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When the parabola the y-intercept

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66j^2-2j-8

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Ik You have multiply on the bottom and add on the top of that X

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Ik the absolute value goes to left 5 and down 1

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Ik you have to match up the squared numbers with each other

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i know you have to either add or subtract the exponents

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Its the square root of 10

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Ik this is a maximum.

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the y-intercept is -5 because that's where parabola crosses the y-axis.

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Ik you have the match up the J’s and either add or subtract

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for the X the left is 3x the right is 8x the top is 11x^2.

# data[].attributes.subject
for the X the left is 3x the right is 8x the top is 11x^2.

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the absolute value is a "v" shaped graph

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7x^2+x-5

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maximum with no vertex

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66j^2-8-2j

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you find the two numbers that will multiply to 24

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The Quotient of Powers Property

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square root of ten

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i know that the y-x intercept is -5 i know that because thats where it crosses the y axis

# data[].attributes.subject
i know that the y-x intercept is -5 i know that because thats where it crosses the y axis

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Figure out which numbers that multiply into the top and bottom blank boxes. 

# data[].attributes.subject
Figure out which numbers that multiply into the top and bottom blank boxes. 

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i know that to find the vertix you have to go left 5 and down 1

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i know that to find the vertix you have to go left 5 and down 1

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i know that that you combine like terms and the answer is 7x^2+1x-5

# data[].attributes.subject
i know that that you combine like terms and the answer is 7x^2+1x-5

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anything that has a 0 exponent will always equal 1

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you need to find the square root of 10

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the vertex is maximum because the because it is above the x-axis

# data[].attributes.subject
the vertex is maximum because the because it is above the x-axis

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The y-intercept is where the line crosses the y-axis.

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This translation will be shifted to the left 5 times.

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Like terms must be combined.

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It would be the quotient of powers property.

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It would be the quotient of powers property.

# data[].attributes.body
The vertex has the option of being both maximum or minimum depending on the parabola.

# data[].attributes.body
to find the y-int you need to find the point where the parabola crosses the x axis.

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Combine all like terms.

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the graph will look like a V and will be -5 and 1

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combine all the like terms until you can't anymore

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the vertex is where the center of the parabola, it can either be maximum or minimum

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The y-intercepts point meets at -5, making -5 the y-intercept.

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The y-intercepts point meets at -5, making -5 the y-intercept.

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combine all like terms

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It should be V shaped graph from points -5 and -4.

# data[].attributes.subject
It should be V shaped graph from points -5 and -4.

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combine all the numbers with the same terms and bring down the other numbers onto the side and solve it.

# data[].attributes.subject
combine all the numbers with the same terms and bring down the other numbers onto the side and solve it.

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Has no vertex and is maximum  because its opened while going downwards.

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Has no vertex and is maximum  because its opened while going downwards.

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combine like terms with 11j and 6j and multiply the rest of the numbers.

# data[].attributes.subject
combine like terms with 11j and 6j and multiply the rest of the numbers.