<?xml version="1.0"?>
<rss version="2.0">
   <channel>
      <title>Il mio padlet geometrico by </title>
      <link>https://padlet.com/abdileedekhissi/40yc1bldi8a1</link>
      <description>Realizzato con un colpo di fortuna</description>
      <language>en-us</language>
      <pubDate>2017-02-07 10:17:57 UTC</pubDate>
      <lastBuildDate>2017-02-07 11:22:05 UTC</lastBuildDate>
      <webMaster>hello@padlet.com</webMaster>
      <image>
         <url>https://padlet-assets.s3.amazonaws.com/icons/Brightnessdown.png</url>
      </image>
      <item>
         <title>pitagora scopri  come  come calcolare  i lati di un triangolo retangolo</title>
         <author>abdileedekhissi</author>
         <link>https://padlet.com/abdileedekhissi/40yc1bldi8a1/wish/152088441</link>
         <description><![CDATA[<div>conosendo  2 lati</div>]]></description>
         <enclosure url="" />
         <pubDate>2017-02-07 11:07:07 UTC</pubDate>
         <guid>https://padlet.com/abdileedekhissi/40yc1bldi8a1/wish/152088441</guid>
      </item>
      <item>
         <title>Ragazzi buongiorno,oggi vi voglio sottoporre un problema.Un rettangolo ha l&#39;area di 4200 cm quadrati e una dimensione lunga 120 cm. calcola il perimetro di ciascuno dei due triangoli in cui esso rimane diviso da una diagonale. </title>
         <author>abdileedekhissi</author>
         <link>https://padlet.com/abdileedekhissi/40yc1bldi8a1/wish/152089033</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2017-02-07 11:10:05 UTC</pubDate>
         <guid>https://padlet.com/abdileedekhissi/40yc1bldi8a1/wish/152089033</guid>
      </item>
      <item>
         <title></title>
         <author>abdileedekhissi</author>
         <link>https://padlet.com/abdileedekhissi/40yc1bldi8a1/wish/152091187</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2017-02-07 11:22:00 UTC</pubDate>
         <guid>https://padlet.com/abdileedekhissi/40yc1bldi8a1/wish/152091187</guid>
      </item>
   </channel>
</rss>
