Mathematics 203 by Harris Danial https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr Sequence en-us 2021-01-31 09:42:04 UTC 2021-02-08 04:32:26 UTC hello@padlet.com Even Numbers and Odd Numbers ekalkimi0401 https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1152357165
1. The list of even  numbers:0,2,4,6,8,10,12,14,16,18,20
2. Every even number is divisible by 2
3. The list of odd number :1,3,6,7,9,11,13,15,17,19,
4. Every odd number is not divisible by 2]]> 2021-02-02 08:00:44 UTC https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1152357165 ekalkimi0401 https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1152372403 • All even numbers end with the digits 0,2,4,6 or 8.
• All odd numbers end with the digits 1,3,5,7 or 9.]]> 2021-02-02 08:05:15 UTC https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1152372403 Quadratic Sequence harrisdanial2600 https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1152786332 How to find the nth term?

Note: The answer will always be in this form  = an² + bn + c

4, 15, 32, 55, 84

First step:
Find the difference from the 1st term until u get a constant difference.
     1st difference = 11, 17, 23, 29
     2nd difference = 6, 6, 6

Second step:
Divide the second difference by 2 and you will get the value of (a)
6÷2=3                   So the first term of the nth term is 3n²

Third step:
Substutute the number 1 to 5 into 3n²
n= 1, 2, 3, 4, 5
3n²=3, 12, 27, 48, 75

Fourth step:
Take the 3n² and the original number sequence (4, 15, 32, 55, 84) and work out the nth term of these numbers
3n²=3, 12, 27, 48, 75
Original sequence:4, 15, 32, 55, 84
Differences= 1, 3, 5, 7, 9
Now the nth term of these differences (2, 4, 6, 8, 10) is 2n -1.
So b = 2 and c = -1

Final step:
Write down your final answer in the form of an² + bn + c.
=3n² + 2n -1
]]> 2021-02-02 09:57:48 UTC https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1152786332 Cubic Sequence harrisdanial2600 https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1153445550 How to find the nth term?

Note: The answer will always be in this form  = an3 + bn² + cn+ d

0, 12, 10, 0, -12, -20

First step:
Find the difference from the 1st term until u get a constant difference.
     1st difference = 12, -2, -10, -12
     2nd difference =-14, -8, -2
     3rd difference =-6, 6

Second step:
Divide the third difference by 6 and you will get the value of (a)
6÷6=1                 So the first term of the nth term is n3

Third step:
Substitute the number 1 to 5 into n3 and find the difference between the original sequence and n3
n= 1, 2, 3, 4, 5
n3= 1, 8, 27, 64, 125, 216
s-n3=-1, 4, -17, -64, -137, -236

Fourth step:
Find the difference in s-n3
1st difference = 5, -21, -47, -73
2nd difference =--26, -26, -26
-26÷2= -13²

Fifth step:
Work out s-(n3-13² )

(n3-13² )= -12, -44, -90, -144, 200
s-(n3-13² )= 12, 56, 100, 144, 188
Common difference = 44

Final step:
12+ (n-1) 44 = 44n-44 = 44n + 32
Final answer = n3-13²+44n + 32]]> 2021-02-02 13:16:23 UTC https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1153445550 Fibonacci numbers ekalkimi0401 https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1157425502 0,1,1,2,3,5,8,13,21,34,55,89,......
1. In the above sequence of numbers, it begins with 0,1,1 and the numbers that follow are obtained by adding two numbers before it
2. This sequence of numbers is called Fibonacci Numbers]]> 2021-02-03 08:02:33 UTC https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1157425502 Pascal's triangle ekalkimi0401 https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1157435451 1. The following arrangement of numbers is known as the Pascal's Triangle
2. Each row begins and ends with the number 1 and it has one number more than the previous row.
3. To obtain the numbers in the next row, add the two numbers that are immediately above it in the previous row.

]]> 2021-02-03 08:05:21 UTC https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1157435451 Linear Sequences muhdimanrosdi17 https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1161371552 How to find the nth terms?

Example: Find the nth terms of the sequence
                      3,5,7,9

First step:
Find the difference of the sequences
The differences are always the number behind the n
So the nth term begins with 2n


Second step: 
Worked out what the previous number would be or you can say find the number before 3. 
= 1,3,5,7,9


Third step:
Add number 1 into the nth term formula
= 2n + 1

Final step:
Now check your answer if it correct. Check it with n = 1,2,3,4 and + 1

n = 1          2 x 1 + 1 = 3
n = 2          2 x 2 + 1 = 5
n = 3          2 x 3 + 1 = 7
n = 4          2 x 4 + 1 = 9

The answer is the same with the sequences given which are 3,5,7,9. So we're done with linear sequences



]]> 2021-02-03 23:18:06 UTC https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1161371552 Geometric Sequences muhdimanrosdi17 https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1162327781 How to find the nth terms?

Example: Find the ratio and the seventh terms of the sequences
                     2/9, 2/3, 2, 6, 18 

First step:
Divide the successive pairs of the terms as long as they are next to each other

(2/9) / (2/3) = 2/9 / 3/2 = 3
2 / (2/3) = 2/1 / 3/2 = 3
6/2 = 3
18/6 = 3

Second step: 
Find the ratio

The ratio is always 3, so r = 3


Third step:
Find the sixth terms and seventh terms

 a6 = 18 x 3 = 54
a7 = 54 x 3 = 162


Final step:
Rewrite your answer

Ratio = 3
Seventh terms = 162

Now done with geometric sequences. Thank You :)
]]> 2021-02-04 07:25:17 UTC https://padlet.com/harrisdanial2600/3dqb9m3o3rydvsbr/wish/1162327781