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      <title>Popcorn Discussions Week Ending 6/03/22 by Felix Mariano</title>
      <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1</link>
      <description>Write your response to the topic on every column as well as your reactions to other classmate comments</description>
      <language>en-us</language>
      <pubDate>2022-05-29 14:45:28 UTC</pubDate>
      <lastBuildDate>2022-06-03 21:46:05 UTC</lastBuildDate>
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         <title>maya</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206373993</link>
         <description><![CDATA[<div><strong>AE.EC=DE.EB</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:51:35 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206373993</guid>
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      <item>
         <title>Tiona </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206374100</link>
         <description><![CDATA[<div><strong>The formula for intersecting chords inside of a circle is AE⋅EC=DE⋅EB .</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:51:41 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206374100</guid>
      </item>
      <item>
         <title>Franky</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206375497</link>
         <description><![CDATA[<div><strong>AE⋅EC=DE⋅EB</strong>&nbsp;<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:52:48 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206375497</guid>
      </item>
      <item>
         <title>Jaden </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206375768</link>
         <description><![CDATA[<div><strong>The formula for intersecting chords inside of a circle is AE⋅EC=DE⋅EB .</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:53:02 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206375768</guid>
      </item>
      <item>
         <title>cipriano</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206379523</link>
         <description><![CDATA[<div><strong>The formula for intersecting chords inside of a circle is AE⋅EC=DE⋅EB . -google</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:56:18 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206379523</guid>
      </item>
      <item>
         <title>Chris</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206382752</link>
         <description><![CDATA[<div>theorem is a statement in elementary geometry that describes a relation of the four line segments created by two intersecting chords within a circle</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-05-31 16:58:58 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2206382752</guid>
      </item>
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         <title>Franky</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207790560</link>
         <description><![CDATA[<div>Both of them are circles.&nbsp;<br>One focuses on the top of the circle (circular)<br>And the other focuses on the side and top (sector)<br>(Wow I think this is the first time where I gave a serious answer) (look at google images)</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 17:01:09 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207790560</guid>
      </item>
      <item>
         <title>Fabian</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207791836</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. The area enclosed by a segment and the angle subtended by a segment is called a sector. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 17:02:23 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207791836</guid>
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      <item>
         <title>the area enclosed by a segment and the angle subtended by a segment is called a sector.</title>
         <author>zpolanco</author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207792050</link>
         <description><![CDATA[]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 17:02:35 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207792050</guid>
      </item>
      <item>
         <title>Zion</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207793863</link>
         <description><![CDATA[<div>You can compare and contrast a circular segment to a sector because they both take&nbsp; a portion of the circle </div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 17:04:10 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207793863</guid>
      </item>
      <item>
         <title>Jaden</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207794905</link>
         <description><![CDATA[<div>A segment is an interior region of a circle. The area enclosed by a segment and the angle subtended by a segment is called a sector. The area of the segment of a circle is determined by subtracting the triangle formed inside the sector from the sector which has the segment.</div><div><br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 17:05:08 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207794905</guid>
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      <item>
         <title>cipriano</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207794932</link>
         <description><![CDATA[<div><strong>the area enclosed by a segment and the angle subtended by a segment is called a sector.</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 17:05:10 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207794932</guid>
      </item>
      <item>
         <title>Kimora</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207811157</link>
         <description><![CDATA[<div><strong>The formula for intersecting chords inside of a circle is AE⋅EC=DE⋅EB .</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 17:18:51 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207811157</guid>
      </item>
      <item>
         <title>Kimora</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207811512</link>
         <description><![CDATA[<div><strong>the area enclosed by a segment and the angle subtended by a segment is called a sector.</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-01 17:19:10 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2207811512</guid>
      </item>
      <item>
         <title>Franky</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209214437</link>
         <description><![CDATA[<div>You could draw a line in the circle then calculated it&nbsp;<br>(?)</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:53:33 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209214437</guid>
      </item>
      <item>
         <title>Tiona</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209215313</link>
         <description><![CDATA[<div>You could calculate the area of a segment in a circle by doing (½) × r<sup>2</sup> (θ – Sin θ) which 0 would be the degrees.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:53:47 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209215313</guid>
      </item>
      <item>
         <title>Kimora </title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209216260</link>
         <description><![CDATA[<div>You could calculate the area of a segment in a circle by doing (½) × r<sup>2</sup> (θ – Sin θ) which 0 would be the degrees.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:54:39 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209216260</guid>
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      <item>
         <title>Cipriano</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209217240</link>
         <description><![CDATA[<div>If you know the radius, r, of the circle and you know the central angle, ϴ, in degrees of the sector that contains the segment, you can use this formula to calculate the area, A, of only the segment: <strong>A = ½ × r^2 × ((π/180) ϴ - sin ϴ)</strong></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:55:35 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209217240</guid>
      </item>
      <item>
         <title>Fabian</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209217489</link>
         <description><![CDATA[<div>You could calculate the area of a segment in a circle by doing (½) × r<sup>2</sup> (θ – Sin θ) which 0 would be the degrees.<br><br></div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:55:51 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209217489</guid>
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      <item>
         <title>Jaden A</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209218273</link>
         <description><![CDATA[<div>You could calculate the area of a segment in a circle by doing (½) × r<sup>2</sup> (θ – Sin θ) which 0 would be the degrees.</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-02 16:56:38 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2209218273</guid>
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      <item>
         <title>Tiona</title>
         <author></author>
         <link>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2210410188</link>
         <description><![CDATA[<div>The difference between sector and circular segment is the area enclosed by a segment and the angle subtended by a segment is called a sector. and a segment is an interior region of a circle.&nbsp;</div>]]></description>
         <enclosure url="" />
         <pubDate>2022-06-03 17:17:25 UTC</pubDate>
         <guid>https://padlet.com/felixmariano2/3owd6yxn8a1c4as1/wish/2210410188</guid>
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