# data[].attributes.body
B=4m
H=3m
Rate of whitewashing =AED 7.5 per m2
LSA+AREA OF CEILING
={2*(l+b)h}+{l*b}
=74m2
Cost=AED 7.5*74
=555 AED

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Lateral surface area = 4(a)
=4(10)^2
=4 x (100)
=400

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LSA cube= 4 x 10 2                                        .    =4 x 100    . =400cm 2 .

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250h time 10 = total cost of painting which is 15000 therefore 2500h=15000therefore height is 15000divided by 25 =6

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250h time 10 = total cost of painting which is 15000 therefore 2500h=15000therefore height is 15000divided by 25 =6

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Time up boys

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Perimeter of rectangle =2(l+b)
2(l+b)=250
L+b=125
LSA of cuboid =2h(125)=250h
Cost =15000/10
Cost =1500
250h=1500
H=1500/250
H= 6 cm

Therefore the height of the hall is 6 cm

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Group 3

Perimeter = 2(l + b)=250m
Rate = 10 rupees per m^2
Cost = 15000 rupees

LSA of a cuboid = 2(l + b)h
= 250h

Cost of painting 4 walls = 250h x 10 rupees = 2500h
=15000 rupees

Therefore, h = 15000/2500
= 6m

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(group 1)
L.S.A
CUBE= 4 (a)
= 4 (10)^2
= 4(100)
= 400 cm

CUBOID= 2(l+b)h
= 2(12+10)8
= 44×8
= 352 cm

Therefore cube has a larger lateral surface of 400cm

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naeem,dalvin,shivadatt,alan,
aidan, aadhi,athul,joseph,
joshua ,mithun,noel,steve , fazalu .
Area of four walls = 2lh + 2bh = 2(l + b) h

Perimeter of the floor of hall = 2(l + b)

Perimeter of the floor of hall = 250 m
Therefore, 2(l + b) = 250 mPutting this value in the formula of Area of four walls we get,

Area of four walls = 2(l + b) h

Area of four walls = 250h m ²

Cost of painting per m² area = Rs 10

Cost of painting 250h m² area = Rs (250h × 10)

= Rs 2500h

However, it is given that the cost of painting the walls is Rs 15000

15000 = 2500h
1500/2500
150/250
h=6

# data[].attributes.headline
Noel Thomas Daniel (9-M) Area of four walls = 2lh + 2bh = 2(l + b) hPerimeter of the floor of hall = 2(l + b)Perimeter of the floor of hall = 250 mTherefore, 2(l + b) = 250 mPutting this value in the formula of Area of four walls we get,Area of four walls = 2(l + b) hArea of four walls = 250h m2Cost of painting per m2 area = Rs 10Cost of painting 250h m2 area = Rs (250h × 10)= Rs 2500hHowever, it is given that the cost of painting the walls is Rs 1500015000 = 2500h1500/2500150/

# data[].attributes.subject
Noel Thomas Daniel (9-M) Area of four walls = 2lh + 2bh = 2(l + b) hPerimeter of the floor of hall = 2(l + b)Perimeter of the floor of hall = 250 mTherefore, 2(l + b) = 250 mPutting this value in the formula of Area of four walls we get,Area of four walls = 2(l + b) hArea of four walls = 250h m2Cost of painting per m2 area = Rs 10Cost of painting 250h m2 area = Rs (250h × 10)= Rs 2500hHowever, it is given that the cost of painting the walls is Rs 1500015000 = 2500h1500/2500150/

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L.S.A
Cube= 4 x (10)^2
= 4 x 100
= 400m^2

Cuboid= 2 (12 + 10) x 8
= 44 x 8
=  352m^2

= The cube has the greater lateral surface by 48m

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The cube box with each edge 10 cm wide has more LSA than the other cuboidal box.
LSA OF CUBE = 400
LSA OF CUBOID = 384

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LSA of cube = 400
LSA of cuboid = 352

Therefore LSA of cube is greater by 48 cm

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L.S.A of cube=4a² =4x(10)² =400cm² L.S.A if cuboid=2(l+b)h =2x(12+10)x8 =360cm² => L.S.A of cube >L.S.A of cuboid by 40cm²

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CUBE

LSA 4a^2
40cm^2
400cm

CUBOID

LSA 2(l+b)h
2(12+10)8
44×8
352cm

Therefore cube has a larger LSA of 400cm

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Shazal Shakir

The question asks us to compare the LSA's of both cube and the cuboid.

LSA of cube = 4a^2
= 4 x 10^2
= 4 x 100
= 400cm^2

LSA of cuboid = 2 x (l+b) x h
= 2 x (5+4) x 3
= 2 x 9 x 3
= 18 x 3
= 54cm^2

Therefore we can conclude that the cubical box has a larger LSA by 500-54
= 446cm^2

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Lateral surface area = 2 x height (length + wide)
perimeter = 2( length + width)
length + wide = 125
area costing of
lateral surface are painting = 15000/10=1500
m^2

height =1500/250=6 m

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The L.S.A. of the cube is 400 cm²
The L.S.A. of the cuboid is 352 cm²
Therefore the L.S.A. of the cube is 48 cm²cm bigger than the cuboid

The calculations
L.S.A. OF THE CUBE =4 × a²
=4×10×10=400
L.S.A. of the cuboid = 2( l+b ) h
=2 (12+10) 8
= 44 × 8 = 352

# data[].attributes.body
Perimeter: 250 m
lateral surface area: 2h (l + b)
= 250 h
Cost of painting: 10 x 250h
Cost of painting= 2500h
2500h = 15000
h= 15000/2500
h = 6 metres

- BY: Group 3 Leader - Dalvin Thomas

# data[].attributes.body
LSA of Cube :-  4a^2
= 4 x 10 ^2
= 4 x 100
= 400 cm^2
LSA of Cuboid :- 2 (lh + bh)
= 2 ( 12x8 + 10x8 )
= 2 ( 96 + 80)
=  2 x (176)
= 352 cm^2

Therefore the cube has more LSA than the Cuboid by 48cm^2 .

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GROUP  1                                 Qn5. A cubical box has each edge 10cm and another cuboidal box has 12 cm long 10cm wide and 8 cm high. Which box has the greater lateral surface area and by how much?   

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GROUP  1                                 Qn5. A cubical box has each edge 10cm and another cuboidal box has 12 cm long 10cm wide and 8 cm high. Which box has the greater lateral surface area and by how much?   

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Qn 2.

The length, breadth and height of a room are 5m,4m and 3m respectively. Find the cost of white washing the walls of the room and the ceiling at the rate of  AED 7.50 per m2

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Length=5m
Breadth=4m
Height=3m
Rate of whitewash=7.50AED per m²
LSA+l*b=4 walls of the room+ceiling.
LSA+l*b=2*(l+b)h+l*b
=2*(5+4)*3+5*4
=2*9*3+20
=54+20
=74m
LSA+l*b=74m²
74*7.50AED=Price of whitewashing.
=555AED for whitewshing all four walls+celing.

Answer=555AED for whitewshing all four walls+celing.

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Qn 3.

The floor of a rectangular hall has a perimeter 250 m.If the cost of painting the four walls at the rate of AED 10  per m2 is AED 15000, find the height of the hall.