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These are two possible methods:

Method 1:

BQ//OQ and BQ:OA = 3:2. Hence, height of triangle BOQ : height of triangle YOA = 3:2.

How to see this: Draw the heights to the bases BO and YO. Look at the similar right angle triangles.

Method 2:

Notice angle QBO = 180 deg - angle AOB

Use area of triangle = 0.5 x a x b sin C

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These are two suggested methods. Do share if you have found any other methods :)

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You may make use of the above concept to solve (d).

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1. Get into groups of 4.

2. Do and discuss solutions to the questions in PS 5.7.

3. As a group, post the solutions to each question under each section.

4. You are welcome to provide encouragements to other groups or suggest constructive improvements in other groups's solutions.