# data[].attributes.body
Part 1
Vin = 100Vrms ; R1 = 5ohm ; RL = 15 ohm

I = Vin/(R1 + RL)
= 100/(5+15)
= 5A

Power at R1 = (I^2)*R1
=25*5
= 125W

Part 2
Vin=100Vrms ; R1=5ohm ; RL=15ohm ; XL=j15ohm

Z= (XL*RL)/(XL+RL)+R1
=(j15*15)/(j15+15)+5
=12.5+j7.5 ohm

I=Vin/Z
= 100/(12.5+j7.5)
= 6.89 A (with angle -30.1 degree)

Power at R1 = (I^2)*R1
=47.4721*5
= 237.36W

The power dissipated at R1 is higher for the second circuit due to the inductor in the circuit that will draw higher current.

# data[].attributes.body
1st case:

V=100V ; R1=5ohm ; RL=15ohm
Current =V/total R
= 100/(5+15)
= 5A#
Power dissipated = I^2*R1
= 5^2*(5)
=125W#

2nd case:

V=100V ; R1=5ohm ; RL=15ohm ; XL=j15ohm
Total Impedance, Z = (XL*RL)/(XL+RL)+R1
= (j15*15)/(j15+15)+5
=12.5+j7.5 ohm#
Magnitude of Power = 14.58 watts#
Current = V/total Z
= 100/14.58
= 6.86 A#
Power dissipated = I^2*R1
= 6.86^2*(5)
= 235.298 W#

Explanation:

In comparison, with a higher amount of current due to the inductor, the power dissipated is increased. Therefore, in a inductive circuit, there is more power dissipated. #

# data[].attributes.body
Case 1:
Power dissipated on R1=5^2x5=125W

Case 2:
total Z=12.5+j7.5
mag of total current=mag(V/Z)=6.86 A
Power dissipated on R1=6.86^2x5 = 235.3W

By comparison, more power dissipated on the transmission line of case 2 because the circuit is inductive .

# data[].attributes.body
Part 1
V = 100V
R = 20 ohm
I = 5A #
P = 500W #

Part 2
V = 100V
Z = 5.067 - 0.067i
= 5.067<-0.76
I = 19.73 + 0.26i
= 19.74<0.76
S= 1973.34 - 25.97i
= 1973.52<-0.76
P = 1973.34
Q = -25.97

# data[].attributes.body
Before : 125 W
After : 201.69 W

Since the latter draws a higher current due to the inductor, the total power dissipated will be increased as indicated by the formula P=I^2.R

# data[].attributes.body
This is a transmission system to deliver electrical energy to the load.
When the load increased in the system, the total current of the system will be increased. How the power dissipated on the transmission line change?
In other words, you need to calculate the active power of the resistance R1 in the two cases and compare them. Explain your comparison.