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Gene G is the gene that is most likely being encoded with proteins that are essential to glycolysis. Because

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A. It would be Gene G, since it is present in all six tissue systems.
B. Tissues with high gene H mRNA levels can still manage to have no gene H protein by a negative feedback loop that is caused by the halt of translation of mR

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a. I would circle the arrow where it shows Gene Trp-t to mRNA.
b. if the deletion of mRNA were to happen, then the creation of enzyme

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Based on the data provided, the gene most likely to to encode a protein that is an essential component of glycolysis would be Gene G. The reason is because of how of how it tends to occur within all 6 tissues.

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(a). Gene G is the gene that is most likely to encode a protein that is an essential component of glycolysis because of the fact that it is not only the only gene present in all tissue’s, but because of the fact that it has high amounts of mRNA in the liver and moderate amounts in the Kidney and Pancreas, locations where glycolysis is present and occurs.

(b). It is possible that tissues such as the Kidney or Pancreas can have high levels of Gene H mRNA but not actual Gene H protein present because of the fact that specific mRNA arrived in said tissues through translation and movement across different cell membranes. That is to say

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a. The gene that is most likely to encode a protein that is an essential component of glycolysis is Gene G. This is due to how it can be found expressed in all six tissues.

b. The mRNA

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Gene G is most likely to encode a protein that is essential of glycolysis because it is found in all tissues.

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a. Gene G is most likely to encode a protein that is an essential component of glycolysis, this is because gene G is expressed an all tissue types.
b. because of interference in mRNA levels for Gene HH it could not have any gene H protein as it causes a negative feedback loop.

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(a) The gene that is most likely to encode a protein that is an essential component of glycolysis is Gene G because it is the only gene that is presented in all six tissues and glycolysis occurs in all six tissues as well.
(b)Tissues with high gene H mRNA levels can have no gene H protein

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it would be Gene G because it is the only one that

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a. Gene G would be the gene that is most likely to encode an essential protein for glycolysis. This is because the gene has mRNA present in every tissue.
b. In order for there to be tissues with high gene H mRNA levels yet no gene H proteins, there has to be a lack of translation that occurs from the gene H mRNA. The lack of translation means that the mRNA would not be able to be changed

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a) The gene that is most likely to encode a protein that is an essential component to glycolysis is Gene G. This is because mRNA is present in all the tissues of Gene G, and all tissues undergo glycolysis.

b) Tissues with high gene H mRNA levels can have no gene H protein if something prohibits mRNA from being translated. mRNA is important for protein synthesis; however, if there is a high presence of mRNA but it can't be translated, then proteins cannot be produced in the tissue.

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A. It would be Gene G, since it is present in all six tissue systems.
B. Tissues with high gene H mRNA

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a. The gene that is most likely to encode a protein that is an essential component of glycolysis is Gene G. Gene G is the only gene expressed in all of the tissues and glycolysis occurs in all of the tissues.
b. Tissues with high gene H mRNA levels can have no gene H protein because something could prohibit the mRNA from translating.

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1.  Circle the arrow of Gene Trp-t to mRNA. IAA would be the missing molecule if enzyme YUC was nonfunctional.

2. This would cause the transcription process to not create enzyme Trp-t because there was a deletion in the codon of the gene. As a result, we are not able to convert Tryptophan to I3PA and without I3PA, we can’t produce any IAA. This basically prevents any IAA production at all since we won’t be able to produce I3PA without a functioning Trp-t enzyme.

3. We can create a negative feedback loop where IAA acts as an inhibitor to enzyme YUC so that as more IAA is produced, less will be produced over time because of the inhibition eventually reaching the point where the IAA is capped. This doesn’t affect I3PA production at all yet limits the amount of IAA we can produce.

4. Rhizobacteria live in the nodules of the plant roots and they can produce IAA and convert it to nitrogen for the plants to use to eventually strengthen their roots which the Rhizobacteria benefits off of. They are helping each other by providing each other with a resource where plants get nitrogen and the bacteria get to live in nice roots while benefiting off on the carbon molecules in the roots. It’s a relationship that focuses on mutuality as they help each other directly.

5. Cheater bacterias are able to benefit off the other working bacterias from being able to live in the same roots and get the carbon molecules, while being able to conserve their energy for other things like reproduction instead of producing IAA. More cheater bacteria in the population or if majority of the bacterias were cheaters as then we would have less IAA production and nitrogen conversion thus since there’s less nitrogen going to the plants, the plants will reduce the amount of carbon fixation in the roots.

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A.it would be gene G since it is the only gene that is at the minimum moderately present in all tissues. and to that extent we know that every tissue goes through glycolosis in order to get a little bit of atp to work. since gene G is present in all tissues that also means that mRna is present in all of the tissues meaning that transcribing might happen in order to make other proteins it needs

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A.it would be gene G since it is the only gene that is at the minimum moderately present in all tissues. and to that extent we know that every tissue goes through glycolosis in order to get a little bit of atp to work. since gene G is present in all tissues that also means that mRna is present in all of the tissues meaning that transcribing might happen in order to make other proteins it needs

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a. The gene that is most likely to encode a protein that is an essential component of glycosis is gene G because in the chart you can see that gene g is listed in all 6 tissues and glycosis happens in those 6. Meaning that if gene g was not present in those tissues, it wouldn’t be able to complete glycosis

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a) Gene G is the most likely to encode a protein essential to glycolysis because regardless of the amount of its mRNA expression, it is present in all organs that contribute to the conversion of glucose to energy.
b) Tissues with high Gene H mRNA expression might not have high Gene H proteins because of interference in mRNA translation.

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a). Gene g is most likely to encode a protein component of glycolysis because the gene is present in all 6 tissues and glycolysis occurs in all 6 tissues.

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The arrow from Gene Trp-T to mRNA represents transcription on the template pathway.

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a) Gene g is most likely to encode a protein that is an essential component of glycolysis; this is because mRNA is present in all six tissues and we know that glycolysis occur also occur in all six tissues in the table.

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a) circle arrow from Gene Trp-T to mRNA. the molecule that would be absent if enzyme YUC is nonfunctional is IAA.
b) the deletion of one base pair in the fourth codon of the coding region of gene Trp-T would most likely stop the production of IAA. This is because the deletion/mutation would cause the Top-T enzyme to be translated inactive, therefore IAA would not be produced.
c) one feedback mechanism by which the cell could prevent the production of too much IAA limiting I3PA production is a negative feedback mechanism. negative feedback mechanisms would increase the amounts of IAA, which inhibits the production of enzyme YUC.
d)

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a) the arrow towards the mRNA represents transcription. If YUC doesn't work, IAA would not be present because it relies on enzyme YUC, which cannot be present if YUC isn't present. 

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a) the arrow towards the mRNA represents transcription. If YUC doesn't work, IAA would not be present because it relies on enzyme YUC, which cannot be present if YUC isn't present. 

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b) Changing TRP-T would change enzyme TRP-T because the enzyme TRP-T relies on TRP-T. Since the enzyme is different, the production of IAA would be stopped because the enzymes are now different.
c) This describes a

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a) Gene G is most likely to encode a protein that s an essential component of glycolysis because glycolysis occurs in all six tissues, and Gene G is the only gene expressed in all six tissues.

b) Tissues with high gene H mRNA levels can have no gene H protein because gene H mRNA is not translated.

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a. Gene G is most likely to encode a protein that is an essential component of glycolysis because it is the only gene that's expressed in all 6 tissues and glycolysis occurs in all those 6 tissues as well.
b.  Tissues with high gene H mRNA levels can have no gene H protein because the Gene H mRNA was not translated, so there is no Gene H protein.

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a) Gene G is most likely the gene that encodes a protein that is essential in glycolysis as it is in all of the different tissues. Glycolysis needs to take place in all cells and therefore the gene has to be present in all of the different tissues.

b) One reason why the tissue with high gene H mRNA levels do not have any gene H protein is if the H mRNA has not been used outside of the nucleus. If the H mRNA does not leave the nucleus than the protein would have never been made by the cell, but still have a high level of H mRNA.

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A. The transcription pathway would be the left hand-side with Gene Trp-T.
B. The deletion of one base pair in the fourth codon would most likely cause the production of IAA to decrease significantly because without the base codon, translation and synthesis wouldn't behave normally and cause either a significant decrease or a complete halt to the production of IAA.
B. One feedback mechanism that could prevent the over production of IAA without limiting the I3PA production would be the negative feedback loop because it allows for the regulation of IAA. Since I3PA isn't directly affecting the production of IAA, this feedback mechanism wouldn't affect the production of I3PA.
D. One advantage of bacteria producing IAA is

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b. The deletion of one base pair in the fourth codon of the coding region of gene Trp-T would most likely affect the production of IAA by decreasing the amount of IAA. That is because the production of IAA depends on the chemical reactions of both Enzyme Trp-T and Enzyme YUC. If the base pair which helps create the mRNA that creates the enzymes is deleted, then the enzymes would also decrease or disappear, and the chemical reaction would not be able to happen.
c. One feedback mechanism by which a cell could prevent production of too much IAA without limiting I3PA production is having the production of Enzyme YUC slow down once there is a maximum amount of IAA. If only Enzyme YUC is affected, then that would only prevent the chemical reaction from converting I3PA to IAA. The production of I3PA wouldn't be affected since the enzyme in charge of converting Tryptophan to I3PA is Enzyme Trp-T.
d.

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a) Gene G is probably most likely to encode a protein that is an essential component of glycolysis because Gene G is the only gene that is expressed within all these six tissues. All tissues undergo glycolysis, so the gene that is expressed in all these tissues is the only viable choice.
b) Tissues with high gene H mRNA levels can have no gene H protein perhaps due to an issue occurring within mRNA translation, preventing translation. If there wasn't any translation, then no functional protein will be made.

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a.)If enzyme YUC is not functional, then IAA will be absent 

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a.)If enzyme YUC is not functional, then IAA will be absent 

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B.) The deletion of of one base pair in the fourth codon will likley reduce IAA production. This is due to the fact that the mRNA translation would become heaivly altered or nonfuctional, meaning that Trp-enzyme would not be functional as well due to differnece in primary structure.
C.) In this case, we will need to utilize a negaitve feebackloop that would the presence of enzyme YUC in order to supress IAA production.
D.) The most liklely ecological relationship between plants and rhizobacteria is mutulaims. One advantage of bacteria producing IAA is that the root will flourhing in rpesence of IAA, increasing Rhizcobacteira habitat.

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a) Gene G is most likely going to be the gene which is involved with encoding a protein for glycolysis. Glycolysis is a necessary part of the process for every single cell and so a gene for the process would need to be present in every part of the body which gene g is.
b)If there is a negative feedback mechanism which stops the translation of mRNA into the gene H protein unless certain prerequisites occur then there could be a large amount of gene H mRNA but no gene H protein. This would be that there is an inhibitor which is, most likely, physically stopping translation but not stopping transcription and so the situation described occurs.