# data[].attributes.body
a0
b +3
c+2
D -2
e 0
f +3

# data[].attributes.body
CS2 c=4, s=-2
BrF3 Br=3, F=-1
H2SO4 h=5+

# data[].attributes.body
HClO4-  +7
ClO3-     +5
ClO- +1
Cl2 0
Cl-          -1
HCl         -1

# data[].attributes.body
Cl2(0
HCl(-1
ClO3-(+5
ClO-(+1
Cl-(-1
HClO4(+7

HCl=Cl-<Cl2<ClO-<ClO3-<HClO4

# data[].attributes.body
HClO4
ClO3-
ClO-
HCl , -Cl
Cl2

# data[].attributes.body
-1 to -2
Reduction

2Cr + 7(-2) = -2
Cr= +6
Reduction

Neither

Reduction
R +6 TO +4

# data[].attributes.body
H=no change
O=reduced
Cr=reduced
Cr=no change
S=reduced

# data[].attributes.body
H2O2 O reduce H neither
Cr2O72- Cr reduce
Cr2O72- Cr oxidise O neither
SO42- S reduce O neither

# data[].attributes.body
1-R
2-R
3-N
4-R

# data[].attributes.body
Cl2(g)+2I-(aq)-->2Cl-(aq)+I2(aq)
Chlorine's oxidation number decreases from 0 to -1, it gains an electron, it is reduced. Iodine's oxidation number increases from-1 to 0, it loses an electron, it is oxidised.

2Na(s)+Cl2(g)-->2NaCl(s)
Sodium's oxidation number increases from 0 to +1, it loses an electron, it is oxidised. Chlorine's oxidation number decreases from 0 to -1, it gains an electron, it is reduced.

H2(g)+Cl2(g)-->2HCl(g)

Hydrogen's oxidation number increases from 0 to +1, it loses an electron, it is oxidised. Chlorine's oxidation number decreases from 0 to -1, it gains an electron, it is reduced.

# data[].attributes.body
Mg is oxidized +2 
Cu is reduced -2
Redox reaction 

Cl is is reduced -1
I is oxidaized +1
Redox reaction


2Na + Cl2 = 2NaCl
Na= 0  Na= +1 ( Oxidized)
Cl= 0   Cl = -1 (Reduced)
REDOX


H2+ Cl2 = 2HCl
H=0 = H=+1  ( oxidized)
Cl =0 Cl = -1 ( reduced)
redox reaction

# data[].attributes.body
Mg=oxidise
Cu=reduce
Cl=oxidise
I=reduce
Na=oxidise
Cl=reduce
H=oxidise
Cl=reduce

# data[].attributes.body
1-Cl redused  and I oxidised
2- Cl redused and Na oxidised
3- Cl redused and H oxidised
and all of them is redox

# data[].attributes.body
Mg oxidise
Cu2+ reduce
Cl2 reduce
I- oxidise
Na oxidise
Cl2 reduce
H2 oxidise
Cl2 reduce

# data[].attributes.body
CS2
C= +4

BrF3 =
Br + 3f =0
Br + 3(-1) =0
Br= +3

PCl4+
P+4(-1) = 1
P-4 = +1
P+-5

H2SO4
S= + 6

SOCl2
S= +4

# data[].attributes.body
CS2
C=+4
BrF3
Br=+3
PCl4+
p=+5
H2SO4
S=+6
SOCl2
S=+4

# data[].attributes.body
CS2: C+2S=0
C+2(-2)=0
C=4

BrF3: Br+3F=0
Br+3(-1)=0
Br=+3

PCl4+: P+4Cl=+1
P+4(-1)=+1
P=+5

H2SO4: 2H+S+4O=0
2(-1)+S+4(-2)=0
-2+S-8=0
S=10

SOCl2: S+O+2Cl=0
S+(-2)+2(-1)=0
S=+4

# data[].attributes.body
C+2S=0
C=+4
Br+3F=0
Br=+3
P+4Cl=+1
P=+5
2H+S+4O=0
S=+6
S+O+2Cl=0
S=+4

# data[].attributes.body
1)CS2 = 0
C+2S=0
C+2(-2)=0
C=+4
2)BrF3=0
Br=+3
3)PCl4+=+1
P=+5
4)H2SO4=0
(+1)2+S+(-2)4=0
S=+6
5)SOCl2=0
S+(-2)+2(-1)=0
S=+4

# data[].attributes.body
CS2: C+4 S-2
BrF3: Br+3 F-1
PCl4: P+4 Cl-1
H2SO4: H+1 S-6 O-2
SOCl2: S+4 O-2 Cl-1

# data[].attributes.body
S2O32-: 2S+3O=-2
2S+3(-2)=-2
2S-6=-2
2S=+4
S=+2
S4O62-: 4S+6O=-2
4S+6(-2)=-2
4S-12=-2
4S=+10
S=+10/4
S=+2.5

# data[].attributes.body
a. +4
b. -3
c. +4
d. -3
e. +7
f. +7
g. +5
h. +3

# data[].attributes.body
N=+3
N=-3
S=+2
S=+2.5

# data[].attributes.body
N+4H = +1
N+4(1) = 1
N= -3

NO2-
N+2(-2) = -1
N-4 = -1
N= +3

S2O3 2-
2S+3O = -2
2S + 3(-2) = -2
2S - 6 = -2
s= +2

S4O6 2-
S4 + O6(-2) = 2
S4 = 10
S= -0/4 = 5/2

# data[].attributes.body
NH4 + = -3
NO2 - = +3
S2O3 2- = +2
S4O6 2- = +2.5

# data[].attributes.body
-3
+3
+2
+5/2

# data[].attributes.body
a)0
b)3
c)2
d)-2
e)0

# data[].attributes.body
C = 0
O2- = 2-
Fe3+ = 3+
He = 0
Fe2+ = 2+
Al3+ = 3+

# data[].attributes.body
a. 0
b. +3
c. +2
d. -2
e. 0
f. +3

# data[].attributes.body
0
+3
+2
-2
0
+3

# data[].attributes.body
a) C = 0
b) Fe3+ = 3+
c) Fe2+ = 2+
d) O2- = -2
e) He = 0
f) Al3+ = 3+

# data[].attributes.body
a)0
b)3+
c)2+
d)2-
e)0
f)3+

# data[].attributes.body
0
+3
+2
-2
0
+3

# data[].attributes.body
HClO₄→+7
ClO₃⁻→+5
ClO⁻→+1
Cl₂→0
Cl⁻, HCl→-1

# data[].attributes.body
HClO4
ClO3-
ClO-
Cl2
Cl-, HCl

# data[].attributes.body
HClO4=7
ClO3(-)=5
ClO(-)= 1
Cl2=0
HCl=-1 ,Cl(-)= -1

# data[].attributes.body
HCl=Cl^-<Cl2<ClO^-<ClO3^-<HClO4

# data[].attributes.body
cl2  Cl=0
HCl Cl=-1
ClO3  Cl=5
ClO-    Cl=1
HClO4  Cl=7

# data[].attributes.body
1) H ₂ O ₂→O 2
The oxidation number of O2 in H2O2 is -1 and the oxidation number of O2 is 0. The oxidation number has changes from -1 to 0, which means that O has lose 1 electron during the reaction. Therefore, the reaction involves oxidation.

2) H2O2→H2O
The oxidation number of O in H2O2 is -1 while the oxidation number of O in H2O is -2. The oxidation number has changed from -1 to -2, which means hat 0 has gained 1 electron. Therefore, the reaction involves reduction.
3) Cr ₂ O ₇ ²⁻→CrO ₄ 2-
The oxidation number of Cr in Cr2O72- is +6 while the oxidation number of Cr in CrO42- is +6. There are no change in the oxidation number of Cr.
4)SO ₄ ²⁻→SO 2
The oxidation number of S in SO₄ ²⁻ is +6 while the oxidation number of S in SO₂ is +4. The oxidation number  changes from +6 to +4, which mean that S has gained 2 electrons. Therefore, the reaction involves reduction.

# data[].attributes.body
H2O2→O2
The oxidation number of O is changed from -1 in H2O2 to 0 in O2 which has increased. This is an oxidation.

H2O2→H2O
The oxidation number of O is changed from -1 in H2O2 to -2 in H2O which has decreased. This is a reduction.

(Cr2O7)2-→(CrO4)2-
The oxidation number of Cr is changed from+6 in (Cr2O7)2- to +6 in (CrO4)2- which is unchanged. So is neither.

SO42- —>  SO2
The oxidation number of S is changed from +6 in SO42- to +4 in SO2 which has decreased. So this is reduction .

# data[].attributes.body
H2O2–> O2:  The oxidation number of O  is increased from -1 in H2O2 to 0 in O2 so it is oxidation.
H2O2–> H2O: The oxidation number of O decreased from -1 in H2O2 to -2 in H2O so it is reduction.
Cr2O7(2-)—>CrO4(2-): The oxidation number of Cr remain unchanged so it is neither oxidation or reduction.
SO4(2-)—>SO2: The oxidation number of S decreased from +6 in SO4(2-) to +4 in SO2 so it is reduction.

# data[].attributes.body
H2O2->O2: O
H2O2->H2O: R
Cr2O7^2- ->CrO2-: N
SO4^2- -> SO2: R

# data[].attributes.headline
Jacy: Defining Oxidized and Reduced Elements

# data[].attributes.subject
Jacy: Defining Oxidized and Reduced Elements

# data[].attributes.body
1) Mg(s) + Cu2+(aq)→ Mg2+(aq) + Cu(s)
In the equation above, the oxidation number of Mg has changed from 0 to 2+, which means that Mg has lose 2 electrons in the reaction. On the other hand, the oxidation number of Cu has changed from 2+ to 0, which means the Cu has gained 2 electrons in the reaction. Therefore, Mg is oxidized and Cu is reduced and redox occured.
2) Cl ₂(g) + 2I⁻(aq)→ 2Cl⁻(aq) + I ₂(aq)
In the reaction, the oxidation number of Cl has changed from 0 to -1, which means that Cl has lose 1 electron during the reaction. On the other hand, the oxidation number of I has changed from -1 to 0, which means that I has gained 1 electron during the reaction. Therefore, Cl is reduced and I is oxidized and redox occured.
3) 2Na(s) + Cl2(g)→ 2NaCl(s)
In the reaction, the oxidation number of Cl has changed from -1 to 0, which means that Cl has gained 1 electron during the reaction. On the other hand, the oxidation number of Na has changed from 0 to +1, which means that I has lose 1 electron during the reaction. Therefore, Cl is reduced and Na is oxidized and redox occured.
4) H ₂(g) + Cl ₂(g)→2HCl(g)
In the reaction, the oxidation number of H2 changed from 0 to +1, which means that H has lose 1 electron during the reaction. On the other hand, the oxidation number of Cl changes from 0 to -1, which means Cl has gained 1 electron during the reaction. Therefore, H is oxidized and Cl is reduced and redox occured.

# data[].attributes.body
O
R
N
R

# data[].attributes.body
The oxidation number of Mg is changed from 0 in Mg to +2 in Mg2+. The oxidation number has increased which shows Mg is oxidized.
The oxidation number of Cu is changed from +2 in Cu2+ to 0 in Cu. The oxidation number has decreased which shows Cl is reduced.
Therefore, Redox occurs.

The oxidation number of Cl is changed from 0 in Cl2 to -1 in Cl-. The oxidation number has decreased which shows Cl is reduced.
The oxidation number of I  is changed from -1 in I- to 0 in I2. The oxidation number has increased which shows I is oxidized.
Therefore, Redox occurs.

The oxidation number of Na is changed from 0 in Na to +1 in NaCl. The oxidation number has increased which shows Na is oxidized.
The oxidation number of Cl  is changed from 0 in Cl2 to -1 in Cl-. The oxidation number has decreased which shows Cl is reduced.
Therefore, Redox occurs.

The oxidation number of H2 is changed from 0 in H2 to +1 in HCl. The oxidation number has increased which shows H is oxidized.
The oxidation number of Cl is changed from 0 in Cl2 to -1 in Cl-. The oxidation number has decreased which shows Cl is reduced.
Therefore, Redox occurs.

# data[].attributes.body
Cl reduction
I oxidation

Na oxidation
Cl reduction

H oxidation
Cl reduction

# data[].attributes.body
The oxidation number of Na increase from 0 in Na to +1 in NaCl so it is oxidized. The oxidation number of Cl is decreased from 0 in Cl2 to -1 in NaCl so it is reduced.
The oxidation number of H increased from 0 in H2 to +1 in HCl so it is oxidized. The oxidation number of Cl is decreased from 0 in Cl2 to -1 in HCl so it is reduced.

# data[].attributes.body
Mg oxidized
Cu2+ reduced
Cl2 Reduced
2I- Oxidized
Na Oxidized
Cl2 Reduced
H2 Oxidized
Cl2 reduced

# data[].attributes.body
Cl: reduction
T: oxidation

cl:reduction
Na: oxidation

Cl: reduction
H :oxidation

# data[].attributes.body
Cl- reduction
I- oxidation

Na- oxidation
Cl- reduction

H- oxidation
Cl-reduction

# data[].attributes.body
P= +3
CL=-1

N=+3
CL= -1

Br=+3
F=-1

P=+5
CL= -1

H=+1
S= +6
0= -2

# data[].attributes.body
p(+3) +3CL(-1)
N(-3)+3(-1)
Br(-3)+3F(1)
P(4)+4Cl(-1)
2H(1)+S(6)+4O(-2)
Mg(6)+c(0)+3O(-2)

# data[].attributes.body
PCl3- P +3, Cl -1
NCl3- N +3, Cl -1
BrF3- Br +3, F -1
PCl4+- P +5, Cl -1
H2SO4- H +1, S +6, O -2
MgCO3- Mg +2, C +4, O -2
SOCl2- S +4, O -2, Cl -1

# data[].attributes.body
PCl3: Cl=-1, P=+3
NCl3: Cl=-1, N=+3
BrF3: F=-1, Br= +3
PCl4(+): Cl=-1, P= +5
H2SO4: O=-2, H=+1, S=+6
MgCO3: O=-2, Mg=+2, C=+4
SOCl2: Cl=-1, O=-2, S= +4

# data[].attributes.body
PCl₃: P→+3 ; Cl→-1
NCl₃: N→+3 ; Cl→-1
BrF₃: Br→+3 ; F→-1
PCl₄⁺: P→+3 ; Cl→-1
H₂SO₄: H→+1 ; S→+6 ; O→-2
MgCO₃: Mg→+2 ; C→+4 ; O→-2
SOCl₂: S→+4 ; O→-2 ; Cl→-1

# data[].attributes.body
PCl3: P=+3 Cl=-1
NCl3: N=+3 Cl=-1
BrF3: Br=+3 F=-1
PCl4+: P=+5 Cl=-1
H2SO4: H=+1 S=+7 O=-2
MgCO3: Mg=+2 C=+4 O=-2
SOCl2: S=+4 O=-2 Cl=-1

# data[].attributes.body
P +3 Cl -1
N +3 Cl -1
Br +3 F -1
P +5 Cl -1
H +1 S +6 O -2
Mg +2 C +4 O -2
S +4 O -2 Cl -1

# data[].attributes.body
a) +4
b) +7
c) +2.5

# data[].attributes.body
N=+4
I=+7
S= +2
S=+2.5
Mn=+6

# data[].attributes.body
N=+4
I=+7
S=+2
S=+2.5
Mn= +6

# data[].attributes.body
N= 4
I: 7
S= 2
S=5/2
Mn= 6

# data[].attributes.headline
Jacy: Oxidation State of Highlighted Elements

# data[].attributes.subject
Jacy: Oxidation State of Highlighted Elements

# data[].attributes.body
c) NO₂: N→+4
e) IF₇: I→+7
j) S ₂O₃ ²⁻: S→-2
k) S ₄O₆ ²⁻: S→+2.5
l) MnO₄ ²⁻: Mn→+6

# data[].attributes.body
N in NO2=4
I in IF7=7
S in S2O3(2-)=2
S in S4O6(2-)=2.5
Mn in MnO4(2-)=6

# data[].attributes.body
N -4
I +7
S +2
S +2.5
Mn +6

# data[].attributes.body
+3
+2
-2
0
+3

# data[].attributes.body
a) 0
b)+3
c)+2
d)-2
e)0
f)+3

# data[].attributes.body
c: 0
Fe(3+): +3
Fe(2+): +2
O(2-): -2
He: 0
Al(3+): +3

# data[].attributes.body
a) 0
b) +3
c) +2
d) -2
e) 0
f) +3

# data[].attributes.body
C 0
Fe3+ 3+
Fe2+ 2+
O2- 2-
He 0
Al3+ 3+

# data[].attributes.body
a)C: +4
b)Fe3+: +3
c)Fe2+: +2
d)O2-: -2
e) He: 0
f) Al3+: +3

# data[].attributes.body
HCl, Cl-, Cl2, ClO-, ClO3, HClO4

# data[].attributes.body
HCl=Cl- < Cl2 < ClO- < ClO3- < HClO4

# data[].attributes.body
Cl-, HCl < Cl2 < ClO- <ClO3- < HClO4

# data[].attributes.body
HClO4
CLO3
ClO
Cl2
CL-/HCl

# data[].attributes.body
Cl-,HCL < Cl2 < CLO-  < ClO3 - < HClO4

# data[].attributes.body
H2O –> H2O
H doesn't change
O is reduction since number decreases

Cr207 --> Cr3+
Cr 6+ --> 3+
Reduction

Cr207(2-) --> Cr04(2-)
Cr neither, does not change

# data[].attributes.body
H2O2 -> H20
(+1) (-1) --> (+1)(-2)
H doesn't change
O is reduction

Cr2O7(2-) --> Cr3+
Cr(6+) --> (3+) is reduction

Cr2O7(2-) --> CrO4(2-)
Cr does not change

# data[].attributes.body
the oxidation number of O decreases from -1 to -2. it involves reduction only.
the oxidation number of Cr decreases from +6 to +3. it involves reduction.
the oxidation number of Cr remains unchanged. it involves neither.
the oxidation number of S decreases from +6 to +4. it is reduction.

# data[].attributes.body
1. O
2. R
3. R
4.O
5. O
6. R
7. R
8. N
9. R

# data[].attributes.body
R O in H2O2 -1 to in H2O -2
R Cr in Cr2O72- +6 to in Cr+3 +3
N Cr in Cr2O72- +6 to in CrO42- +6
R S in So42- +6 to in SO2 +4

# data[].attributes.body
H2O=R
Cr=O
CrO4=O
SO2=R

# data[].attributes.body
oxidized: Mg from 0 to +2; reduced: Cu from +2 to 0
oxidized: I from -1 to 0; reduced: Cl from 0 to -1
oxidized: Na from 0 to +1; reduced: Cl from 0 to -1
oxidized: H from 0 to +1; reduced: Cl from 0 to -1

# data[].attributes.body
Na, H, Mg, I are oxidized.
Cl, Cu are reduced.

# data[].attributes.body
Mg is oxidized 0 to +2, Cu is reduced 2+ to 0
Cl is reduced 0 to -1, I is oxidized -1 to 0
Na is oxidized 0 to +1, Cl is reduced to 0 to -1
H is oxidized 0 to +1, Cl is reduced 0 to -1

# data[].attributes.body
NH4+= 1
NO2-= -1
S2O3(2-)=-2
S4S6(2-)= +2

# data[].attributes.body
CS2=+2
-1
-1

# data[].attributes.body
CS2 - C=(+4) S= (2-)
BrF3  Br=(3+) F=(1-)
PCl4+  P=(5+) Cl =(1-)
H2SO4 H=(1+) S=(+6) O=(2-)
SOCl2  S=(4+) O=(2-) Cl= (-1)

# data[].attributes.body
1. CS2, C =+4, S =-2
2. BrF3, Br =+3, F =-1
3.PCl4+, P = +5, Cl = -1
4. H2SO4, H = +1, S= +6, O = -2
5.SOCl2, S = +3, O = -2, Cl = -1

# data[].attributes.body
CS2: C=-4, S=2
BrF3: Br+3, F=-1
PCl: P=1, Cl= -1
H2SO4: H=3,S=6,O=-1
SOCl2: S=-4,O=-4,Cl=2

# data[].attributes.body
CS2) C is +4, S is -2
BrF3) Br is +3, F is -1
PCl4) P is +5, Cl is -1
H2SO4) H is +1, S +6 and O -2
SOCL2) S +4 O is -2 and Cl is -1

# data[].attributes.body
C n S in CS2 = +4 n -2
Br n F in BrF3 = +3 n -1
P n Cl in PCl4+ =+5 n -1
H n S n O in H2SO4 = +1 n +6 n -2
S n O n Cl in SOCl2 = +4 n -2 n -1

# data[].attributes.body
CS2: C=+4/ S=-2
BrF3: Br=+3/ F=-1
PCl4+: P=+5/ Cl=-1
H2SO4: H=+1/ S=+6/ O=-2
SOCl2: S=+4/ O=-2/ Cl=-1

# data[].attributes.body
S=10/4=+2.5

# data[].attributes.body
NO2- is +3
NH4+ is +4
S2O2 2- is +2
S4O6 2- is +2.5

# data[].attributes.body
NH4(+)  = 3+
NO2(-)   = 5+
S2O3(2-)  =3+
S4O6(2-)  =2.5+

# data[].attributes.body
1. NH4 + = -4
2. NO2 - = +3
3. S2O3 2- = +2
4. S4O6 2-= +2.5

# data[].attributes.body
N in NH4+ = -5
N in NO2- = +3
S in S2O32- = +2
S in S4O62- = +2.5

# data[].attributes.body
a) 0 b) +3 c) +2 d) -2 e)0 +3

# data[].attributes.body
a) 0
b) +3
c) +2
d) -2
e) 0
f) +3

# data[].attributes.body
C = 0
o2- = 2-
fe3+ = 3+
he = 0
fe2+ 2+
Al3+ 3+