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(i)520=(2x2x2)x5x13

1600=(2x2x2x2x2x2)x(5x5)

LCM=(2x2x2x2x2x2)x(5x5)x13

=20800

(ii)HCF=(2x2x2)x5

=40

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The task: Textbook 1A REVISION EXERCISE A1

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The task: Textbook 1A REVISION EXERCISE A1

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There are altogether 5 questions.

Each member of the group shall take charge of 1 question - the group shall discuss who will be in-charge of which question.

1. You will refer to the question in your textbook

2. Attempt the question in your notebook

3. Label the question clearly when you post your work

4. Remember to indicate your name

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Instructions to post in your group

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Show your working clearly.

Use either factor tree or long division to find the prime factorisation.

Express the numbers in index notation.

Use INDEX NOTATION to find the answers.

1(a) [3m]

1(b) [3m]

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2(i) [1m]

2(ii) [2m]

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Show your working clearly.

1(a) [2m]

1(b) [2m]

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Show your working clearly.

Use either factor tree or long division to find the prime factorisation of each number.

Show how you apply the concept of roots to find the answers

2(a) [3m]

2(b) [3m]

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Show your working clearly.

Use either factor tree or long division to find the prime factorisation of each number.

Show how you apply the concept of HCF and LCM to find the answers

3 [4m]

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a) 42 = 2 x 3 x 7

66 = 2 x 3 x 11

78=2x3x13

Ans: 2 x 3 = 6

b) 9=3²

16=2⁴

18= 2 x 3²

Ans: 2⁴ x 3² = 144

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42 = 2 × 3 × 7

66 = 2 × 3 × 11

78 = 2 × 3 × 13

2 and 3 appears in all 3 numbers, so the HCF is 2 x 3 = 6

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Revision A2 Q2 - Using prime factorisation, find the value of each of the following.

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Revision A2 Q2 - Using prime factorisation, find the value of each of the following.

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(a) -√10816

(b) ∛13824

(a): 10816 = 2x2x2x2x2x2x13x13 = (2x2x2x13)(2x2x2x13) = (2x2x2x13)² = 104² ∴√10816 = 104

∴ -√10806 = -104 (ans)

(b): ∛13824 = 2x2x2x2x2x2x2x2x2x3x3x3 = (2x2x2x3)(2x2x2x3)(2x2x2x3) = (2x2x2x3)³ = 24³

∴∛13824 = 24 (ans)

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Last checked: 1 Feb 5.30am

Group 1: 19 points

Group 2: STAY BACK - Missing Revision A1 Q1, Q2; Revision A2 Q2

Group 3: STAY BACK - Missing Revision A2 Q1

Group 4: STAY BACK - Missing Revision A1 Q2

Group 5: 25 points (complete submission)

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(a) -√10,816

10,816 = 2^6 × 13^2

√10,816 = 2^3 × 13 = 8 × 13 = 104

-√10,816 = -104

(b) ∛13,824

13,824 = 2^9 × 3^3

∛13,824 = 2^3 × 3 = 8 × 3 = 24

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Denzel (12)

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LCM(520, 1600) = 2^6 x 5^2 x 13(a)

HCF(520, 1600) = 40

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part a) -104

part b) 24