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      <title>MDM4U Unit3 Assignment by Acheron</title>
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      <language>en-us</language>
      <pubDate>2025-05-20 02:02:00 UTC</pubDate>
      <lastBuildDate>2025-05-20 03:19:55 UTC</lastBuildDate>
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         <title>Lesson 5</title>
         <author>raidenmeica</author>
         <link>https://padlet.com/raidenmeica/1aodxalvf490jmup/wish/3458286364</link>
         <description><![CDATA[<p><strong>Pascal’s Triangle Fundamentals</strong></p><ul><li><p><strong>Structure</strong>: Each term is the sum of the two terms directly above it. Rows start and end with 1.</p></li><li><p><strong>Term Notation</strong>: tn,r denotes the term in row n (starting from 0) at position r.</p><p><br/></p></li></ul>]]></description>
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         <pubDate>2025-05-20 02:20:57 UTC</pubDate>
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         <title>Lesson 5</title>
         <author>raidenmeica</author>
         <link>https://padlet.com/raidenmeica/1aodxalvf490jmup/wish/3458336438</link>
         <description><![CDATA[<p>Patterns in Pascal's Triangle</p><ol><li><p>Pascal's method</p><p>t(n+1,r+1)=t(n,r)+t(n,r+1)</p></li><li><p>Row sums</p><p>Row sum=2^n (n: the sum of nth row)</p></li><li><p>Divisibility</p><p>Find the divisibility of two terms within the Pascal's Triangle</p><p>Concepts: Odd-numbered rows (odd numbers: 1,3,5,7,...)</p><p>Even-numbered rows (even numbers: 2,4,6,8,...)</p><p>All rows that have x or more terms: Exclude 0~(x-2) rows</p></li><li><p>Triangular numbers</p><p>Finding the number of dots in a triangle (equilateral) with nth rows: t(n+1,2)</p></li><li><p>Perfect  Squares</p><p>n^2=t(n,2)+t(n+1,2)</p></li></ol>]]></description>
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         <pubDate>2025-05-20 02:42:43 UTC</pubDate>
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         <title>Lesson 6: Applications</title>
         <author>raidenmeica</author>
         <link>https://padlet.com/raidenmeica/1aodxalvf490jmup/wish/3458371475</link>
         <description><![CDATA[<p>Research question: Pathway problems</p><p>Conditions:</p><ol><li><p>Starting and ending points are defined</p></li><li><p>Only can move into 2 direction in one step</p></li></ol><p>Specific Applications</p><p>A: Path to spell a world: easy application of Pascal Triangle, the sum of value in the last row is the number of paths</p><p><br/></p><p>B: Checkerboard</p><p>Features: Limited area</p><p>There may be only one path to a grid. If so, only the data of the previous layer needs to be retained without adding them.</p><p>*Special circumstances: Blocked grid: Just skip them, there is only one path leading to the diagonally adjacent grids on the next layer.</p><p><br/></p><p>C: Paths in two locations</p><p>“Rhombus” Pascal's Triangle: Narrow-Wide-Narrow——The push-down principle remains unchanged</p><p>*Special circumstances: Impassable Road</p><p>Treat them as edges (see example)</p><p><br/></p>]]></description>
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         <pubDate>2025-05-20 02:58:35 UTC</pubDate>
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         <title>Example 1</title>
         <author>raidenmeica</author>
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         <pubDate>2025-05-20 03:19:54 UTC</pubDate>
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      <item>
         <title></title>
         <author>raidenmeica</author>
         <link>https://padlet.com/raidenmeica/1aodxalvf490jmup/wish/3458417105</link>
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         <pubDate>2025-05-20 03:20:07 UTC</pubDate>
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