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      <title>2020-09-21 Collaboration on Hyperbolic Trig by TJ Middleton</title>
      <link>https://padlet.com/tj_middleton/2az7gnhmb48qf6cn</link>
      <description>Use this as a way to collaborate about getting GeoGebra to calculate the area  of the &quot;pink region&quot; from our notes, including making the area negative if the point goes below the x-axis. If you all can solve this together, you all get a free extra 4 (out of 4) in the gradebook. It&#39;s kinda a small bonus. At the very least, everyone must either post what they&#39;ve done so far as an attempt or make a couple of deep, helpful comments on the work of others. I feel that making an account on GeoGebra and then sharing a link to your work there is your best bet for showing classmates what you&#39;ve accomplished so far. Remember that insightful questions also show engagement in the task. If this is solved before class on Thursday, you get that extra free homework grade!</description>
      <language>en-us</language>
      <pubDate>2020-09-21 21:21:26 UTC</pubDate>
      <lastBuildDate>2025-04-17 21:44:48 UTC</lastBuildDate>
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         <author>saskiabauman</author>
         <link>https://padlet.com/tj_middleton/2az7gnhmb48qf6cn/wish/772931359</link>
         <description><![CDATA[<div>This is the first one I did which is just what we did in class:  https://www.geogebra.org/classic/afndqrc3<br>I was trying to get the integral, like I remember doing between functions last year, but the original equation wasn't a function, so I made it one: y=sqrt(x^2-1). I was able to find the area below the curve and then subtracted it from the whole triangular area to get the weird area we wanted (and multiplied by 2 because if I hadn't made it a function, the same area would be on the other side of the x-axis. This let me see the area at many different values for A, but I couldn't make the area negative. Here's my geogebra: https://www.geogebra.org/classic/ncy4g3dg<br>Third, I found the derivative of the hyperbola. I got dy/dx=x/y. I made a tangent line at A. My equation was y-y[A]=x[A]/y[A](x-x[A]). I don't really know what this tells me, but here's the geogebra: https://www.geogebra.org/classic/cp9s9ueu</div>]]></description>
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         <pubDate>2020-09-23 16:49:10 UTC</pubDate>
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         <title></title>
         <author>victoriademersseman</author>
         <link>https://padlet.com/tj_middleton/2az7gnhmb48qf6cn/wish/774461234</link>
         <description><![CDATA[<div>Here's my geogebra. I made the triangle like middy said. I wasn't really sure what to do about the other two sections but I kinda had a similar idea to saskia in that made you could use a function that is the top half of each branch, but I'm not really sure how. I am especially unsure about making it negative because even just the triangle area I made didn't go negative when I brought A below the X-Axis. https://www.geogebra.org/classic?lang=en . A question I have is whether Middy figured out how to do this himself or if he was shown how?</div>]]></description>
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         <pubDate>2020-09-24 03:10:15 UTC</pubDate>
         <guid>https://padlet.com/tj_middleton/2az7gnhmb48qf6cn/wish/774461234</guid>
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         <title></title>
         <author></author>
         <link>https://padlet.com/tj_middleton/2az7gnhmb48qf6cn/wish/774829356</link>
         <description><![CDATA[<div>Here's my graph of what we did in class. I'm not sure how to make the area negative. I was thinking if I move it below the x-axis that would work but it didn't seem to. Saskia went way in depth though and everything she did looks really good!</div>]]></description>
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         <pubDate>2020-09-24 06:42:38 UTC</pubDate>
         <guid>https://padlet.com/tj_middleton/2az7gnhmb48qf6cn/wish/774829356</guid>
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         <title></title>
         <author>branchdemersseman</author>
         <link>https://padlet.com/tj_middleton/2az7gnhmb48qf6cn/wish/775904313</link>
         <description><![CDATA[<div>Here's my Geogebra file: <br><a href="https://www.geogebra.org/classic/tewnmxft">https://www.geogebra.org/classic/tewnmxft</a><br>Like Victoria, I followed Middy's suggestion of seperating the are into three different regions, though I was only able to find the area of the triangular region. <br>I thought that I may be able to find the area by taking the integral of the function and multiplying by 2. However, I had trouble with this because I didn't convert it into a function.</div>]]></description>
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         <pubDate>2020-09-24 14:17:42 UTC</pubDate>
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