺] [OH⁻]<br>Equilibrium Constant changes with temperature.</div>]]></description>
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         <pubDate>2022-10-05 09:19:48 UTC</pubDate>
         <guid>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2327254050</guid>
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      <item>
         <title>Calculating pH in Strong Bases</title>
         <author>n8dsouza</author>
         <link>https://padlet.com/n8dsouza/4o8qipwr8rs49fsg/wish/2328870124</link>
         <description><![CDATA[<div>AkOH → Ak⁺ + OH⁻<br>Relationship between AkOH and OH⁻ is 1:1 therefore:<br>K<sub>w</sub> = [H⁺] [OH⁻]<br>K<sub>w</sub> = [H⁺] [AkOH]<br>By rearranging we can get:<br>[H⁺] = K<sub>w</sub> / [AkOH] <br>pH = -log(K<sub>w</sub> / [AkOH])</div>]]></description>
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         <pubDate>2022-10-06 06:56:28 UTC</pubDate>
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