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4)The tape is attracted to other areas of you desk that are not charged because  there is an opposite change.
5) Since plastic materials are not conductors they don't compose electrons in the molecule.
1) F=8.9875x10^9
(-8.0x10^-6)^2/(.05)^2=230.08N
2)F=(8.9875x10^9(12x10^-9 (-18x10^-5N
b.F=8.9875x19^9(-3x10^-9)^2/(.30)^2=8.98x10^-7N
3)175=8.9875x10^9 (-3x10^-9)^2/(.30)^2=8.98x10^-6)(0.5x10^-6)/(d^2)=175
d=0.393

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1)

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Sakshi Hegde, Diana Rendler, Catlan Tran

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Sakshi Hegde, Diana Rendler, Catlan Tran

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1. It is equal to the magnitude of the rod's charge.
2. The charge was negative for a single electron.
3. 10.0 C / (1.602 x 10^-19) = 6.242 x 10^19
4. The tape becomes negatively charged when pulled off the desk, and attracts the areas of the table because it induced an opposite surface charge.
5. Plastic materials are not conductors for they do not have a sea of electrons in their molecule composition.

1. 8.9875x10^9 x (-8.0 x 10^-6)^2 / (5 x 10^-2)^2 =  230 N
2.a.  8.9875x10^9 x (12x10^-9)x(-18x10^-9) / (0.3)^2 = -2.157 x 10^-5 N
b.  8.9875x10^9 x (15x10^-9)^2 / (0.3)^2  = 2.247 x 10^-5 N
3. 175 / 8.9875x10^9 / (60 x 10^-6)(50 x 10^-6) = 6.490
Square root of 6.490 is 2.548 m

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REVIEW
1. The wool would be charged after rubbing with the rod due to the law of conservation of charge.
2. Millikan's oil drop experiment revealed the negative charge of an electron
3. 10C / (1.602 x 10^-19) = 6.24 x 10^19 electrons
4. The tape will be attracted to other parts of the table that aren't charged because it has the charge already built up in it so it maintains the charge it accumulated.

5. Electrons are able to flow through because metals are conductors. The metal atoms are so large that the outer electron shell is very far away from the nucleus. The positive charge on the nucleus pulls the electrons into a cloud around it. If the distance between the positive and the negative particles (electrons) is very high, the strength of attraction between them would also be very weak and thus the electrons move out of the orbit and into a sea of electrons around all the atoms of a metal. This sea of electrons carries a negative charge. When electric current is applied to one end of any metal body, these electrons take the electric charge up and carry it to the other end. That is how metals conduct electricity.
PROBLEMS
1. F= (8.99x10^9) (-8.0x10^-6)(-8.0x10^-6) / (.25)= -230N
2.
a) (8.99 x 10^9)(12x10^-9)(18x10^-9)/ (0.3^2)= 2.2 x 10^-5
b) (8.99x10^9) (3x10^(-9) (3x10^(-9) / (.30)^2 = 9 x 10^-7 N
3. (8.99x10^9) (0.6x10^-6)(0.5x10^-6) / (d^2)= 175
d= 0.393 m

# data[].attributes.body
1. The magnitude of the wool's charge is the same as the rod. This is the law of conservation of charge.
2. Milikan's oil experiment revealed that the electric charge for an electron is negative.
3) 10/(1.603 x 10 to the power of -19)= 6.24 x 10 to the power of 19.
4. The tape is negatively charged and when it is pulled off the desk, the desk has the opposite charge.
5.

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Review
1) Law of conservation of charge allows the magnitude of the wools charge to be the same as the rod's charge.
2) The charge for an electron is negative.
3) Electron =q/e=(10)/(1.6 x 10^-19
4) The tape is

# data[].attributes.body
1) The magnitude of the wool's charge will be the same as the rod, due to law of conservation of charge.
2) The Milikan's oil experiment  revealed that electron have a negative charge.
3)  10.0 c/ (1.603x10^-19)=6.24x10^19 in excess
4)  The tape is negatively charged when it's pulled off the desk, and then it is attracted to other areas of the desk because  it has an opposite surface charge on the desk.
5) Charges can't move through them because most plastics are electrical insulators . It moves through Metals and coppers because  they are  electrical conductor.

practice A
1)  F= k(Q1xQ2) /R^2
F= 8.9875x10^9 (-8.0x10^-6)^2 /(.05)^2 =230.08N
2)  F= (8.9875x10^9( 12x10^-9) ( -18x10^-9) /( .30)^2= 2.158x10^-5 N
b) F= 8.9875 x10^9 ( -3x10^-9 ) ^2 / (.30)^2 = 8.98x10^-7 N
3) 175= 8.9875x10^9( 60x10^-6)(50x10^-6) /r^2= 39cm or .3925 m

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1. Can conclude that the magnitude of the wool's charge is equal to the magnitude of the  rod's charge.
2. Millikan's oil drop experiment reveals that the charge is quantified.
3. A typical lightning bolt has:
electron = Q/E = (10)/(1.6 x 10^-19) = 6.24 x 10^-19
4. This happens since the tape are negatively charged once it's pulled off the desk. It also attracts areas of the desk because it induced and opposite surface charge.
5. They can be charged by induction while some plastics can't because since plastics are an insulator, it doesn't produce electricity as easily.
1.

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Review
1. The magnitude of the wool's charge is equal to the magnitude of the rod's charge because energy is conserved.
2. Millikan's oil drop experiment revealed the negative nature of the electric charge.
3. 10 c /(1.602x10^-19) = 6.24x10^19
4. The charged tape induces opposite charges on the parts of the desk which is not charged and hence it is attracted.
5. Metals, on the periodic table, lie on the left side. They have delocalized electrons that allow them to allows charge to move freely. Plastic, on the other hand, does not have these free electrons, making it difficult for electric charge to run freely.

Coulomb's Law
1. (8.99x10^9)(-8.0x10^(-6))(-8.0x10^(-6)) / (.05)^2 = -230.15 N
2. a. (8.99x10^9)(12x10^(-9))(18x10^(-9)) / (.30)^2 = 2.16 x 10^ (-5) N
b. (8.99x10^9)(3x10^(-9))(3x10^(-9)) / (.30)^2 = 8. 99 x 10^ (-7) N
3. 175 = (8.99x10^9)(60x10^(-6))(50x10^(-6)) / (d^2)
d = 39 cm

# data[].attributes.body
1. The wool will end up having the same magnitude of the rod. This happens since the charge of the rod was transferred to the wool. This is known as the law of conservation of charge.
2. Millikan's experiment revealed that the electric charge is measured specifically and can be quantified. He happened to figure out the exact charge of the electron/ proton.
3. 10/ (1.603 x 10^-19)= 6.24 x 10^19 electrons are in excess.
4. When the tape is removed from the desk, it becomes negatively charged and the surface of the desk has an opposite charge.
5. Metals have a sea of electrons, which allows electrical charges to flow quickly through the metal, so it is able to conduct electricity easily. Also, plastic is an insulator versus metals which are conductors.
6. F= (k)q1(q2)/ r^2
F= (8.99x10^9)(-8.0x10^-6)(-8.0x10^-6)/ (.25)= -230.12 N
7. A) (8.99 x 10^9)(12x10^-9)(18x10^-9)/ (0.3^2)= 2.158 x 10^-5 N
B) IDK
8. (8.99x10^9)(0.6x10^-6)(0.5x10^-6)/ (d^2)= 175
d= 39 cm or 0.393 m